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A1.5 · Expand and simplify quadratic expressions

Learn to expand and simplify quadratic expressions through clear examples and targeted practice.

Ontario Grade 11 Mathematics

Mathematical Models

MBF3C, specific expectation A1.5

A quadratic expression is an expression in which the highest power of the variable is two. For example, x2+5x+6x^2+5x+6 is quadratic. Expanding means removing brackets by multiplying each term correctly. Simplifying means combining like terms so the expression is written more compactly. In this lesson, you will use multiplication and the distributive property to expand and simplify quadratic expressions. You will not solve equations; the goal is to rewrite expressions in an equivalent form.

What you will learn

1. Review the building blocks

A term is a part of an expression separated from other parts by a plus or minus sign. In 4x+74x+7, the terms are 4x4x and 77. The number multiplying a variable is its coefficient. So, the coefficient of xx is 44 in 4x4x. A constant is a number with no variable, such as 77.
The exponent tells how many times a variable is used as a factor. Thus, x2x^2 means xx multiplied by xx. It does not mean 2x2x. In a quadratic expression, the x2x^2 term is often called the squared term. For instance, in 3x2−2x+83x^2-2x+8, the squared term is 3x23x^2, the linear term is −2x-2x, and the constant is 88.
Like terms have the same variable raised to the same power. You can combine 3x3x and 5x5x to get 8x8x, but you cannot combine x2x^2 with xx. Their variable parts are different. This rule will matter after brackets are expanded.
x2=x⋅xx^2=x\cdot x

2. Expand by multiplying every term

The distributive property says that a factor outside brackets multiplies every term inside. For example, 3(x+4)3(x+4) becomes 3x+123x+12. The factor 33 must reach both xx and 44.
A product of two brackets needs the same care. In (x+3)(x+2)(x+3)(x+2), each term in the first bracket multiplies each term in the second bracket. The four products are x⋅xx\cdot x, x⋅2x\cdot2, 3⋅x3\cdot x, and 3⋅23\cdot2. This is sometimes remembered as first, outer, inner, last, but the important idea is to include every pair once.
The product x⋅xx\cdot x gives x2x^2. The two middle products are both terms in xx, so they can be combined. The final product is a constant. That pattern explains why multiplying two linear brackets can produce a quadratic expression.
A box or area model can help organize the products. Put the terms from one bracket along the top and the terms from the other bracket down the side. Multiply across each cell. This makes it easier to see whether any product has been missed.
(a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd

3. Simplify and check the result

After expansion, collect like terms. Put squared terms together, then linear terms, then constants. For example, 2x2+3x+4x+12x^2+3x+4x+1 simplifies to 2x2+7x+12x^2+7x+1 because 3x3x and 4x4x are like terms.
Signs are part of terms. In (x−4)(x+2)(x-4)(x+2), the first bracket contains xx and −4-4. The product of −4-4 and 22 is negative, and the product of −4-4 and xx is also negative. Keeping each sign attached to its term helps avoid errors.
You can check an expansion by using the same value of the variable in both forms. If the original and expanded expressions give different results for that value, an error has occurred. Matching values are a useful check, although it is still important to show the expansion steps.
A quadratic expression may describe a measurement, such as the area of a rectangle whose side lengths are expressions. If one side is x+3x+3 and the other is x+2x+2, multiplying the side lengths gives an expression for the area. Expanding writes that area as a sum of a squared term, linear terms, and a constant. The expression is equivalent; its value does not change just because its form changes.
2x2+3x+4x+1=2x2+7x+12x^2+3x+4x+1=2x^2+7x+1

Area model for $(x+3)(x+2)$

Multiply byxx22
xxx2x^22x2x
333x3x66

Worked example

Example 1: Expand a product of two binomials

Expand and simplify (x+4)(x+2)(x+4)(x+2).
  1. List every product
    Multiply each term in the first bracket by each term in the second. This ensures that all four pairings are included.
    x⋅x+x⋅2+4⋅x+4⋅2x\cdot x+x\cdot2+4\cdot x+4\cdot2
  2. Multiply the terms
    The variable multiplied by itself gives a squared term. The two middle products are terms in xx, and the last product is a constant.
    x2+2x+4x+8x^2+2x+4x+8
  3. Combine like terms
    The terms 2x2x and 4x4x have the same variable part, so add their coefficients. Keep x2x^2 and 88 separate.
    x2+6x+8x^2+6x+8
Answer: The expanded and simplified expression is x2+6x+8x^2+6x+8.
Check: Substitute x=1x=1. The original gives (1+4)(1+2)=15(1+4)(1+2)=15. The expanded form gives 1+6+8=151+6+8=15, so the forms agree for this value.

