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B2.7 · Solve sinusoidal applications in radians

Learn to solve sinusoidal applications in radians through clear examples and targeted practice.

Ontario Grade 12 Mathematics

Trigonometric Functions

Build a model, connect it to a situation, and find the times or values that answer a question.

Sinusoidal models describe quantities that repeat in a smooth cycle. Examples include the height of a point on a rotating wheel and the position of a swinging object over time. In an application, the model connects a changing quantity to an input such as time. This lesson focuses on solving those applications when angles are measured in radians. Before calculating, identify the cycle, set up a model that fits the situation, and keep track of which solutions are meaningful.

What you will learn

1. Prerequisite bridge: read a repeating cycle

A sinusoidal graph is a smooth wave that repeats. Its highest and lowest values are called the maximum and minimum. The midline is the horizontal line halfway between them. The amplitude is the vertical distance from the midline to a maximum or minimum. It is always positive.
The period is the input distance needed for one complete cycle. For a time-based model, it tells how long one cycle takes. A cycle may be described using sine or cosine. Sine begins at the midline when its angle is zero. Cosine begins at a maximum when its angle is zero. Reflections or shifts can change these starting positions.
Radians measure angles. One complete turn is 2π2\pi radians, and a half-turn is π\pi radians. A calculator must be in radian mode when you evaluate trigonometric expressions or use inverse trigonometric functions in a radian model.
midline=maximum+minimum2,amplitude=maximum−minimum2\text{midline}=\frac{\text{maximum}+\text{minimum}}{2},\quad \text{amplitude}=\frac{\text{maximum}-\text{minimum}}{2}

2. From a situation to a sinusoidal model

Begin with the setting. Decide what the input and output represent, and write their units. For example, the input might be time in seconds and the output might be height in metres. Identify the maximum and minimum output values. These give the midline and amplitude.
Next, determine the period from the situation. A model with period PP has an angle that completes one full turn, or 2π2\pi radians, during that input interval. Therefore, the multiplier on the input is 2π/P2\pi/P. This multiplier is often called the angular frequency; here it simply converts the input into the angle used by sine or cosine.
Choose sine or cosine to match a known point in the cycle. If the quantity starts at a maximum, a cosine model is often convenient. If it starts at the midline and rises, a sine model is often convenient. A negative sign can represent a reflected curve. A horizontal shift can place a maximum, minimum, or midline crossing at the correct input value.
A common model is y=Asin⁡(B(x−D))+Cy=A\sin(B(x-D))+C or y=Acos⁡(B(x−D))+Cy=A\cos(B(x-D))+C. In either form, CC is the midline, |A| is the amplitude, and the period is 2π/∣B∣2\pi/|B|. The value DD shifts the cycle horizontally. These symbols describe features of the situation, so their units should be interpreted in context.
P=2π∣B∣P=\frac{2\pi}{|B|}

3. Solve and interpret the model

An application question may ask for an output at a given time or for the time when an output reaches a specified value. For an output question, substitute the input into the model and evaluate. For a time question, set the model equal to the target output and solve the trigonometric equation.
A target output can occur more than once in a cycle. Sine and cosine repeat, so solving for one angle is not always enough. Use the graph, a cycle sketch, or the situation to find every solution in the requested interval. Then convert angles to input values using the model’s angle multiplier and shift.
Inverse sine and inverse cosine on a calculator usually return one angle, not every angle in the cycle. Use the symmetry of the graph to identify any other angle that fits. Finally, check each answer by substituting it into the model and confirm that it falls within the time interval and makes sense in the situation.
θ=B(x−D)\theta=B(x-D)

4. Application habits

A good solution tells the reader what the variables mean. State the units for the input and output. If the answer is a time, report it as a time in the situation, not just as an angle. Rounding should suit the context. For example, a time measured in seconds might be reported to the nearest hundredth of a second if the model and question support that precision.
It is useful to check the model at important points in the cycle. At a maximum, the output should equal the midline plus the amplitude. At a minimum, it should equal the midline minus the amplitude. After one period, the model should return to the same value. These checks can reveal a wrong sign, period, or shift before you solve the full question.

