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D1.4 · Define and relate secant, cosecant, and cotangent

Learn to define and relate secant, cosecant, and cotangent through clear examples and targeted practice.

Ontario Grade 11 Mathematics

Trigonometric Functions

MCR3U – D1.4: Define and Relate Secant, Cosecant, and Cotangent

You already know three trigonometric ratios from Grade 10: sine, cosine, and tangent. Each of those ratios has a reciprocal — a companion ratio formed by flipping it upside down. These three companions are called secant, cosecant, and cotangent. They appear regularly in trigonometric identities and in the analysis of periodic functions, so being comfortable with them is an important step in MCR3U. This lesson builds directly on your knowledge of sin⁡θ\sin\theta, cos⁡θ\cos\theta, and tan⁡θ\tan\theta, so keep those definitions close as you work through the new material.

What you will learn

Prerequisite Bridge: The Three Primary Ratios

Recall from Grade 10 that for a right triangle with an acute angle θ\theta, the three primary ratios are defined using the sides of the triangle relative to that angle. The side directly across from θ\theta is called the opposite side, the side next to θ\theta (that is not the hypotenuse) is the adjacent side, and the longest side is the hypotenuse.
Using those labels: sin⁡θ=oppositehypotenuse\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}}, cos⁡θ=adjacenthypotenuse\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}, and tan⁡θ=oppositeadjacent\tan\theta = \frac{\text{opposite}}{\text{adjacent}}. These three ratios apply to any angle θ\theta in a right triangle, as long as θ\theta is between CAD 0° and CAD 90° (exclusive).
A key arithmetic fact you will need constantly: the reciprocal of a fraction ab\frac{a}{b} is ba\frac{b}{a}, provided neither aa nor bb is zero. For example, the reciprocal of 35\frac{3}{5} is 53\frac{5}{3}. Division by zero is never defined, so a reciprocal ratio is undefined whenever its paired primary ratio equals zero.

Defining the Three Reciprocal Ratios

Each primary ratio has exactly one reciprocal ratio paired with it. The reciprocal of sine is called cosecant, written csc⁡θ\csc\theta. The reciprocal of cosine is called secant, written sec⁡θ\sec\theta. The reciprocal of tangent is called cotangent, written cot⁡θ\cot\theta. Notice the abbreviations: csc, sec, and cot.
Formally, the definitions are: csc⁡θ=1sin⁡θ\csc\theta = \frac{1}{\sin\theta}, which equals hypotenuseopposite\frac{\text{hypotenuse}}{\text{opposite}}. Next, sec⁡θ=1cos⁡θ\sec\theta = \frac{1}{\cos\theta}, which equals hypotenuseadjacent\frac{\text{hypotenuse}}{\text{adjacent}}. Finally, cot⁡θ=1tan⁡θ\cot\theta = \frac{1}{\tan\theta}, which equals adjacentopposite\frac{\text{adjacent}}{\text{opposite}}.
A useful memory tip: the reciprocal of each ratio starts with the same letter as its pair's co-function. Cosecant pairs with sine (both involve 'co' and 's'), and secant pairs with cosine. Just remember that csc goes with sin, and sec goes with cos — they look like they should be switched, but they are not.
Because these ratios are reciprocals, two important relationships always hold for any angle where both sides are defined: sin⁡θ⋅csc⁡θ=1\sin\theta \cdot \csc\theta = 1 and cos⁡θ⋅sec⁡θ=1\cos\theta \cdot \sec\theta = 1 and tan⁡θ⋅cot⁡θ=1\tan\theta \cdot \cot\theta = 1. Multiplying any ratio by its reciprocal always gives 1, the same way 35×53=1\frac{3}{5} \times \frac{5}{3} = 1.
csc⁡θ=1sin⁡θ,sec⁡θ=1cos⁡θ,cot⁡θ=1tan⁡θ\csc\theta = \frac{1}{\sin\theta}, \sec\theta = \frac{1}{\cos\theta}, \cot\theta = \frac{1}{\tan\theta}

When Are the Reciprocal Ratios Undefined?

