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D2.6 · Determine amplitude, period, phase shift, domain, and range

Learn to determine amplitude, period, phase shift, domain, and range through clear examples and targeted practice.

Ontario Grade 11 Mathematics

Trigonometric Functions

MCR3U – D2.6 | Transformations of Trigonometric Functions

You already know that the sine and cosine curves repeat in a wave-like pattern. In Grade 10, you explored what these basic curves look like. Now, in Grade 11, you will learn how to read an equation and immediately know everything important about its graph: how tall the wave is, how long one full cycle takes, whether the wave has slid left or right, and what set of inputs and outputs the function uses. These five features, amplitude, period, phase shift, domain, and range, are the complete identity card of any sinusoidal function. Mastering them lets you sketch, interpret, and compare waves without plotting dozens of points.

What you will learn

Prerequisite Bridge: The Basic Sine and Cosine Curves

Before transformations, recall what the parent functions y=sin⁡xy = \sin x and y=cos⁡xy = \cos x look like. Both curves oscillate smoothly between a minimum value of −1-1 and a maximum value of 11. One complete wave, called a cycle, takes CAD 360° to finish. The sine curve starts at (0°,0)(0°, 0), rises to a peak, falls through zero, dips to a trough, and returns to zero. The cosine curve starts at (0°,1)(0°, 1), which is already at its peak.
Both parent functions are defined for every real-number input, so their domain is all real numbers. Because the output never goes below −1-1 or above 11, their range is −1≤y≤1-1 \leq y \leq 1. Keep these benchmarks in mind, since every transformation you study today is a change made to these starting values.

The General Form and What Each Parameter Does

A transformed sinusoidal function is written in the general form y=asin⁡(k(x−d))+cy = a\sin(k(x - d)) + c or y=acos⁡(k(x−d))+cy = a\cos(k(x - d)) + c. There are four parameters: aa, kk, dd, and cc. Each one controls a different feature of the graph, and you can read all four directly from the equation.
The parameter aa is the coefficient in front of the sine or cosine. It stretches or compresses the wave vertically and controls the amplitude. The parameter kk is the coefficient inside the brackets, beside xx. It stretches or compresses the wave horizontally and controls the period. The parameter dd is the value being subtracted from xx inside the brackets. It slides the entire graph left or right and controls the phase shift. The parameter cc is the constant added on the outside. It shifts the graph up or down and controls the vertical shift, which in turn affects the range.
Notice that the form uses k(x−d)k(x - d), not kx−dkx - d. This distinction is critical. If you see y=sin⁡(2x−90°)y = \sin(2x - 90°), you must factor the inside first, giving y=sin⁡(2(x−45°))y = \sin(2(x - 45°)). Only then can you read d=45°d = 45° correctly. Skipping this factoring step is the single most common error in this unit.
y=asin⁡(k(x−d))+cy = a\sin(k(x - d)) + c

Calculating Each Feature from the Equation

Amplitude is the distance from the midline of the wave to its maximum (or minimum) value. It is always a positive number. Calculate it using the absolute value of aa. For example, if a=−3a = -3, the amplitude is 33. The negative sign on aa means the wave is reflected (flipped upside down), but the amplitude, the height, is still 33.
Period is the horizontal length of one complete cycle, measured in degrees. It tells you how far the wave travels along the xx-axis before repeating. Divide CAD 360°by by |k| to find it. If ∣k∣>1|k| > 1, the wave is horizontally compressed, so cycles are shorter. If 0<∣k∣<10 < |k| < 1, the wave is horizontally stretched, so cycles are longer.
Phase shift is the horizontal distance the graph has moved compared to the parent function. It equals dd. If d>0d > 0, the graph shifts to the right. If d<0d < 0, the graph shifts to the left. Remember to always factor first so that the inside of the brackets matches the form (x−d)(x - d) exactly.
Domain refers to all allowable input values, the xx-values. Because the sine and cosine functions accept any angle, the domain of every sinusoidal function studied in this course is all real numbers, written as x ∈ R\mathbb{R}. Transformations of type aa, kk, dd, and cc do not restrict which xx-values can be used.
Range refers to all possible output values, the yy-values. The midline sits at y=cy = c. The wave rises |a| units above the midline and falls |a| units below it. Therefore the minimum output value is c−∣a∣c - |a| and the maximum is c+∣a∣c + |a|.
Period=360°∣k∣\text{Period} = \frac{360°}{|k|}

