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Position, Displacement, and Total Distance Using Derivatives

Name: Position, Displacement, and Total Distance Using Derivatives
Uploaded: 2026-07-18T13:50:45.355Z
Duration: 3 min 10 s
Description: Given the position function $s = 1.5t^3 - 13.5t^2 + 22.5t$ ft, where $t$ is in seconds, find: 1. The position at $t = 6$ s 2. The total distance traveled from $t = 0$ to $t = 6$ s

Calculus · Calculus — University

Course: Calculus Book: Calculus — University

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Given the position function

s = 1.5t^3 - 13.5t^2 + 22.5t

ft, where

t

is in seconds, find: 1. The position at

t = 6

s 2. The total distance traveled from

t = 0

t = 6

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Position, Displacement, and Total Distance Using Derivatives

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Problem and lesson overview

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