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C1.1 · Connect sequences with discrete functions

Learn to connect sequences with discrete functions through clear examples and targeted practice.

Ontario Grade 11 Mathematics

Discrete Functions

Connecting Patterns to Function Notation (MCR3U – C1.1)

You have worked with functions before — rules that pair every input with exactly one output. In this lesson you will see that a sequence (an ordered list of numbers that follows a pattern) is actually a special kind of function. The key difference from the functions you saw in Grade 10 is that the inputs are restricted to counting numbers: 1, 2, 3, 4, and so on. That restriction turns out to be very useful for modelling real situations where things happen in distinct steps, like monthly savings deposits or the number of seats in expanding rows of a theatre. By the end of this lesson you will be able to move fluently between a sequence written as a list and the same sequence written in function notation.

What you will learn

Prerequisite Bridge: What Is a Function?

Recall from Grade 10 that a function is a rule that assigns exactly one output value to each input value. You can think of it as a machine: drop in an input, get out one specific output. We write this as f(x)f(x), read 'f of x', where xx is the input.
A function also has a domain (the set of all allowed inputs) and a range (the set of all resulting outputs). For example, the linear function f(x)=3x+1f(x) = 3x + 1 has domain 'all real numbers' and produces any real number as output.
The functions in this lesson use a much smaller, very specific domain: the natural numbers {1,2,3,4,… }\{1, 2, 3, 4, \dots\}. This restriction is what makes a sequence a discrete function — 'discrete' means the inputs are separated, with gaps between them, rather than forming a continuous line.

What Is a Sequence?

A sequence is an ordered list of numbers, called terms, arranged according to a pattern or rule. We label each term by its position: the first term is t1t_1, the second is t2t_2, the third is t3t_3, and so on. The subscript (the small number below the tt) is the term number, or index.
Consider the sequence 2,5,8,11,14,…2, 5, 8, 11, 14, \dots Each term is 3 more than the one before it. This constant addition of 3 is the pattern. If someone asks for the 6th term, you can find it because the rule is consistent.
Because each term number (1, 2, 3, …) maps to exactly one term value, a sequence satisfies the definition of a function. The term number is the input; the term value is the output. This is why we call a sequence a discrete function.
tn=f(n),n∈{1,2,3,… }t_n = f(n), n ∈ \{1, 2, 3, \dots\}

Function Notation for Sequences

Because a sequence is a discrete function, we can write it using function notation. Instead of writing a list, we write a formula where nn is the input (term number) and f(n)f(n) is the output (term value). The domain is stated explicitly as the positive integers.
Take the sequence 2,5,8,11,…2, 5, 8, 11, \dots again. Each term equals 3n−13n - 1 when nn is its position. Check: f(1)=3(1)−1=2f(1) = 3(1) - 1 = 2 ✓, f(2)=3(2)−1=5f(2) = 3(2) - 1 = 5 ✓, f(3)=3(3)−1=8f(3) = 3(3) - 1 = 8 ✓. The formula works for every term.
This sequence is called arithmetic because consecutive terms differ by the same constant, called the common difference dd. A general arithmetic sequence can always be written as f(n)=a+(n−1)df(n) = a + (n-1)d, where aa is the first term and dd is the common difference. Expanding this gives a linear function of nn, which explains why arithmetic sequences, when graphed, produce points that lie on a straight line.
A geometric sequence, by contrast, multiplies by the same constant ratio rr each time. Its function rule is f(n)=a⋅rn−1f(n) = a \cdot r^{n-1}, where aa is the first term. Because the variable nn is in the exponent, this is an exponential function of nn, not a linear one.
f(n) = a + (n-1)d or f(n) = a · r^{n-1}

The Graph of a Sequence: Discrete vs. Continuous

When you graphed f(x)=3x−1f(x) = 3x - 1 in Grade 10, you drew a solid line because every real-number value of xx was allowed. A sequence version of the same rule, f(n)=3n−1f(n) = 3n - 1 with n ∈ \{1, 2, 3, \dots\}, looks completely different on a graph: you get isolated dots at (1,2)(1, 2), (2,5)(2, 5), (3,8)(3, 8), and so on, with nothing drawn between them.
This distinction is critical. You must never connect the dots of a sequence graph with a line or curve, because non-integer inputs (like n=1.5n = 1.5) have no meaning in the sequence — there is no 'term 1.5'. The dots are deliberately isolated to show that the function is discrete.
The same idea applies to geometric sequences. The sequence f(n)=3⋅2n−1f(n) = 3 \cdot 2^{n-1} gives the points (1,3)(1, 3), (2,6)(2, 6), (3,12)(3, 12), (4,24)(4, 24). These points curve upward, just like an exponential graph, but they are plotted as separate dots, not as a smooth curve.