Reading Features from a Graph

Sometimes you are given a graph instead of an equation, and you need to identify the features visually. Start by finding the maximum and minimum yy-values on the graph. The amplitude is half the distance between them. The midline, the value of cc, is the average of the maximum and minimum.
To find the period, locate two consecutive points where the wave is in the exact same position and moving in the same direction, for example, two successive peaks. Measure the horizontal distance between them; that distance is the period. To find the phase shift, compare where the first peak (or zero crossing) of the transformed graph occurs versus where it would occur on the parent function. The horizontal shift between those two positions is the phase shift.
Once you have the amplitude, period, and midline from the graph, you can work backwards to find aa, kk, dd, and cc, and then write the equation. This skill connects graphical and algebraic representations, which is a key goal of the course.
∣a∣=max−min2|a| = \frac{\text{max} - \text{min}}{2}

Putting It All Together: A Summary Strategy

When you encounter any sinusoidal equation, follow these four steps in order. First, factor the expression inside the brackets to match the form (x−d)(x - d), and read off kk and dd. Second, read aa and cc directly from the equation. Third, calculate amplitude as |a|, period as CAD 360° divided by |k|, and phase shift as dd. Fourth, state the domain as all real numbers and calculate the range using cc and |a|.
Keeping this sequence consistent prevents you from mixing up parameters. For instance, it stops you from confusing the vertical shift cc with the amplitude |a|, which is one of the most common errors. With practice, reading these five features from an equation will feel as natural as reading the slope and intercept from a linear function.
c−∣a∣≤y≤c+∣a∣c - |a| \leq y \leq c + |a|

Summary: Parameters in $y = a\sin(k(x-d)) + c$ and Their Effects

ParameterFeature It ControlsFormula or RuleExample ValueResult
aaAmplitude and reflection|a|a=−3a = -3Amplitude equals 33; graph reflected
kkPeriod360°∣k∣\frac{360°}{|k|}k=2k = 2Period equals CAD 180°
ddPhase shiftShift equals dd (factor first)d=30°d = 30°Graph moves CAD 30° right
ccVertical shift and midlineMidline at y=cy = cc=−2c = -2Midline at y=−2y = -2
aa and ccRangec−∣a∣≤y≤c+∣a∣c - |a| \leq y \leq c + |a|a=3, c=1a = 3,\ c = 1−2≤y≤4-2 \leq y \leq 4

Worked example

Example 1 — Reading Features from an Equation

For the function y=−4sin⁡(3(x−20°))+1y = -4\sin(3(x - 20°)) + 1, determine the amplitude, period, phase shift, domain, and range.
  1. Identify the parameters
    Match the equation to the general form y=asin⁡(k(x−d))+cy = a\sin(k(x - d)) + c. The equation is already factored correctly inside the brackets, so you can read the parameters directly.
    a=−4, k=3, d=20°, c=1a = -4,\ k = 3,\ d = 20°,\ c = 1
  2. Calculate the amplitude
    Amplitude equals the absolute value of aa. The negative sign on aa tells you the graph is reflected over the midline (the wave goes down first instead of up), but it does not change the height of the wave.
    Amplitude=∣−4∣=4\text{Amplitude} = |-4| = 4
  3. Calculate the period
    Divide CAD 360°by by |k|. Here ∣k∣=3|k| = 3, so one full cycle is compressed, meaning the wave repeats three times in the space where the parent function repeats once.
    Period=360°3=120°\text{Period} = \frac{360°}{3} = 120°
  4. State the phase shift
    The phase shift equals dd. Because d=20°d = 20° is positive, the entire graph has shifted to the right compared to y=−4sin⁡(3x)+1y = -4\sin(3x) + 1.
    Phase shift=20° right\text{Phase shift} = 20°\ \text{right}
  5. State the domain
    Sine accepts any real-number input, and none of the parameters restricts the xx-values. The domain is all real numbers, written x ∈ R\mathbb{R}.
  6. Calculate the range
    The midline is at y=c=1y = c = 1. The wave travels ∣a∣=4|a| = 4 units above and below that midline. So the minimum output is 1−4=−31 - 4 = -3 and the maximum is 1+4=51 + 4 = 5.
    −3≤y≤5-3 \leq y \leq 5
Answer: Amplitude equals 44; period equals CAD 120°; phase shift equals CAD 20° to the right; domain is x ∈ R\mathbb{R}; range is −3≤y≤5-3 \leq y \leq 5.
Check: Verify the range: midline at y=1y = 1, amplitude 44. Maximum equals 1+4=51 + 4 = 5, correct. Minimum equals 1−4=−31 - 4 = -3, correct. Verify the period: 360°3=120°\frac{360°}{3} = 120°, correct.

