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B1.1 · Graph and define exponential functions

Learn to graph and define exponential functions through clear examples and targeted practice.

Ontario Grade 11 Mathematics

Exponential Functions

MCR3U – Unit B1.1 | Understanding, Graphing, and Defining Exponential Functions

You already know how to evaluate powers like 23=82^3 = 8 or 5−1=0.25^{-1} = 0.2. In previous grades you worked with linear functions (straight lines) and quadratic functions (parabolas). Both of those have the variable in the base — for example, x2x^2. An exponential function flips that idea: the variable sits in the exponent, and the base is a fixed positive number. That one change produces dramatically different behaviour — quantities that double, triple, or shrink by a fixed proportion with every step. Population growth, radioactive decay, and compound interest all follow this pattern. This lesson builds the definition carefully, connects it to a table of values and a graph, and develops the key vocabulary you need for the rest of the exponential unit.

What you will learn

Prerequisite Bridge: Powers and Function Notation

Before defining an exponential function, recall two tools from earlier courses. First, integer and rational exponents: for any real base bb and positive integer nn, the expression bnb^n means bb multiplied by itself nn times, and b0=1b^0 = 1 for any non-zero base. Negative exponents mean reciprocals: b−n=1bnb^{-n} = \frac{1}{b^n}. These rules still apply when the exponent is a variable.
Second, function notation: writing f(x)f(x) simply means 'the output of function ff when the input is xx'. So f(3)f(3) means substitute x=3x = 3 into the rule for ff and calculate. Nothing about this changes when the rule is exponential — you still substitute and simplify.

Defining an Exponential Function

An exponential function is a function of the form f(x)=bxf(x) = b^x, where bb is a positive constant called the base, and xx is the variable (the exponent). The base must satisfy b>0b > 0 and b≠1b \neq 1. Understanding why these restrictions exist is important.
Why must b>0b > 0? If bb were negative, powers like b1/2b^{1/2} (the square root) would not produce real numbers. For example, (−4)1/2=−4(-4)^{1/2} = \sqrt{-4}, which is not a real number. Allowing negative bases would create gaps in the domain, so we exclude them.
Why must b≠1b \neq 1? If b=1b = 1, then 1x=11^x = 1 for every value of xx. That gives a constant function — a flat horizontal line — which has none of the interesting growing or shrinking behaviour we associate with exponential functions. It is technically valid but not useful here, so we exclude it by definition.
The domain of f(x)=bxf(x) = b^x is all real numbers, written \{x ∈ R\mathbb{R}\}, because you can raise a positive base to any power and get a real result. The range is all positive real numbers, \{y ∈ R\mathbb{R} \mid y > 0\}, because a positive base raised to any power is always positive — it never equals zero and never goes negative.
f(x)=bx,b>0,b≠1f(x) = b^x, b > 0, b ≠ 1

Graphing Exponential Functions: Growth vs. Decay

To graph f(x)=bxf(x) = b^x, build a table of values for several integer inputs, plot the points, and connect them with a smooth curve. The shape of the curve depends entirely on whether b>1b > 1 or 0<b<10 < b < 1.
When b>1b > 1, the function models exponential growth. As xx increases, f(x)f(x) increases rapidly. As xx decreases (moves left), f(x)f(x) gets closer and closer to zero but never actually reaches it. The xx-axis acts as a horizontal asymptote — a line the graph approaches but never crosses. The graph rises steeply to the right and flattens toward the left.
When 0<b<10 < b < 1, the function models exponential decay. As xx increases, f(x)f(x) decreases and approaches zero. As xx decreases, f(x)f(x) grows without bound. The graph falls steeply to the right and rises to the left. The xx-axis is still a horizontal asymptote.
A horizontal asymptote is an imaginary horizontal line that the graph gets infinitely close to but never touches. For f(x)=bxf(x) = b^x, that asymptote is always the xx-axis, written as y=0y = 0. This tells you the range cannot include zero or any negative number.
Comparing bases: for two growth functions f(x)=2xf(x) = 2^x and g(x)=5xg(x) = 5^x, both pass through (0,1)(0, 1) and both increase to the right. However, gg grows much more steeply because a larger base means each unit increase in xx multiplies the output by a larger factor. For two decay functions f(x)=(0.8)xf(x) = (0.8)^x and g(x)=(0.3)xg(x) = (0.3)^x, gg decreases more rapidly because the base 0.30.3 is further from 11 than 0.80.8 is.