Recognising and Using the Connection

To confirm that a sequence is a discrete function, check two things: (1) every term number in the domain produces exactly one term value, and (2) the domain is a set of positive integers. If both are true, you can write the sequence as f(n)f(n) with n ∈ N\mathbb{N}.
Recognising the type of sequence helps you choose the right formula. If consecutive differences are constant, use the arithmetic formula. If consecutive ratios are constant, use the geometric formula. To find the ratio between consecutive terms, divide any term by the one before it: r=tntn−1r = \frac{t_{n}}{t_{n-1}}.
Once you have the formula, function notation lets you answer questions precisely. 'What is the 20th term?' becomes 'Evaluate f(20)f(20).' 'Which term equals 98?' becomes 'Solve f(n)=98f(n) = 98 for nn, where nn must be a positive integer.' This connection between sequences and discrete functions gives you a powerful, organised way to work with patterns.
r=tntn−1r = \frac{t_n}{t_{n-1}}

Arithmetic vs. Geometric Sequences as Discrete Functions

FeatureArithmetic SequenceGeometric Sequence
Pattern ruleAdd a constant dd each timeMultiply by a constant rr each time
Function formulaf(n)=a+(n−1)df(n) = a + (n-1)df(n)=a⋅rn−1f(n) = a \cdot r^{n-1}
Type of functionLinear in nnExponential in nn
Graph appearanceDots on a straight lineDots on a curve
DomainPositive integers {1,2,3,… }\{1, 2, 3, \dots\}Positive integers {1,2,3,… }\{1, 2, 3, \dots\}

Worked example

Writing an Arithmetic Sequence as a Discrete Function

A sequence begins: 7,11,15,19,…7, 11, 15, 19, \dots (a) Identify the type of sequence and find the common difference. (b) Write the sequence as a discrete function f(n)f(n). (c) Find f(12)f(12) and explain what it represents. (d) Determine which term of the sequence has the value 6363.
  1. Identify the type and common difference
    Subtract each term from the next: 11−7=411 - 7 = 4, 15−11=415 - 11 = 4, 19−15=419 - 15 = 4. The difference is constant at 44, so this is an arithmetic sequence with first term a=7a = 7 and common difference d=4d = 4.
    d=4,a=7d = 4, a = 7
  2. Write the general function rule
    Use the arithmetic sequence formula f(n)=a+(n−1)df(n) = a + (n-1)d. Substitute a=7a = 7 and d=4d = 4, then simplify by expanding and collecting like terms.
    f(n)=7+(n−1)(4)f(n) = 7 + (n-1)(4)
  3. Simplify the formula
    Expand the bracket: (n−1)(4)=4n−4(n-1)(4) = 4n - 4. Then add 77: 7+4n−4=4n+37 + 4n - 4 = 4n + 3. The simplified rule is f(n)=4n+3f(n) = 4n + 3, valid for n ∈ \{1, 2, 3, \dots\}.
    f(n)=4n+3,n∈{1,2,3,… }f(n) = 4n + 3, n ∈ \{1, 2, 3, \dots\}
  4. Evaluate f(12)
    Substitute n=12n = 12 into the formula. Multiply first, then add, following order of operations.
    f(12)=4(12)+3=48+3=51f(12) = 4(12) + 3 = 48 + 3 = 51
  5. Interpret f(12)
    Because f(12)=51f(12) = 51, the 12th term of the sequence is 5151. In other words, when the term number (input) is 1212, the term value (output) is 5151.
  6. Find which term equals 63
    Set f(n)=63f(n) = 63 and solve for nn. Subtract 33 from both sides, then divide by 44. Check that the result is a positive integer so it is a valid term number.
    4n+3=63  ⟹  4n=60  ⟹  n=154n + 3 = 63 \implies 4n = 60 \implies n = 15
Answer: The sequence is arithmetic. The function is f(n)=4n+3f(n) = 4n + 3, n ∈ \{1, 2, 3, \dots\}. The 12th term is f(12)=51f(12) = 51. The value 6363 occurs at the 15th term.
Check: Verify f(15)=4(15)+3=60+3=63f(15) = 4(15) + 3 = 60 + 3 = 63 ✓. Verify f(1)=4(1)+3=7f(1) = 4(1) + 3 = 7 ✓, matching the first term given.