Worked example

Example 2 — Factoring First, Then Finding Features

For the function y=2cos⁡(4x−60°)+3y = 2\cos(4x - 60°) + 3, determine the amplitude, period, phase shift, domain, and range.
  1. Factor the inside of the brackets
    The expression inside the cosine is 4x−60°4x - 60°. This is not yet in the form k(x−d)k(x - d). Factor out the 44 from both terms inside to get 4(x−15°)4(x - 15°). Now the equation can be rewritten in proper general form. This step is essential; if you skip it, you would incorrectly read the phase shift as CAD 60° instead of the correct CAD 15°.
    y=2cos⁡(4(x−15°))+3y = 2\cos(4(x - 15°)) + 3
  2. Identify the parameters
    Now match to y=acos⁡(k(x−d))+cy = a\cos(k(x - d)) + c. Read off each parameter from the rewritten equation.
    a=2, k=4, d=15°, c=3a = 2,\ k = 4,\ d = 15°,\ c = 3
  3. Calculate the amplitude
    Amplitude equals |a|. The coefficient aa is positive, so the graph is not reflected; it starts at its maximum when x=dx = d.
    Amplitude=∣2∣=2\text{Amplitude} = |2| = 2
  4. Calculate the period
    Divide CAD 360°by by |k|, where ∣k∣=4|k| = 4. The wave completes one full cycle every CAD 90°.
    Period=360°4=90°\text{Period} = \frac{360°}{4} = 90°
  5. State the phase shift
    The phase shift equals d=15°d = 15°. Because dd is positive, the graph has moved to the right. If you had not factored and mistakenly used CAD 60°, your sketch would be off by a significant amount, which is a good reason to always factor first.
    Phase shift=15° right\text{Phase shift} = 15°\ \text{right}
  6. State the domain
    Cosine accepts every real-number input, and no parameter here restricts the xx-values. The domain is all real numbers, written x ∈ R\mathbb{R}.
  7. Calculate the range
    The midline is y=c=3y = c = 3. The amplitude is 22, so the wave reaches as high as 3+2=53 + 2 = 5 and as low as 3−2=13 - 2 = 1.
    1≤y≤51 \leq y \leq 5
Answer: Amplitude equals 22; period equals CAD 90°; phase shift equals CAD 15° to the right; domain is x ∈ R\mathbb{R}; range is 1≤y≤51 \leq y \leq 5.
Check: Verify factoring: 4(x−15°)=4x−60°4(x - 15°) = 4x - 60°, correct. Verify range: 3−2=13 - 2 = 1 and 3+2=53 + 2 = 5, correct. Verify period: 360°4=90°\frac{360°}{4} = 90°, correct.

Common mistakes and how to avoid them

Reading the phase shift directly from kx−dkx - d without factoring out kk first, giving a phase shift that is kk times too large.
Correction: Always factor the expression inside the brackets into the form k(x−d)k(x - d) before identifying dd. For 4x−60°4x - 60°, factor to get 4(x−15°)4(x - 15°), so the phase shift is CAD 15°, not CAD 60°.
Using a negative value for amplitude, for example writing amplitude equals −4-4 when a=−4a = -4.
Correction: Amplitude is always a positive number, equal to |a|. The negative sign means the wave is reflected, but amplitude still equals ∣−4∣=4|-4| = 4.
Confusing the vertical shift cc with the amplitude |a|, especially when calculating the range.
Correction: The amplitude tells you how far the wave moves above and below the midline. The midline itself is at y=cy = c. The range runs from c−∣a∣c - |a| to c+∣a∣c + |a|.
Stating the period as CAD 360° multiplied by |k| instead of divided.
Correction: A larger |k| compresses the wave, making the period shorter. The correct formula divides CAD 360°by by |k|.
Thinking the domain changes when vertical or horizontal shifts are applied.
Correction: For sine and cosine functions, transformations of type aa, kk, dd, and cc never restrict the xx-values. The domain remains all real numbers regardless of the transformation.