Key Characteristics Summary

When describing the graph of an exponential function, mathematicians focus on five characteristics: domain, range, intercepts, asymptote, and end behaviour. Knowing these five features lets you sketch or interpret any basic exponential graph quickly and precisely.
The domain is always all real numbers because any real number is a valid exponent for a positive base. The range is always y>0y > 0 because the output is a positive number raised to a power. There is always a yy-intercept at (0,1)(0, 1), and there is never an xx-intercept because the graph never crosses the xx-axis. The horizontal asymptote is y=0y = 0.
End behaviour describes what happens to f(x)f(x) as xx becomes very large (written x \to +\infty) or very small (written x \to -\infty).Forgrowth(). For growth (b > 1):as): as x \to +\infty, f(x) \to +\infty; as x \to -\infty, f(x) \to 0.Fordecay(. For decay (0 < b < 1):as): as x \to +\infty, f(x) \to 0; as x \to -\infty, f(x) \to +\infty.

Key Features of f(x) = b^x: Growth vs. Decay at a Glance

FeatureGrowth (b > 1)Decay (0 < b < 1)
Example baseb=3b = 3b=13b = \frac{1}{3}
DomainAll real numbersAll real numbers
Rangey>0y > 0y>0y > 0
y-intercept(0,1)(0, 1)(0,1)(0, 1)
Horizontal asymptotey=0y = 0y=0y = 0
As x \to +\inftyf(x) \to +\inftyf(x) \to 0
As x \to -\inftyf(x) \to 0f(x) \to +\infty
Graph directionRises left to rightFalls left to right

Worked example

Example 1 – Building a Table and Sketching the Graph of an Exponential Growth Function

Let f(x)=3xf(x) = 3^x. (a) Evaluate f(x)f(x) for x ∈ \{-2, -1, 0, 1, 2, 3\}. (b) State the domain, range, yy-intercept, and horizontal asymptote. (c) Describe the end behaviour and identify whether this is growth or decay.
  1. Substitute each input value
    Replace xx with each integer in the set and apply exponent rules. For negative exponents, use 3−n=13n3^{-n} = \frac{1}{3^n}. Calculate each output carefully: f(−2)=3−2=19f(-2) = 3^{-2} = \frac{1}{9}, f(−1)=3−1=13f(-1) = 3^{-1} = \frac{1}{3}, f(0)=30=1f(0) = 3^{0} = 1, f(1)=31=3f(1) = 3^{1} = 3, f(2)=32=9f(2) = 3^{2} = 9, f(3)=33=27f(3) = 3^{3} = 27.
    f(x)=3xf(x) = 3^x
  2. Record the table of values
    Organize the six input-output pairs. Notice that each time xx increases by 11, the output is multiplied by 33. This constant multiplication factor is the hallmark of an exponential function and explains its rapid growth.
  3. Identify domain and range
    Because any real number can be used as an exponent of 33, the domain is all real numbers. The outputs 19,13,1,3,9,27\frac{1}{9}, \frac{1}{3}, 1, 3, 9, 27 are all positive, and this holds for every real xx — the base 33 raised to any power can never be zero or negative. So the range is all positive real numbers.
    Domain: {x∈R},Range: {y∈R∣y>0}\text{Domain: } \{x ∈ \mathbb{R}\}, \text{Range: } \{y ∈ \mathbb{R} \mid y > 0\}
  4. State the y-intercept and asymptote
    At x=0x = 0, f(0)=30=1f(0) = 3^0 = 1, so the yy-intercept is the point (0,1)(0, 1). As xx decreases, f(x)f(x) gets smaller and smaller, approaching zero but never reaching it. The line y=0y = 0 (the xx-axis) is the horizontal asymptote.
    y-intercept: (0,1),asymptote: y=0y\text{-intercept: } (0,1), \text{asymptote: } y = 0
  5. Describe end behaviour and classify
    Since the base 33 is greater than 11, this is an exponential growth function. As xx increases without limit, f(x)f(x) increases without limit. As xx decreases without limit, f(x)f(x) approaches 00. The graph rises steeply to the right and hugs the xx-axis to the left.
Answer: Table: (−2, 19)(-2,\, \frac{1}{9}), (−1, 13)(-1,\, \frac{1}{3}), (0, 1)(0,\, 1), (1, 3)(1,\, 3), (2, 9)(2,\, 9), (3, 27)(3,\, 27). Domain: all real numbers. Range: y>0y > 0. yy-intercept: (0,1)(0, 1). Horizontal asymptote: y=0y = 0. Exponential growth because b=3>1b = 3 > 1.
Check: Verify a midpoint: 32=93^2 = 9 ✓. Verify a negative exponent: 3−2=132=193^{-2} = \frac{1}{3^2} = \frac{1}{9} ✓. Each successive output is exactly 33 times the previous one: 19×3=13\frac{1}{9} \times 3 = \frac{1}{3}, 13×3=1\frac{1}{3} \times 3 = 1, 1×3=31 \times 3 = 3 ✓. All outputs are positive, confirming range y>0y > 0 ✓.