Worked example

Writing a Geometric Sequence as a Discrete Function

A sequence begins: 5,15,45,135,…5, 15, 45, 135, \dots (a) Identify the type of sequence and find the common ratio. (b) Write the sequence as a discrete function f(n)f(n). (c) Evaluate f(6)f(6). (d) Is the value 12151215 a term of this sequence? If yes, which term?
  1. Find the common ratio
    Divide each term by the one before it: 155=3\frac{15}{5} = 3, 4515=3\frac{45}{15} = 3, 13545=3\frac{135}{45} = 3. The ratio is constant at 33, confirming this is a geometric sequence with first term a=5a = 5 and common ratio r=3r = 3.
    r=3,a=5r = 3, a = 5
  2. Write the general function rule
    Use the geometric sequence formula f(n)=a⋅rn−1f(n) = a \cdot r^{n-1}. Substitute a=5a = 5 and r=3r = 3. State the domain explicitly.
    f(n)=5⋅3n−1,n∈{1,2,3,… }f(n) = 5 · 3^{n-1}, n ∈ \{1, 2, 3, \dots\}
  3. Verify the first few terms
    Check f(1)=5⋅30=5⋅1=5f(1) = 5 \cdot 3^{0} = 5 \cdot 1 = 5 ✓. Check f(2)=5⋅31=15f(2) = 5 \cdot 3^{1} = 15 ✓. Check f(3)=5⋅32=5⋅9=45f(3) = 5 \cdot 3^{2} = 5 \cdot 9 = 45 ✓. The formula matches the given terms.
    f(1)=5,f(2)=15,f(3)=45f(1) = 5, f(2) = 15, f(3) = 45
  4. Evaluate f(6)
    Substitute n=6n = 6 into the formula. Compute the exponent first: 35=2433^{5} = 243. Then multiply by 55.
    f(6)=5⋅35=5⋅243=1215f(6) = 5 · 3^{5} = 5 · 243 = 1215
  5. Determine whether 1215 is a term
    From the calculation above, f(6)=1215f(6) = 1215. So 12151215 is indeed a term of the sequence — specifically, the 6th term. Because n=6n = 6 is a positive integer, this is a valid answer within the sequence's domain.
    f(6)=1215  ⟹  n=6f(6) = 1215 \implies n = 6
Answer: The sequence is geometric. The function is f(n)=5⋅3n−1f(n) = 5 \cdot 3^{n-1}, n ∈ \{1, 2, 3, \dots\}. The 6th term is f(6)=1215f(6) = 1215. Yes, 12151215 is the 6th term of the sequence.
Check: List the terms: CAD 5, 15, 45, 135, 405, 1215. Counting to the 6th position gives 12151215 ✓.

Common mistakes and how to avoid them

Connecting the dots on a sequence graph with a solid line or curve.
Correction: Plot only isolated dots at integer values of nn. A sequence is discrete, so non-integer inputs do not exist and must not be shown.
Using n=0n = 0 as the first term number.
Correction: In MCR3U, the domain of a sequence starts at n=1n = 1. The first term is t1=f(1)t_1 = f(1), not f(0)f(0). Using n=0n = 0 shifts every term number and produces the wrong formula.
Forgetting to check that a solved term number nn is a positive integer.
Correction: When solving f(n)=kf(n) = k, the answer is only valid if nn is a positive integer. A fractional or negative solution means kk is not actually a term of the sequence.
Applying the arithmetic formula to a geometric sequence, or vice versa.
Correction: Always check the pattern first. Compute consecutive differences to test for arithmetic; compute consecutive ratios to test for geometric. Use the matching formula.
Writing f(n)=a⋅rnf(n) = a \cdot r^{n} instead of f(n)=a⋅rn−1f(n) = a \cdot r^{n-1} for a geometric sequence.
Correction: The exponent must be n−1n - 1 so that substituting n=1n = 1 gives f(1)=a⋅r0=af(1) = a \cdot r^{0} = a, which equals the first term. Using rnr^n would make f(1)=arf(1) = ar, which is the second term.