Lesson summary

Check your understanding

Question 1

What is the amplitude of y=−5sin⁡(2(x−10°))+4y = -5\sin(2(x - 10°)) + 4?
  1. -5
  2. 5
  3. 4
  4. 2
Show answer and explanation
5
Amplitude equals ∣a∣=∣−5∣=5|a| = |-5| = 5. The negative sign reflects the graph but does not affect the amplitude, which is always a positive value.

Question 2

What is the period of y=3cos⁡(12(x+30°))−1y = 3\cos\left(\frac{1}{2}(x + 30°)\right) - 1?
  1. 180°
  2. 720°
  3. 360°
  4. 90°
Show answer and explanation
720°
Period equals CAD 360° divided by ∣k∣=12|k| = \frac{1}{2}, which gives 360°×2=720°360° \times 2 = 720°. Because ∣k∣<1|k| < 1, the period is longer than the parent function's CAD 360°.

Question 3

A student writes the phase shift of y=sin⁡(3x−90°)y = \sin(3x - 90°) as CAD 90° to the right. What went wrong?
  1. The student forgot to take the absolute value of kk.
  2. The student did not factor out k=3k = 3 first, so the phase shift should be CAD 30° to the right.
  3. The student confused sine and cosine.
  4. The student used the wrong period formula.
Show answer and explanation
The student did not factor out k=3k = 3 first, so the phase shift should be CAD 30° to the right.
Factoring correctly: 3x−90°=3(x−30°)3x - 90° = 3(x - 30°), so d=30°d = 30°. The phase shift is CAD 30° to the right, not CAD 90°. Skipping the factoring step produced an answer three times too large.

Question 4

What is the range of y=6cos⁡(x−45°)−2y = 6\cos(x - 45°) - 2?
  1. −6≤y≤6-6 \leq y \leq 6
  2. −8≤y≤4-8 \leq y \leq 4
  3. 2≤y≤82 \leq y \leq 8
  4. −2≤y≤6-2 \leq y \leq 6
Show answer and explanation
−8≤y≤4-8 \leq y \leq 4
Here ∣a∣=6|a| = 6 and c=−2c = -2. Minimum equals c−∣a∣=−2−6=−8c - |a| = -2 - 6 = -8 and maximum equals c+∣a∣=−2+6=4c + |a| = -2 + 6 = 4. Range: −8≤y≤4-8 \leq y \leq 4.

Key terms

Sinusoidal function
A function whose graph has the repeating wave shape of sine or cosine.
Amplitude
The positive distance from the midline of a sinusoidal wave to its maximum (or minimum) value; equal to |a|.
Period
The horizontal length, in degrees, of one complete cycle of a sinusoidal function; equal to CAD 360° divided by |k|.
Phase shift
The horizontal distance a sinusoidal graph has moved left or right compared to the parent function; equal to dd after factoring.
Midline
The horizontal line y=cy = c that runs through the vertical centre of a sinusoidal wave, halfway between its maximum and minimum.
Domain
The complete set of allowable input (xx) values for a function. For all sinusoidal functions in this course, the domain is all real numbers, written x ∈ R\mathbb{R}.
Range
The complete set of possible output (yy) values for a function. For a sinusoidal function, the range is c−∣a∣≤y≤c+∣a∣c - |a| \leq y \leq c + |a|.
Vertical shift
The value cc in the general form; it moves the entire graph up (if c>0c > 0) or down (if c<0c < 0) and sets the position of the midline.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 11 Mathematics (MCR3U), expectation D2.6. It is a study resource, not an official curriculum publication.

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