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G3 · Isolate and evaluate a variable in a formula

Learn to isolate and evaluate a variable in a formula through clear examples and targeted practice.

Ontario Grade 10 Mathematics

Modelling Linear Relations

Use inverse operations to rearrange a formula, then substitute known values

A formula is a rule that connects quantities. For example, the formula for the perimeter of a rectangle uses its length and width. Sometimes you know the measurements and need to calculate a result. At other times, you need to rearrange the formula first so that a different variable is alone. You already know the key idea from solving equations: do the same operation to both sides. This lesson uses that idea with formulas.

What you will learn

1. Bridge: equations and balanced sides

An equation says that two expressions have the same value. The equals sign means “is equal to.” To keep an equation true, you must do the same operation to both sides.
An inverse operation undoes another operation. Addition and subtraction are inverses. Multiplication and division are inverses. For example, subtracting a number undoes adding that number.
A variable is a letter that stands for a number or measurement. To isolate a variable means to get it alone on one side of an equation. In a formula, the variable you want to find may not be alone at first.
a+b=c⇒a=c−ba+b=c \Rightarrow a=c-b

2. Rearrange a formula

A formula is an equation that describes a relationship between quantities. The perimeter formula for a rectangle is P=2l+2wP=2l+2w. Here, PP means perimeter, ll means length, and ww means width.
Suppose you know the perimeter and width but need the length. Start with the original formula and undo the operations attached to the length. First subtract 2w2w from both sides. Then divide both sides by 22. These steps leave ll alone.
The order matters. Undo addition or subtraction before undoing multiplication or division when those operations are applied to the variable. Use the same operation on both sides at each step.
A rearranged formula is still the same relationship, written to make a different variable the subject. The subject is the variable that is alone on one side.
P=2l+2w⇒l=P−2w2P=2l+2w \Rightarrow l=\frac{P-2w}{2}

3. Evaluate a variable

To evaluate a variable means to calculate its value using known values in a formula. Substitution means replacing a variable with a given number.
Use parentheses around substituted negative numbers or values that contain more than one part. Follow the usual order of operations: calculate inside parentheses first, then multiply or divide, then add or subtract.
Include units when the quantities have units. Check that the final value is reasonable and, when possible, place it back into the original formula to confirm it works.
l=P−2w2l=\frac{P-2w}{2}

4. A reliable routine

For a question that asks you to find a variable, first identify which variable is unknown. If it is not alone, rearrange the formula to isolate it. Then substitute the values you know and calculate.
For a question that asks you to rearrange a formula but gives no numbers, stop once the requested variable is isolated. Do not invent values.
A useful final check is to substitute your calculated value into the original formula. Both sides should have the same value. If they do not, review your rearranging steps and arithmetic.
A clear sequence is to write the original formula, isolate the target variable, substitute known values, and check the result.

Undoing operations to isolate the length

StageEquationWhat changes
OriginalP=2l+2wP=2l+2wLength is multiplied by 2, then 2w2w is added.
Subtract 2w2wP−2w=2lP-2w=2lUndo the addition on both sides.
Divide by 2P−2w2=l\frac{P-2w}{2}=lUndo the multiplication on both sides.
Write with the target firstl=P−2w2l=\frac{P-2w}{2}The length is isolated.

Worked example

Find the length of a rectangle

A rectangle has a perimeter of 34 cm and a width of 6 cm. Use the perimeter formula to find its length.
  1. Choose the variable
    The unknown is the length, so we want ll alone. The given values are P=34P=34 and w=6w=6.
  2. Isolate the length
    Start from the perimeter formula. Subtract 2w2w from both sides to undo the addition of 2w2w. Then divide both sides by 22 to leave ll alone.
    P=2l+2wP=2l+2w
  3. Substitute the known values
    Replace PP with 3434 and ww with 66 in the isolated formula. This uses the same relationship, now arranged to calculate length.
    l=34−2(6)2l=\frac{34-2(6)}{2}
  4. Calculate and check
    Multiply first, then subtract and divide. The result is 1111 cm. Check it in the original formula: twice the length plus twice the width gives the stated perimeter.
    l=11,2(11)+2(6)=34l=11,\qquad 2(11)+2(6)=34
Answer: The length is 11 cm.
Check: Substituting l=11l=11 cm and w=6w=6 cm into the original formula gives 2(11)+2(6)=342(11)+2(6)=34 cm, which matches the given perimeter.

Common mistakes and how to avoid them

Changing only one side when rearranging a formula.
Correction: Apply the same operation to both sides so the equation stays balanced.
Dividing by 2 before removing the added 2w2w in P=2l+2wP=2l+2w.
Correction: Subtract 2w2w from both sides first, then divide by 2.
Substituting values into the original formula without isolating the requested variable.
Correction: If the requested variable is not alone, rearrange the formula first.
Stopping after finding a number without checking it.
Correction: Substitute the result into the original formula and confirm the relationship works.

Lesson summary

Check your understanding

Question 1

Rearrange A=lwA=lw to make ww the subject.
  1. w=A−lw=A-l
  2. w=Alw=\frac{A}{l}
  3. w=Alw=Al
  4. w=lAw=\frac{l}{A}
Show answer and explanation
w=Alw=\frac{A}{l}
Divide both sides by ll to undo multiplication by ll. This gives w=A/lw=A/l.

Question 2

Use d=vtd=vt to find tt when d=48d=48 km and v=8v=8 km/h.
  1. 6 h
  2. 40 h
  3. 56 h
  4. 384 h
Show answer and explanation
6 h
Divide distance by speed: t=d/v=48/8=6t=d/v=48/8=6 h.

Question 3

Which operation should be used first to isolate xx in y=3x+7y=3x+7?
  1. Add 7 to both sides
  2. Subtract 7 from both sides
  3. Multiply both sides by 3
  4. Divide both sides by 7
Show answer and explanation
Subtract 7 from both sides
Subtract 7 from both sides to undo the addition. Then divide by 3 to isolate xx.

Key terms

Formula
An equation that describes a relationship between quantities.
Variable
A letter that stands for a number or measurement.
Isolate
Get a chosen variable alone on one side of an equation.
Inverse operation
An operation that undoes another operation, such as subtraction undoing addition.
Substitution
Replacing a variable with a known value.
Evaluate
Calculate the value of a variable or expression using known values.

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About this lesson

Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 10 Mathematics (MFM2P), study topic G3. It is a study resource, not an official curriculum publication.

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