Lesson summary

Check your understanding

Question 1

Which statement best explains why a sequence is called a discrete function?
  1. Its outputs increase by the same amount each time.
  2. Each term number (a positive integer) maps to exactly one term value.
  3. Its graph is always a straight line through the origin.
  4. It can only have a finite number of terms.
Show answer and explanation
Each term number (a positive integer) maps to exactly one term value.
A function requires each input to produce exactly one output. A sequence does this with positive integers as inputs, making it a discrete function. The other options describe specific types of sequences or incorrect ideas — sequences can be infinite and their graphs are not always straight lines.

Question 2

The function f(n)=6n−2f(n) = 6n - 2 with domain {1,2,3,… }\{1, 2, 3, \dots\} represents a sequence. What is f(5)f(5)?
  1. 28
  2. 30
  3. 32
  4. 22
Show answer and explanation
28
Substitute n=5n = 5: f(5)=6(5)−2=30−2=28f(5) = 6(5) - 2 = 30 - 2 = 28. Option B forgets to subtract 2; option C adds 2 instead; option D uses n=4n = 4 instead of n=5n = 5.

Question 3

A sequence is 4,12,36,108,…4, 12, 36, 108, \dots Which function rule describes it correctly?
  1. f(n)=4+8(n−1)f(n) = 4 + 8(n-1)
  2. f(n)=4⋅3nf(n) = 4 \cdot 3^{n}
  3. f(n)=4⋅3n−1f(n) = 4 \cdot 3^{n-1}
  4. f(n)=3⋅4n−1f(n) = 3 \cdot 4^{n-1}
Show answer and explanation
f(n)=4⋅3n−1f(n) = 4 \cdot 3^{n-1}
Each term is multiplied by 33, so the sequence is geometric with a=4a = 4 and r=3r = 3. The correct formula is f(n)=4⋅3n−1f(n) = 4 \cdot 3^{n-1}. Option A is arithmetic (constant difference), which does not fit. Option B uses 3n3^n, giving f(1)=12f(1) = 12 not 44. Option D swaps aa and rr.

Question 4

For the sequence f(n)=5n+2f(n) = 5n + 2, a student solves f(n)=19f(n) = 19 and gets n=3.4n = 3.4. What does this mean?
  1. The 3rd and 4th terms both equal 19.
  2. The value 19 is not a term of this sequence because 3.4 is not a positive integer.
  3. The formula is wrong and needs to be recalculated.
  4. The 4th term equals 19 because you round up to the nearest integer.
Show answer and explanation
The value 19 is not a term of this sequence because 3.4 is not a positive integer.
Solving 5n+2=195n + 2 = 19 gives 5n=175n = 17, so n=3.4n = 3.4. Since term numbers must be positive integers, 3.43.4 is not valid. The value 1919 is simply not a term of this sequence. You never round nn — only exact positive integers are valid term numbers.

Key terms

Sequence
An ordered list of numbers arranged according to a consistent rule or pattern. Each number in the list is called a term.
Term
An individual number in a sequence. The nn-th term is written tnt_n or f(n)f(n).
Term number (index)
The position of a term in a sequence, always a positive integer. It serves as the input to the sequence function.
Discrete function
A function whose domain consists of separated, individual values (here, positive integers) rather than all real numbers.
Arithmetic sequence
A sequence in which consecutive terms differ by a fixed constant called the common difference dd.
Geometric sequence
A sequence in which consecutive terms share a fixed constant ratio rr, found by dividing any term by the previous one.
Common difference (dd)
The constant value added to each term of an arithmetic sequence to produce the next term.
Common ratio (rr)
The constant value by which each term of a geometric sequence is multiplied to produce the next term.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 11 Mathematics (MCR3U), expectation C1.1. It is a study resource, not an official curriculum publication.

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