DoAssignment.ca

M10 · Develop the surface-area relationship for a pyramid

Learn to develop the surface-area relationship for a pyramid through clear examples and targeted practice.

Ontario Grade 10 Mathematics

Measurement and Trigonometry

Build the relationship by adding the base and triangular faces

A pyramid has one base and triangular side faces that meet at a point called the apex. Its surface area is the total area of all its outside faces. In this lesson, you will build a relationship for a regular pyramid. Its base is a regular polygon, and its side triangles have the same slant height. The relationship shows how the base perimeter and slant height combine to give the area of the triangular faces.

What you will learn

1. Start with familiar area ideas

You already know how to find the area of a rectangle: multiply its length by its width. For a triangle, multiply its base by its perpendicular height, then divide by two. Perpendicular lines meet at a right angle.
A pyramid’s outside is made of its base and triangular side faces. To find its surface area, find the area of each face and add the areas together.
The height of a triangular face is measured at a right angle to that triangle’s base. In a regular pyramid, this face height is called the slant height. It runs along a side face from the apex to the midpoint of a base edge. It is not the vertical height inside the pyramid.
A△=12bhA_{\triangle}=\frac{1}{2}bh

2. Combine the triangular faces

Imagine unfolding the pyramid so that its faces lie flat. This flat layout is called a net. It shows one base and all the triangular side faces.
Each triangle’s base matches an edge of the pyramid’s base. Its area is half its base-edge length multiplied by the slant height. In a regular pyramid, all the side triangles have the same slant height.
Add the areas of the side triangles. Their base-edge lengths add up to the perimeter of the base. Perimeter means the total distance around a shape. So the combined area of the triangles is half the base perimeter multiplied by the slant height. This combined area is called the lateral area.
The total surface area includes the base as well as the side triangles. Add the base area to the lateral area. In the relationship, BB means the base area, PP means the base perimeter, and ℓ\ell means the slant height.
SA=B+12PℓSA=B+\frac{1}{2}P\ell

3. Match each measurement to the correct part

The relationship applies to a regular pyramid: one with a regular polygon base and equal slant heights on its side triangles. A regular polygon has equal sides and equal angles.
Check what each measurement describes before using it. Find the base area from the shape at the bottom. Find the perimeter by adding the base’s edge lengths. Use the slant height of a triangular side face in the lateral-area part.
If a problem gives the pyramid’s vertical height, do not substitute it for slant height. They measure different distances. The vertical height is inside the pyramid; slant height lies on a triangular face.
Use consistent units for all lengths. Give area in square units, such as square centimetres. For a square base with side length ss, its perimeter is four times ss, and its area is ss multiplied by itself.
P=4s,B=s2P=4s,\quad B=s^2

4. Guided example and independent practice

In the example, find the base area and perimeter first. Then find the area of the triangular faces. Add the base area last. This keeps the two parts of the total separate.
For independent practice, consider a regular square pyramid with a base side length of 77 cm and a slant height of 99 cm. Find the base area, perimeter, lateral area, and total surface area. Check that the lateral area includes only the triangles and that your final answer uses square centimetres.

Parts of a regular pyramid’s surface area

PartHow to find its areaHow it contributes
BaseFind the area of the base shape.Add the base area once.
Triangular side facesMultiply half the base perimeter by the slant height.This is the lateral area.
Whole outsideAdd the base area and lateral area.This is the surface area.

Worked example

A regular square pyramid

A regular square pyramid has a base side length of 66 cm and a slant height of 88 cm. Find its surface area.
  1. Find the base area
    The base is a square. Multiply its side length by itself to find the area.
    B=6×6=36 cm2B=6\times6=36\text{ cm}^2
  2. Find the base perimeter
    A square has four equal sides. Multiply the side length by four to find the total distance around the base.
    P=4×6=24 cmP=4\times6=24\text{ cm}
  3. Find the lateral area
    Multiply half the perimeter by the slant height. This gives the combined area of the four triangular faces.
    12Pℓ=12×24×8=96 cm2\frac{1}{2}P\ell=\frac{1}{2}\times24\times8=96\text{ cm}^2
  4. Add the base area
    Surface area includes the base and the triangular faces. Add their areas to find the total.
    SA=36+96=132 cm2SA=36+96=132\text{ cm}^2
Answer: The surface area is 132 cm2132\text{ cm}^2.
Check: The base area is 36 cm236\text{ cm}^2 and the lateral area is 96 cm296\text{ cm}^2. Their sum is 132 cm2132\text{ cm}^2, which includes the square base and all four triangular faces.

Common mistakes and how to avoid them

Using the pyramid’s vertical height in the lateral-area relationship.
Correction: Use the slant height measured on a triangular face, at a right angle to that face’s base edge.
Calling the lateral area the total surface area.
Correction: Lateral area includes only the side faces. Add the base area to get the total surface area.
Using the base area instead of the base perimeter in the lateral-area calculation.
Correction: The relationship uses the total length around the base, not the area inside it.
Giving an area in ordinary length units, such as centimetres.
Correction: Area uses square units, such as cm2\text{cm}^2.

Lesson summary

Check your understanding

Question 1

A regular square pyramid has a base side length of 55 cm and a slant height of 66 cm. What is its surface area?
  1. 85 cm285\text{ cm}^2
  2. 60 cm260\text{ cm}^2
  3. 95 cm295\text{ cm}^2
  4. 30 cm230\text{ cm}^2
Show answer and explanation
85 cm285\text{ cm}^2
The square base area is 25 cm225\text{ cm}^2, and the perimeter is 2020 cm. The lateral area is half of 2020 multiplied by 66, or 60 cm260\text{ cm}^2. Add the base area: 25+60=85 cm225+60=85\text{ cm}^2.

Question 2

Which measurement is used with the base perimeter to find the lateral area of a regular pyramid?
  1. The area of the base
  2. The slant height of a side triangle
  3. The length of one base edge only
  4. The vertical height of the pyramid
Show answer and explanation
The slant height of a side triangle
The triangular face areas use the height measured on the side faces. For a regular pyramid, this shared face height is the slant height.

Key terms

Apex
The point where the triangular side faces of a pyramid meet.
Base
The polygon at the bottom of a pyramid.
Base perimeter
The total length around the base.
Lateral area
The combined area of a pyramid’s triangular side faces.
Net
A flat layout that shows the faces of a three-dimensional shape.
Regular pyramid
A pyramid with a regular polygon base and equal slant heights on its triangular side faces.
Slant height
The perpendicular height of a triangular side face, measured from the apex to a base edge.
Surface area
The total area of all the outside faces of a solid.

Continue through MFM2P

View the complete MFM2P Ontario Grade 10 Mathematics curriculum and lessons

About this lesson

Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 10 Mathematics (MFM2P), study topic M10. It is a study resource, not an official curriculum publication.

Official curriculum reference

Report a correction or ask a question