A reciprocal ratio is undefined whenever its paired primary ratio equals zero, because you cannot divide by zero. Let's check each one carefully.
Cosecant (csc⁡θ\csc\theta) is undefined when sin⁡θ=0\sin\theta = 0. In the range CAD 0° to CAD 360°, sine equals zero at θ=0°\theta = 0° and θ=180°\theta = 180°. At those angles, the opposite side has length zero, so the ratio hypotenuse over opposite has no meaning.
Secant (sec⁡θ\sec\theta) is undefined when cos⁡θ=0\cos\theta = 0. Cosine equals zero at θ=90°\theta = 90° and θ=270°\theta = 270°. At those angles, the adjacent side has length zero.
Cotangent (cot⁡θ\cot\theta) is undefined when tan⁡θ=0\tan\theta = 0, which also occurs at θ=0°\theta = 0° and θ=180°\theta = 180°. Notice that tangent itself is undefined at CAD 90° and CAD 270° (because its denominator, cos⁡θ\cos\theta, is zero there). Cotangent, being the reciprocal of tangent, is actually defined at CAD 90° and CAD 270° — you just evaluate cot⁡90°=cos⁡90°sin⁡90°=01=0\cot 90° = \frac{\cos 90°}{\sin 90°} = \frac{0}{1} = 0.
An alternative formula for cotangent that avoids referencing tangent directly is cot⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{\cos\theta}{\sin\theta}. This comes from writing 1tan⁡θ=1 sin⁡θcos⁡θ =cos⁡θsin⁡θ\frac{1}{\tan\theta} = \frac{1}{\,\frac{\sin\theta}{\cos\theta}\,} = \frac{\cos\theta}{\sin\theta}. This form makes it easier to spot when cotangent is undefined (when sin⁡θ=0\sin\theta = 0) and when it equals zero (when cos⁡θ=0\cos\theta = 0).
cot⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{\cos\theta}{\sin\theta}

Evaluating Reciprocal Ratios on a Calculator

Most scientific calculators do not have dedicated buttons for csc, sec, and cot. Instead, you use the primary ratio and then take its reciprocal. Make sure your calculator is set to degree mode before you start.
To find sec⁡40°\sec 40°, first calculate cos⁡40°\cos 40°, then press the reciprocal button (usually labelled x−1x^{-1} or 1/x1/x). So the sequence is: cos⁡40°≈0.7660\cos 40° \approx 0.7660, then sec⁡40°=10.7660≈1.3054\sec 40° = \frac{1}{0.7660} \approx 1.3054.
The same strategy works for cosecant and cotangent. To find csc⁡25°\csc 25°: calculate sin⁡25°≈0.4226\sin 25° \approx 0.4226, then csc⁡25°=10.4226≈2.3662\csc 25° = \frac{1}{0.4226} \approx 2.3662. To find cot⁡70°\cot 70°: calculate tan⁡70°≈2.7475\tan 70° \approx 2.7475, then cot⁡70°=12.7475≈0.3640\cot 70° = \frac{1}{2.7475} \approx 0.3640.
Notice that when the primary ratio is less than 1 (and positive), its reciprocal is greater than 1. When the primary ratio is exactly 1, the reciprocal is also 1. The reciprocal ratio can never be between −1-1 and 11 (exclusive) for secant and cosecant, because sine and cosine themselves are never greater than 1 in absolute value. Cotangent, however, can take any real value because tangent can.
sec⁡θ=1cos⁡θ,csc⁡θ=1sin⁡θ\sec\theta = \frac{1}{\cos\theta}, \csc\theta = \frac{1}{\sin\theta}

Connecting All Six Ratios: A Unified Picture

You now have six trigonometric ratios in total: sin⁡θ\sin\theta, cos⁡θ\cos\theta, tan⁡θ\tan\theta, csc⁡θ\csc\theta, sec⁡θ\sec\theta, and cot⁡θ\cot\theta. They are all connected, and knowing one ratio for an angle (along with the quadrant) is enough to find all six.
For example, if you know that sin⁡θ=35\sin\theta = \frac{3}{5} and the angle is in the first quadrant, you can use the Pythagorean relationship sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1 to find cos⁡θ=45\cos\theta = \frac{4}{5}. Then tan⁡θ=3/54/5=34\tan\theta = \frac{3/5}{4/5} = \frac{3}{4}. The three reciprocal ratios follow immediately: csc⁡θ=53\csc\theta = \frac{5}{3}, sec⁡θ=54\sec\theta = \frac{5}{4}, cot⁡θ=43\cot\theta = \frac{4}{3}.
This shows that the six ratios always come in three reciprocal pairs: (sin⁡,csc⁡)(\sin, \csc), (cos⁡,sec⁡)(\cos, \sec), and (tan⁡,cot⁡)(\tan, \cot). Understanding these pairs means you only ever need to remember three definitions — the reciprocal definitions give you the other three for free.
sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1