Worked example

Example 2 – Identifying and Comparing Two Exponential Functions From Their Equations

Two functions are defined as g(x)=(14)xg(x) = \left(\frac{1}{4}\right)^x and h(x)=4xh(x) = 4^x. (a) Classify each as growth or decay and justify your answer. (b) Evaluate both functions at x=−1x = -1, x=0x = 0, and x=2x = 2. (c) Explain how the graphs of gg and hh are related to each other.
  1. Identify the base of each function
    For g(x)g(x), the base is 14\frac{1}{4}. Since 0<14<10 < \frac{1}{4} < 1, this is exponential decay — outputs decrease as xx increases. For h(x)h(x), the base is 44. Since 4>14 > 1, this is exponential growth — outputs increase as xx increases.
    bg=14,bh=4b_g = \frac{1}{4}, b_h = 4
  2. Evaluate g(x) at the three inputs
    Substitute x=−1x = -1: g(−1)=(14)−1g(-1) = \left(\frac{1}{4}\right)^{-1}. A negative exponent means take the reciprocal, so (14)−1=4\left(\frac{1}{4}\right)^{-1} = 4. Substitute x=0x = 0: g(0)=(14)0=1g(0) = \left(\frac{1}{4}\right)^{0} = 1. Substitute x=2x = 2: g(2)=(14)2=116g(2) = \left(\frac{1}{4}\right)^{2} = \frac{1}{16}.
    g(−1)=4,g(0)=1,g(2)=116g(-1) = 4, g(0) = 1, g(2) = \frac{1}{16}
  3. Evaluate h(x) at the three inputs
    Substitute x=−1x = -1: h(−1)=4−1=14h(-1) = 4^{-1} = \frac{1}{4}. Substitute x=0x = 0: h(0)=40=1h(0) = 4^{0} = 1. Substitute x=2x = 2: h(2)=42=16h(2) = 4^{2} = 16.
    h(−1)=14,h(0)=1,h(2)=16h(-1) = \frac{1}{4}, h(0) = 1, h(2) = 16
  4. Compare the outputs at each x-value
    At x=−1x = -1: gg gives 44 and hh gives 14\frac{1}{4} — these are reciprocals. At x=0x = 0: both give 11 — both graphs share the yy-intercept (0,1)(0,1). At x=2x = 2: gg gives 116\frac{1}{16} and hh gives 1616 — again reciprocals. This pattern holds for all xx: g(x)=(14)x=14x=4−x=h(−x)g(x) = \left(\frac{1}{4}\right)^x = \frac{1}{4^x} = 4^{-x} = h(-x).
    g(x)=4−x=h(−x)g(x) = 4^{-x} = h(-x)
  5. Describe the graphical relationship
    Because g(x)=h(−x)g(x) = h(-x), the graph of gg is the reflection of the graph of hh across the yy-axis. Every point (a,c)(a, c) on the graph of hh corresponds to the point (−a,c)(-a, c) on the graph of gg. Both graphs share the point (0,1)(0, 1) — the only point on the yy-axis — and both have the horizontal asymptote y=0y = 0.
Answer: g(x)=(14)xg(x) = \left(\frac{1}{4}\right)^x is exponential decay (b<1b < 1); h(x)=4xh(x) = 4^x is exponential growth (b>1b > 1). Values: g(−1)=4g(-1)=4, g(0)=1g(0)=1, g(2)=116g(2)=\frac{1}{16}; h(−1)=14h(-1)=\frac{1}{4}, h(0)=1h(0)=1, h(2)=16h(2)=16. The graph of gg is the reflection of the graph of hh in the yy-axis because g(x)=h(−x)g(x) = h(-x).
Check: Check g(2)g(2): (14)2=1242=116\left(\frac{1}{4}\right)^2 = \frac{1^2}{4^2} = \frac{1}{16} ✓. Check that outputs are reciprocals: 4×14=14 \times \frac{1}{4} = 1 ✓ and 16×116=116 \times \frac{1}{16} = 1 ✓. Both functions have all positive outputs, confirming range y>0y > 0 for each ✓.

