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Problem 12-46: Engineering Mechanics- Dynamics (Hibbeler 14th Edition)

Engineering Mechanics Dynamics · R.C. Hibbeler · Chapter 12

Course: Engineering Mechanics Dynamics Book: R.C. Hibbeler Chapter: Chapter 12

Question

A rocket moves along a straight track starting from rest ($v = 0$ at $s = 0$). Its acceleration–position relationship is: $$a(s) = \begin{cases} 5 \ \text{ft/s}^2 & 0 \leq s \leq 100 \ \text{ft} \\ 5 + 6\left(\sqrt{s} - 10\right)^{5/3} \ \text{ft/s}^2 & s > 100 \ \text{ft} \end{cases}$$ Determine the speed $v$ when $s = 75$ ft and when $s = 125$ ft. Use Simpson's Rule with $n = 100$ intervals to evaluate the integral at $s = 125$ ft.

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