The Six Trigonometric Ratios at a Glance

RatioSymbolDefinition (fraction)Side RelationshipPaired With
Sinesin⁡θ\sin\theta1csc⁡θ\frac{1}{\csc\theta}opp / hypCosecant
Cosinecos⁡θ\cos\theta1sec⁡θ\frac{1}{\sec\theta}adj / hypSecant
Tangenttan⁡θ\tan\theta1cot⁡θ\frac{1}{\cot\theta}opp / adjCotangent
Cosecantcsc⁡θ\csc\theta1sin⁡θ\frac{1}{\sin\theta}hyp / oppSine
Secantsec⁡θ\sec\theta1cos⁡θ\frac{1}{\cos\theta}hyp / adjCosine
Cotangentcot⁡θ\cot\theta1tan⁡θ\frac{1}{\tan\theta}adj / oppTangent

Worked example

Evaluating All Six Ratios from a Right Triangle

A right triangle has legs of length 5 and 12, and a hypotenuse of length 13. The angle θ\theta is opposite the side of length 5. Find all six trigonometric ratios for θ\theta.
  1. Identify the sides relative to angle theta
    The side opposite θ\theta has length 5. The side adjacent to θ\theta has length 12. The hypotenuse is 13. Confirm it is a right triangle: 52+122=25+144=169=1325^2 + 12^2 = 25 + 144 = 169 = 13^2. ✓
    52+122=1325^2 + 12^2 = 13^2
  2. Write the three primary ratios
    Using the definitions opposite/hypotenuse, adjacent/hypotenuse, and opposite/adjacent:
    sin⁡θ=513,cos⁡θ=1213,tan⁡θ=512\sin\theta = \frac{5}{13}, \cos\theta = \frac{12}{13}, \tan\theta = \frac{5}{12}
  3. Write the three reciprocal ratios
    Flip each primary ratio to get its reciprocal. Cosecant is the reciprocal of sine, secant is the reciprocal of cosine, and cotangent is the reciprocal of tangent:
    csc⁡θ=135,sec⁡θ=1312,cot⁡θ=125\csc\theta = \frac{13}{5}, \sec\theta = \frac{13}{12}, \cot\theta = \frac{12}{5}
  4. Verify one reciprocal pair multiplies to 1
    Check that sin⁡θ⋅csc⁡θ=1\sin\theta \cdot \csc\theta = 1 to confirm the reciprocal relationship:
    513×135=1✓\frac{5}{13} × \frac{13}{5} = 1 \checkmark
Answer: sin⁡θ=513\sin\theta = \frac{5}{13}, cos⁡θ=1213\cos\theta = \frac{12}{13}, tan⁡θ=512\tan\theta = \frac{5}{12}, csc⁡θ=135\csc\theta = \frac{13}{5}, sec⁡θ=1312\sec\theta = \frac{13}{12}, cot⁡θ=125\cot\theta = \frac{12}{5}
Check: Each reciprocal pair multiplies to 1: 513⋅135=1\frac{5}{13} \cdot \frac{13}{5} = 1, 1213⋅1312=1\frac{12}{13} \cdot \frac{13}{12} = 1, 512⋅125=1\frac{5}{12} \cdot \frac{12}{5} = 1. All six values are confirmed correct.

