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Q3 · Factor quadratics using a common factor

Learn to factor quadratics using a common factor through clear examples and targeted practice.

Ontario Grade 10 Mathematics

Quadratic Relations

Find what every term shares, then write the expression as a product

A quadratic expression has a highest variable exponent of 22. For example, 6x2+9x6x^2+9x is quadratic. Factoring means rewriting an expression as a product. In this lesson, you will factor a quadratic by finding a factor shared by every term. This reverses the distributive property. Look at the terms, find what they share, and check your result by expanding.

What you will learn

1. Review: terms, factors, and the distributive property

An expression is a mathematical phrase without an equals sign. In 6x2+9x6x^2+9x, the terms are 6x26x^2 and 9x9x. A plus or minus sign separates terms. Keep the sign with the term that follows it when working with subtraction.
A factor is a number or variable multiplied by another number or variable. In 6x26x^2, the factors include 66, xx, and xx, because x2x^2 means x×xx\times x. The coefficient is the number multiplying the variable; the coefficient of 6x26x^2 is 66.
The distributive property lets you multiply a factor by each term inside brackets. For example, 3(x+4)=3x+123(x+4)=3x+12. Factoring out a common factor reverses this action. The common factor must be a factor of every term.
a(b+c)=ab+aca(b+c)=ab+ac

2. Find the greatest common factor

The greatest common factor, or GCF, is the largest positive factor shared by all the terms. To find it, first look for a number that divides every coefficient. Then look for any variable that appears in every term. When a variable appears in each term, use the smallest exponent it has in those terms.
For example, the terms 12x212x^2 and 18x18x share the number factor 66. They also both contain at least one xx. Their GCF is therefore 6x6x. The second term has only one xx, so the common variable factor is xx, not x2x^2.
If the terms have no variable in common, the GCF may be a number only. For this lesson, focus on expressions where the terms share a factor.
GCF⁡(12x2,18x)=6x\operatorname{GCF}(12x^2,18x)=6x

3. Factor out the common factor

Divide each term by the GCF to find what belongs inside the brackets. Put the GCF outside the brackets. The terms inside are the quotients: each original term divided by the common factor.
For 12x2+18x12x^2+18x, dividing each term by 6x6x gives 2x2x and 33. So the expression becomes 6x(2x+3)6x(2x+3). This works because multiplying 6x6x by each term in the brackets returns the original terms.
With subtraction, keep track of the negative sign. For −8x2−12x-8x^2-12x, the positive GCF is 4x4x. You may choose to factor out −4x-4x instead; this leaves 2x+32x+3 inside the brackets. Choosing the negative factor makes the first term inside positive.
ab+ac=a(b+c)ab+ac=a(b+c)

4. Check a factorization by expanding

After factoring, use the distributive property to check your work. Multiply the outside factor by each term inside the brackets. The result should match the original expression, including its signs and exponents.
For instance, expanding 5x(2x−7)5x(2x-7) gives 10x2−35x10x^2-35x. That matches the original expression, so the factorization is correct. If the result has a different coefficient or sign, revisit the division of the terms by the common factor.
This check is especially useful when the terms contain negative signs. It also confirms that no term was left out.
a(b−c)=ab−aca(b-c)=ab-ac

Organize the quotients when factoring

Original termDivide by the common factor 5x5xQuotient
15x215x^215x2÷5x15x^2\div 5x3x3x
25x25x25x÷5x25x\div 5x55

Worked example

Example 1: Factor a quadratic with a variable GCF

Factor 15x2+25x15x^2+25x using a common factor.
  1. Find the shared factor
    The coefficients 1515 and 2525 share the factor 55. Both terms also contain xx. The GCF is 5x5x.
    GCF⁡(15x2,25x)=5x\operatorname{GCF}(15x^2,25x)=5x
  2. Divide each term
    Divide 15x215x^2 by 5x5x to get 3x3x. Divide 25x25x by 5x5x to get 55. These quotients go inside the brackets.
    15x2÷5x=3x,25x÷5x=515x^2\div 5x=3x,\qquad 25x\div 5x=5
  3. Write the product
    Put the GCF outside the brackets and the quotients inside. This gives a product equal to the original quadratic expression.
    15x2+25x=5x(3x+5)15x^2+25x=5x(3x+5)
Answer: 5x(3x+5)5x(3x+5)
Check: Expand to check: 5x(3x+5)=15x2+25x5x(3x+5)=15x^2+25x, which matches the original expression.