Worked example

Example 2: Expand when a bracket contains a negative term

Expand and simplify 2(x−3)(x+5)2(x-3)(x+5).
  1. Expand the bracket product
    First multiply the two bracketed expressions. Pair every term with every term, keeping the negative sign on −3-3.
    (x−3)(x+5)=x2+5x−3x−15(x-3)(x+5)=x^2+5x-3x-15
  2. Combine the linear terms
    The terms 5x5x and −3x-3x are like terms. Adding their coefficients gives 2x2x.
    x2+2x−15x^2+2x-15
  3. Multiply by the outside factor
    The factor 22 is outside the product, so it multiplies every term in the simplified expression.
    2x2+4x−302x^2+4x-30
Answer: The expanded and simplified expression is 2x2+4x−302x^2+4x-30.
Check: Substitute x=2x=2. The original gives 2(2−3)(2+5)=−142(2-3)(2+5)=-14. The expanded form gives 2(4)+4(2)−30=−142(4)+4(2)-30=-14, so the forms agree for this value.

Common mistakes and how to avoid them

Multiplying only the first terms in the brackets and writing x2x^2 as the whole answer.
Correction: Include all four pairings when multiplying two brackets. Then simplify the complete list of products.
Combining x2x^2 and xx because both contain the variable xx.
Correction: They are not like terms: one has xx squared and the other has xx to the first power. Keep them as separate terms.
Losing a negative sign when multiplying a negative term.
Correction: Treat the negative sign as part of the term. For example, −3-3 multiplied by xx gives −3x-3x.
Combining terms before all products have been accounted for.
Correction: First list and calculate every product. Then group and combine like terms.

Lesson summary

Check your understanding

Question 1

Expand and simplify (x+1)(x+6)(x+1)(x+6).
  1. x2+7x+6x^2+7x+6
  2. x2+6x+1x^2+6x+1
  3. 2x+72x+7
  4. x2+5x+6x^2+5x+6
Show answer and explanation
x2+7x+6x^2+7x+6
The four products are x2x^2, 6x6x, xx, and 66. Combining the linear terms gives x2+7x+6x^2+7x+6.

Question 2

Expand and simplify (x−2)(x+3)(x-2)(x+3).
  1. x2+x−6x^2+x-6
  2. x2+5x−6x^2+5x-6
  3. x2−x+6x^2-x+6
  4. x2+3x−2x^2+3x-2
Show answer and explanation
x2+x−6x^2+x-6
The products are x2x^2, 3x3x, −2x-2x, and −6-6. Combining 3x3x and −2x-2x gives xx.

Question 3

Expand and simplify 3(x+2)(x+1)3(x+2)(x+1).
  1. 3x2+9x+63x^2+9x+6
  2. 3x2+3x+63x^2+3x+6
  3. 3x2+9x+23x^2+9x+2
  4. x2+9x+6x^2+9x+6
Show answer and explanation
3x2+9x+63x^2+9x+6
The bracket product is x2+3x+2x^2+3x+2. Multiplying every term by 33 gives 3x2+9x+63x^2+9x+6.

Key terms

Quadratic expression
An expression whose highest variable power is two.
Expand
Remove brackets by multiplying the terms they contain.
Simplify
Rewrite an expression in a more compact form by combining like terms.
Like terms
Terms with the same variable part, including the same exponent.
Distributive property
A multiplication rule that requires a factor to multiply each term in brackets.

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About this lesson

Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 11 Mathematics (MBF3C), expectation A1.5. It is a study resource, not an official curriculum publication.

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