Worked example

Using a Known Sine Value to Find the Remaining Five Ratios

Angle α\alpha is in the first quadrant and sin⁡α=725\sin\alpha = \frac{7}{25}. Find cos⁡α\cos\alpha, tan⁡α\tan\alpha, csc⁡α\csc\alpha, sec⁡α\sec\alpha, and cot⁡α\cot\alpha. Then evaluate csc⁡α\csc\alpha as a decimal rounded to four decimal places.
  1. Find cos alpha using the Pythagorean identity
    Start with sin⁡2α+cos⁡2α=1\sin^2\alpha + \cos^2\alpha = 1. Substitute sin⁡α=725\sin\alpha = \frac{7}{25} and solve for cos⁡α\cos\alpha. Since α\alpha is in the first quadrant, cosine is positive.
    cos⁡α=1−(725)2=1−49625=576625=2425\cos\alpha = \sqrt{1 - (\frac{7}{25})^2} = \sqrt{1 - \frac{49}{625}} = \sqrt{\frac{576}{625}} = \frac{24}{25}
  2. Find tan alpha
    Tangent equals sine divided by cosine:
    tan⁡α=sin⁡αcos⁡α=7/2524/25=724\tan\alpha = \frac{\sin\alpha}{\cos\alpha} = \frac{7/25}{24/25} = \frac{7}{24}
  3. Find the three reciprocal ratios
    Flip each primary ratio. Cosecant is the reciprocal of 725\frac{7}{25}, secant is the reciprocal of 2425\frac{24}{25}, and cotangent is the reciprocal of 724\frac{7}{24}:
    csc⁡α=257,sec⁡α=2524,cot⁡α=247\csc\alpha = \frac{25}{7}, \sec\alpha = \frac{25}{24}, \cot\alpha = \frac{24}{7}
  4. Convert csc alpha to a decimal
    Divide 25 by 7 to get the decimal value of csc⁡α\csc\alpha:
    csc⁡α=257≈3.5714\csc\alpha = \frac{25}{7} \approx 3.5714
  5. Verify using the reciprocal relationship
    Check that sin⁡α⋅csc⁡α=1\sin\alpha \cdot \csc\alpha = 1:
    725×257=1✓\frac{7}{25} × \frac{25}{7} = 1 \checkmark
Answer: cos⁡α=2425\cos\alpha = \frac{24}{25}, tan⁡α=724\tan\alpha = \frac{7}{24}, csc⁡α=257≈3.5714\csc\alpha = \frac{25}{7} \approx 3.5714, sec⁡α=2524\sec\alpha = \frac{25}{24}, cot⁡α=247\cot\alpha = \frac{24}{7}
Check: Verify the Pythagorean identity: (725)2+(2425)2=49625+576625=625625=1\left(\frac{7}{25}\right)^2 + \left(\frac{24}{25}\right)^2 = \frac{49}{625} + \frac{576}{625} = \frac{625}{625} = 1. ✓ All five values are confirmed correct.

Common mistakes and how to avoid them

Thinking secant is the reciprocal of sine, and cosecant is the reciprocal of cosine — reversing the pairs.
Correction: Secant (sec⁡\sec) is paired with cosine (cos⁡\cos), and cosecant (csc⁡\csc) is paired with sine (sin⁡\sin). Remember: csc goes with sin.
Stating that cot⁡90°\cot 90° is undefined because tan⁡90°\tan 90° is undefined.
Correction: cot⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{\cos\theta}{\sin\theta}. At CAD 90°, this equals 01=0\frac{0}{1} = 0, so cot⁡90°=0\cot 90° = 0. It is defined.
Forgetting to set the calculator to degree mode and getting an incorrect decimal answer.
Correction: Always confirm degree mode before evaluating. If the answer looks unreasonable (for example, a very large or very small number for a common angle), check the mode setting first.
Believing sec⁡θ\sec\theta can equal 0.80.8 for some angle.
Correction: Because ∣cos⁡θ∣≤1|\cos\theta| \leq 1, its reciprocal satisfies ∣sec⁡θ∣≥1|\sec\theta| \geq 1. A value of 0.80.8 is between −1-1 and 11, so it is impossible for secant. The same applies to cosecant.
Writing csc⁡θ=sin⁡−1θ\csc\theta = \sin^{-1}\theta, confusing reciprocal notation with inverse function notation.
Correction: sin⁡−1θ\sin^{-1}\theta means the inverse sine function (used to find angles), while csc⁡θ=(sin⁡θ)−1=1sin⁡θ\csc\theta = (\sin\theta)^{-1} = \frac{1}{\sin\theta} is a ratio. These are completely different.