Wheel heights at key points in one rotation

Time (s)Angle (rad)Height (m)
001
3π2\frac{\pi}{2}4
6\pi7
93π2\frac{3\pi}{2}4
122\pi1

Worked example

Height of a point on a rotating wheel

A point on a wheel moves in a vertical circle of radius 33 m. The wheel’s centre is 44 m above the ground. At time t=0t=0, the point is at the bottom and begins moving upward. The wheel turns at π6\frac{\pi}{6} radians per second. Find the first two positive times when the point is 55 m above the ground.
  1. Identify the cycle features
    The lowest height is 4−3=14-3=1 m and the highest is 4+3=74+3=7 m. Thus the midline is 44 m and the amplitude is 33 m. One full turn takes 2π2\pi divided by the angular speed, so the period is 1212 seconds.
    P=2ππ/6=12P=\frac{2\pi}{\pi/6}=12
  2. Choose a model
    The point starts at its minimum height, so a negative cosine model is convenient. The centre height is the midline, and the given turning rate is the angle multiplier. This model starts at 11 m and then increases, as described.
    h(t)=4−3cos⁡(π6t)h(t)=4-3\cos\left(\frac{\pi}{6}t\right)
  3. Set the height to the target
    Substitute the target height of 55 m into the model. Rearranging gives a cosine value of −13-\frac{1}{3}. Use the calculator in radian mode to find the angle in the first half of the cycle.
    5=4−3cos⁡(π6t),cos⁡(π6t)=−135=4-3\cos\left(\frac{\pi}{6}t\right),\qquad \cos\left(\frac{\pi}{6}t\right)=-\frac{1}{3}
  4. Find both angles in one turn
    The first angle is approximately 1.9111.911 radians. Cosine has the same value again later in the turn, at 2π−1.911≈4.3732\pi-1.911\approx4.373 radians. Both angles lie between 00 and 2π2\pi, so they give the two crossings in the first rotation.
    θ1≈1.911,θ2≈2π−1.911=4.373\theta_1\approx1.911,\qquad \theta_2\approx2\pi-1.911=4.373
  5. Convert angles to times
    The model’s angle is π6t\frac{\pi}{6}t, so divide each angle by π6\frac{\pi}{6}. Round to the nearest hundredth. Both times are positive and are less than the 1212-second period.
    t1≈3.65 s,t2≈8.35 st_1\approx3.65\text{ s},\qquad t_2\approx8.35\text{ s}
Answer: The point is 55 m above the ground at approximately 3.653.65 s and 8.358.35 s after it starts moving.
Check: The point rises from its minimum at time zero, reaches its maximum halfway through the rotation at 66 s, and returns to the bottom at 1212 s. The two calculated times fall on either side of 66 s, as expected for the same height.

Common mistakes and how to avoid them

Using the maximum as the midline or using the full maximum-to-minimum distance as the amplitude.
Correction: The midline is the average of the maximum and minimum. The amplitude is half their difference.
Using a period multiplier that does not match the stated period.
Correction: For a model with input multiplier BB, check that its period is 2π/∣B∣2\pi/|B|.
Leaving a calculator in degree mode for a radian model.
Correction: Set the calculator to radian mode before evaluating trigonometric or inverse trigonometric expressions.
Reporting only the first time a target value occurs.
Correction: Check the full requested interval. A sinusoidal quantity may reach the same target more than once in a cycle.
Reporting an angle as the answer when the question asks for time.
Correction: Convert the angle back to the input using the model, then report the time with units.

Lesson summary

Check your understanding

Question 1

A sinusoidal model has maximum value 1111 and minimum value 33. What are its midline and amplitude?
  1. Midline 77, amplitude 44
  2. Midline 88, amplitude 44
  3. Midline 77, amplitude 88
  4. Midline 44, amplitude 77
Show answer and explanation
Midline 77, amplitude 44
The midline is (11+3)/2=7(11+3)/2=7. The amplitude is (11−3)/2=4(11-3)/2=4.

Question 2

A model is y=2sin⁡(π4t)+6y=2\sin(\frac{\pi}{4}t)+6. What is its period?
  1. 44
  2. 88
  3. π4\frac{\pi}{4}
  4. 2π2\pi
Show answer and explanation
88
Here B=π4B=\frac{\pi}{4}. The period is 2π/(π/4)=82\pi/(\pi/4)=8.

Question 3

A rotating point is modelled by h(t)=5+2cos⁡(π3t)h(t)=5+2\cos(\frac{\pi}{3}t). What is its height at t=3t=3 seconds?
  1. 33
  2. 55
  3. 77
  4. 00
Show answer and explanation
33
At t=3t=3, the angle is π\pi. Since cos⁡(π)=−1\cos(\pi)=-1, the height is 5+2(−1)=35+2(-1)=3.

Key terms

Sinusoidal model
A sine- or cosine-based function used to represent a repeating, wave-shaped pattern.
Midline
The horizontal level halfway between a sinusoidal model’s maximum and minimum.
Amplitude
The vertical distance from the midline to a maximum or minimum.
Period
The input change needed for one complete repetition.
Radian
A unit for measuring angle; a full turn is 2π2\pi radians.
Angular frequency
The number that converts the input into the angle used by a sinusoidal model.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 12 Mathematics (MHF4U), expectation B2.7. It is a study resource, not an official curriculum publication.

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