Worked example

Example 2: Factor when both terms are negative

Factor −14x2−21x-14x^2-21x using a common factor.
  1. Find the GCF and choose a factor
    The positive GCF is 7x7x: the coefficients share 77, and both terms contain xx. Since both terms are negative, choose the negative factor −7x-7x for the factorization so the first term inside the brackets is positive.
    GCF⁡(−14x2,−21x)=7x\operatorname{GCF}(-14x^2,-21x)=7x
  2. Divide each term
    Divide −14x2-14x^2 by −7x-7x to get 2x2x. Divide −21x-21x by −7x-7x to get 33. Both quotients are positive.
    (−14x2)÷(−7x)=2x,(−21x)÷(−7x)=3(-14x^2)\div(-7x)=2x,\qquad (-21x)\div(-7x)=3
  3. Write the product
    Place the chosen factor −7x-7x outside the brackets and the quotients inside. Multiplying back restores both negative terms.
    −14x2−21x=−7x(2x+3)-14x^2-21x=-7x(2x+3)
Answer: −7x(2x+3)-7x(2x+3)
Check: Expand to check: −7x(2x+3)=−14x2−21x-7x(2x+3)=-14x^2-21x, which matches the original expression.

Common mistakes and how to avoid them

Calling a negative factor the GCF.
Correction: State the GCF as positive. You may choose its negative as the factor you take out when forming the product.
Taking out a factor that does not divide every term.
Correction: Test the proposed factor against each term. A common factor must divide every term exactly.
Using x2x^2 as the common variable factor in 12x2+18x12x^2+18x.
Correction: The second term contains only one xx. Use the smallest shared exponent, so the variable part of the GCF is xx.
Forgetting a negative sign when dividing terms.
Correction: Divide each signed term by the chosen signed factor, then expand your answer to check the signs.
Leaving a term out of the brackets.
Correction: Divide every term in the original expression by the chosen factor. Each quotient must appear inside the brackets.

Lesson summary

Check your understanding

Question 1

What is the GCF of 18x218x^2 and 30x30x?
  1. 6x6x
  2. 6x26x^2
  3. 3x3x
  4. 66
Show answer and explanation
6x6x
The coefficients share a factor of 66, and both terms contain one xx. The smallest shared variable factor is xx, so the GCF is 6x6x.

Question 2

Which expression is the factorization of 8x2+20x8x^2+20x using a common factor?
  1. 4x(2x+5)4x(2x+5)
  2. 4x(2x+20)4x(2x+20)
  3. 2x(4x+20)2x(4x+20)
  4. 4(2x2+5x)4(2x^2+5x)
Show answer and explanation
4x(2x+5)4x(2x+5)
The GCF is 4x4x. Dividing the terms by 4x4x gives 2x2x and 55, so the factorization is 4x(2x+5)4x(2x+5). Expanding it returns 8x2+20x8x^2+20x.

Question 3

Factor −9x2−12x-9x^2-12x by taking out a negative common factor.
  1. −3x(3x+4)-3x(3x+4)
  2. −3x(3x−4)-3x(3x-4)
  3. −3(3x2+4x)-3(3x^2+4x)
  4. −9x(x+12)-9x(x+12)
Show answer and explanation
−3x(3x+4)-3x(3x+4)
Taking out −3x-3x leaves 3x3x and 44. Expanding −3x(3x+4)-3x(3x+4) gives −9x2−12x-9x^2-12x.

Key terms

Term
A part of an expression separated from other parts by a plus or minus sign.
Factor
A number or variable multiplied by another number or variable.
Coefficient
The number multiplying the variable in a term.
Greatest common factor (GCF)
The largest positive factor shared by every term in an expression.
Factoring
Rewriting an expression as a product of factors.

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About this lesson

Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 10 Mathematics (MFM2P), study topic Q3. It is a study resource, not an official curriculum publication.

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