Lesson summary

Check your understanding

Question 1

Which of the following correctly defines sec⁡θ\sec\theta?
  1. sec⁡θ=1sin⁡θ\sec\theta = \frac{1}{\sin\theta}
  2. sec⁡θ=1cos⁡θ\sec\theta = \frac{1}{\cos\theta}
  3. sec⁡θ=sin⁡θcos⁡θ\sec\theta = \frac{\sin\theta}{\cos\theta}
  4. sec⁡θ=1tan⁡θ\sec\theta = \frac{1}{\tan\theta}
Show answer and explanation
sec⁡θ=1cos⁡θ\sec\theta = \frac{1}{\cos\theta}
Secant is the reciprocal of cosine, so sec⁡θ=1cos⁡θ\sec\theta = \frac{1}{\cos\theta}. Option A is cosecant, option C is tangent, and option D is cotangent.

Question 2

For which angle is csc⁡θ\csc\theta undefined in the range CAD 0° to CAD 360°?
  1. θ=90°\theta = 90°
  2. θ=270°\theta = 270°
  3. θ=180°\theta = 180°
  4. θ=45°\theta = 45°
Show answer and explanation
θ=180°\theta = 180°
csc⁡θ=1sin⁡θ\csc\theta = \frac{1}{\sin\theta}, so it is undefined when sin⁡θ=0\sin\theta = 0. In the range CAD 0° to CAD 360°, sin⁡180°=0\sin 180° = 0, making csc⁡180°\csc 180° undefined. At CAD 90° and CAD 270°, sine is not zero.

Question 3

A right triangle has cos⁡θ=817\cos\theta = \frac{8}{17}. What is sec⁡θ\sec\theta?
  1. 817\frac{8}{17}
  2. 1715\frac{17}{15}
  3. 1517\frac{15}{17}
  4. 178\frac{17}{8}
Show answer and explanation
178\frac{17}{8}
Secant is the reciprocal of cosine. Flipping 817\frac{8}{17} gives sec⁡θ=178\sec\theta = \frac{17}{8}. The other options involve incorrect side pairings or no reciprocal at all.

Question 4

Which statement about the value of sec⁡θ\sec\theta is always true for any defined angle?
  1. sec⁡θ\sec\theta is always between −1-1 and 11.
  2. ∣sec⁡θ∣≥1|\sec\theta| \geq 1 for all defined angles.
  3. sec⁡θ\sec\theta is always positive.
  4. sec⁡θ\sec\theta equals sin⁡θ\sin\theta when θ=45°\theta = 45°.
Show answer and explanation
∣sec⁡θ∣≥1|\sec\theta| \geq 1 for all defined angles.
Because ∣cos⁡θ∣≤1|\cos\theta| \leq 1, its reciprocal satisfies ∣sec⁡θ∣≥1|\sec\theta| \geq 1. Secant can be negative (e.g., in the second or third quadrant), so option C is false. At CAD 45°, sec⁡45°=1cos⁡45°=2≠sin⁡45°\sec 45° = \frac{1}{\cos 45°} = \sqrt{2} \neq \sin 45°, so option D is also false.

Key terms

Reciprocal
The result of swapping the numerator and denominator of a fraction. The reciprocal of ab\frac{a}{b} is ba\frac{b}{a}, provided neither is zero.
Secant (sec⁡θ\sec\theta)
The reciprocal of cosine: sec⁡θ=1cos⁡θ\sec\theta = \frac{1}{\cos\theta}. In a right triangle it equals hypotenuse divided by adjacent.
Cosecant (csc⁡θ\csc\theta)
The reciprocal of sine: csc⁡θ=1sin⁡θ\csc\theta = \frac{1}{\sin\theta}. In a right triangle it equals hypotenuse divided by opposite.
Cotangent (cot⁡θ\cot\theta)
The reciprocal of tangent: cot⁡θ=1tan⁡θ=cos⁡θsin⁡θ\cot\theta = \frac{1}{\tan\theta} = \frac{\cos\theta}{\sin\theta}. In a right triangle it equals adjacent divided by opposite.
Undefined ratio
A trigonometric ratio is undefined when its denominator equals zero, because division by zero has no meaning.
Degree mode
A calculator setting that interprets angles as degrees rather than any other unit. Always confirm this setting before evaluating trigonometric ratios in MCR3U.
Pythagorean identity
The identity sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1, which holds for every angle θ\theta. It comes from the Pythagorean theorem applied to a unit right triangle.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 11 Mathematics (MCR3U), expectation D1.4. It is a study resource, not an official curriculum publication.

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