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Problem 12-50: Engineering Mechanics- Dynamics (Hibbeler 14th Edition)

Engineering Mechanics Dynamics · R.C. Hibbeler · Chapter 12

Course: Engineering Mechanics Dynamics Book: R.C. Hibbeler Chapter: Chapter 12

Question

Question:
A car starts from rest at s equals 0 and is subjected to an acceleration defined by the following a-s graph. For s from 0 to 300 feet, acceleration equals 12 feet per second squared. For s from 300 to 450 feet, acceleration equals negative 0.04 times s plus 24 feet per second squared, which decreases linearly from 12 feet per second squared at s equals 300 feet down to 6 feet per second squared at s equals 450 feet. Draw the v-s graph and determine the time needed to travel 200 feet.

Problem 12-50: Engineering Mechanics- Dynamics (Hibbeler 14th Edition)

This lesson develops velocity–position (v–s) relationships directly from a piecewise acceleration–position (a–s) graph using the kinematic identity a ds = v dv. Students construct the v–s graph analytically and then integrate v = ds/dt to determine the time required to reach a specified position.

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