Common mistakes and how to avoid them

Writing f(x)=xbf(x) = x^b (variable in the base) and calling it exponential. For example, confusing f(x)=x3f(x) = x^3 with f(x)=3xf(x) = 3^x.
Correction: In an exponential function, the variable xx is always the exponent and the base bb is the fixed constant. x3x^3 is a power function (cubic), not an exponential function.
Thinking that b0=0b^0 = 0 instead of b0=1b^0 = 1, which leads to an incorrect yy-intercept of (0,0)(0, 0).
Correction: Any non-zero base raised to the power of zero equals 11, so the yy-intercept of f(x)=bxf(x) = b^x is always (0,1)(0, 1), not the origin.
Believing an exponential function can produce zero or negative outputs, and therefore drawing the graph crossing or touching the xx-axis.
Correction: A positive base raised to any real power is always positive. The xx-axis (y=0y = 0) is a horizontal asymptote — the graph gets close but never touches it.
Applying the negative exponent incorrectly: writing (14)−1=−4\left(\frac{1}{4}\right)^{-1} = -4 instead of 44.
Correction: A negative exponent means take the reciprocal of the base: (14)−1=1(1/4)=4\left(\frac{1}{4}\right)^{-1} = \frac{1}{(1/4)} = 4. The reciprocal of a fraction flips numerator and denominator.
Thinking that a base between 0 and 1 means the function values go negative as xx increases.
Correction: Bases between 0 and 1 produce outputs that approach zero (decay) but never become zero or negative. All outputs remain in the range y>0y > 0.

Lesson summary

Check your understanding

Question 1

Which of the following is an exponential function?
  1. f(x)=x5f(x) = x^5
  2. f(x)=5xf(x) = 5^x
  3. f(x)=5xf(x) = 5x
  4. f(x)=x1/5f(x) = x^{1/5}
Show answer and explanation
f(x)=5xf(x) = 5^x
f(x)=5xf(x) = 5^x has the variable in the exponent and a fixed positive base — this matches the definition f(x)=bxf(x) = b^x with b=5>1b = 5 > 1. The other options all have the variable in the base, making them a power function, linear function, and radical function respectively.

Question 2

What are the domain and range of f(x)=7xf(x) = 7^x?
  1. Domain: x>0x > 0; Range: all real numbers
  2. Domain: all real numbers; Range: y>0y > 0
  3. Domain: all real numbers; Range: all real numbers
  4. Domain: x>0x > 0; Range: y>0y > 0
Show answer and explanation
Domain: all real numbers; Range: y>0y > 0
Any real number can be used as an exponent of 77, so the domain is all real numbers. Because 7x7^x is always positive for any real xx, the range is y>0y > 0. The output can never be zero or negative.

Question 3

The graph of f(x)=(15)xf(x) = \left(\frac{1}{5}\right)^x has what type of behaviour and what horizontal asymptote?
  1. Exponential growth; asymptote y=1y = 1
  2. Exponential decay; asymptote y=1y = 1
  3. Exponential growth; asymptote y=0y = 0
  4. Exponential decay; asymptote y=0y = 0
Show answer and explanation
Exponential decay; asymptote y=0y = 0
The base 15\frac{1}{5} satisfies 0<15<10 < \frac{1}{5} < 1, so this is exponential decay — the graph falls as xx increases. The horizontal asymptote for any function of the form f(x)=bxf(x) = b^x is y=0y = 0, not y=1y = 1.

Question 4

If g(x)=2xg(x) = 2^x, what is the value of g(−3)g(-3)?
  1. −8-8
  2. 18\frac{1}{8}
  3. 66
  4. 88
Show answer and explanation
18\frac{1}{8}
Substitute x=−3x = -3: g(−3)=2−3g(-3) = 2^{-3}. A negative exponent means take the reciprocal: 2−3=123=182^{-3} = \frac{1}{2^3} = \frac{1}{8}. The answer is 18\frac{1}{8}, a positive value less than 11 — consistent with the range y>0y > 0.

Key terms

Exponential function
A function of the form f(x)=bxf(x) = b^x where the base bb is a positive constant not equal to 11, and the variable xx is the exponent.
Base
The fixed positive number bb in an exponential function that is repeatedly multiplied. It must satisfy b>0b > 0 and b≠1b \neq 1.
Exponent
The variable or number that tells how many times the base is used as a factor. In f(x)=bxf(x) = b^x, the exponent is xx.
Horizontal asymptote
A horizontal line that a graph gets infinitely close to but never crosses. For f(x)=bxf(x) = b^x, the horizontal asymptote is y=0y = 0.
Exponential growth
The behaviour of f(x)=bxf(x) = b^x when b>1b > 1: outputs increase as xx increases, and the graph rises from left to right.
Exponential decay
The behaviour of f(x)=bxf(x) = b^x when 0<b<10 < b < 1: outputs decrease toward zero as xx increases, and the graph falls from left to right.
Domain
The set of all allowed input values for a function. For f(x)=bxf(x) = b^x, the domain is all real numbers.
Range
The set of all possible output values of a function. For f(x)=bxf(x) = b^x, the range is all positive real numbers (y>0y > 0).

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 11 Mathematics (MCR3U), expectation B1.1. It is a study resource, not an official curriculum publication.

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