Learn to interpret normal distributions, standard deviation, and z-scores through clear examples and targeted practice.
Alberta Grade 11 Mathematics
Statistics
Mathematics 20-2 — Study topic S1
Suppose the times students take to complete a familiar task are recorded. Most times may be close to the average, while fewer are much shorter or much longer. A normal distribution is a model that represents this kind of pattern. In this lesson, you will learn to read its shape, interpret its standard deviation, and use a z-score to describe how far an observation is from the mean. The examples use hypothetical data.
What you will learn
Describe the main features of a normal distribution.
Interpret standard deviation as a measure of spread around a mean.
Use the 68–95–99.7 rule to interpret approximate proportions in a normal distribution.
Interpret a z-score as the number of standard deviations an observation is from the mean.
1. Review: mean, data, and units
A data set is a collection of recorded values. The mean is the average: add the values and divide by how many values there are. For example, if the mean time for a task is 12 minutes, then 12 minutes is the balance point of the data. It does not mean every person took exactly 12 minutes.
A unit tells what a value measures, such as minutes, centimetres, or points. When comparing an observation with a mean, both values must use the same unit. The difference between them is also measured in that unit.
A distribution describes how data values are spread and how often values occur. A graph of a distribution can help you see whether values cluster near the centre or are spread widely.
The mean describes the data's average value.
Compare values only when they use the same units.
2. Recognizing a normal distribution
A normal distribution is a smooth, bell-shaped pattern. It is symmetric, which means its left and right sides have the same shape around the centre. In a normal distribution, the mean is at the centre. Values near the mean are more common, and values farther from the mean are less common.
The curve shows relative frequency: a taller part of the curve represents values that are more concentrated in that region. The curve does not say that every data set will match the model exactly. It is a way to describe a distribution that is approximately bell-shaped and symmetric.
The standard deviation, written as s or σ, describes the typical distance of values from the mean. A small standard deviation means values tend to stay closer to the mean. A larger standard deviation means they tend to be more spread out. Standard deviation uses the same unit as the data.
For a normal distribution, the 68–95–99.7 rule gives useful approximate proportions. About 68% of values are within one standard deviation of the mean. About 95% are within two standard deviations. About 99.7% are within three standard deviations. These are approximations, not exact counts for every data set.
On a normal curve, the intervals are centred on the mean. For example, if the mean is 12 minutes and the standard deviation is 2 minutes, one standard deviation below and above the mean gives 10 to 14 minutes. About 68% of values are expected in that interval if the model is appropriate.
about 68%:μ±σ,95%:μ±2σ,99.7%:μ±3σ
A normal curve is symmetric and bell-shaped, with its mean at the centre.
Standard deviation describes spread in the data's units.
The 68–95–99.7 rule describes approximate proportions within one, two, and three standard deviations.
3. Interpreting a z-score
A z-score describes an observation's position relative to the mean. It tells how many standard deviations the observation is above or below the mean. A positive z-score is above the mean. A negative z-score is below the mean. A z-score of zero is exactly at the mean.
To find a z-score, subtract the mean from the observation, then divide by the standard deviation. The subtraction gives the observation's distance from the mean. Dividing by the standard deviation expresses that distance in standard-deviation units. The result has no unit.
For example, a z-score of 1.5 means the observation is 1.5 standard deviations above the mean. A z-score of −2 means it is 2 standard deviations below the mean. In a normal distribution, observations farther from zero are farther from the centre and are less common than observations near the mean.
A z-score helps compare positions in different data sets. For instance, being 6 points above a mean may be unusual in one set and ordinary in another. The z-score takes each set's standard deviation into account.
z=σx−μ
The sign tells whether the observation is above or below the mean.
The absolute value tells how many standard deviations away it is.
A z-score has no units.
4. Read the value, then check its meaning
When interpreting a normal distribution, first identify the mean and standard deviation. Then locate the observation or interval in relation to the mean. If you calculate a z-score, explain its sign and size in words.
Check that the result makes sense. An observation above the mean must have a positive z-score. One below the mean must have a negative z-score. If an observation is only a little different from the mean, its z-score should be close to zero. If the observation is several standard deviations away, the z-score should have a larger absolute value.
Do not treat the 68–95–99.7 rule as a guarantee about a particular sample. It describes approximate proportions when a normal model is suitable. Also, standard deviation is not the same as the mean: the mean marks the centre, while standard deviation describes spread.
State the meaning of a z-score in context, including above or below the mean.
Use the normal-rule percentages as approximations.
Check the sign and size against the observation's position.
Worked example
Interpreting the centre and spread
Hypothetical quiz scores are approximately normally distributed, with a mean of 72 points and a standard deviation of 6 points. Interpret the mean, standard deviation, and the interval within one standard deviation of the mean.
Hypothetical quiz-score distribution
The highlighted value is 78 points, one standard deviation above the mean of 72 points.
Identify the centre
The mean is the centre of this normal distribution. A score of 72 points is the average, not a score that every student received.
μ=72 points
Interpret the spread
The standard deviation is 6 points. Scores commonly differ from the mean by a distance measured in points; the standard deviation describes the distribution's spread.
σ=6 points
Find the one-standard-deviation interval
One standard deviation below the mean is 72 minus 6, and one above is 72 plus 6. About 68% of scores are expected in this interval if the normal model is suitable.
72−6=66,72+6=78
Answer: The mean is 72 points, and the standard deviation is 6 points. About 68% of scores are expected to lie from 66 to 78 points.
Check: The interval is centred on 72, and each endpoint is 6 points from the mean.
Worked example
Finding and interpreting a z-score
Hypothetical travel times for a school bus route are approximately normally distributed, with a mean of 24 minutes and a standard deviation of 3 minutes. Interpret the z-score for a trip that takes 30 minutes.
Hypothetical bus travel times
The highlighted travel time of 30 minutes is two standard deviations above the mean of 24 minutes.
Compare with the mean
The trip took 6 minutes longer than the mean. This difference is positive because the observation is above the mean.
30−24=6 minutes
Measure the difference in standard deviations
Divide the 6-minute difference by the standard deviation of 3 minutes. The units cancel, leaving a z-score with no unit.
z=330−24=2
Interpret the result
The positive sign means the trip time is above the mean. The value 2 means it is two standard deviations above the mean. In a normal distribution, that is farther from the centre than most values.
z=2
Answer: The trip time has a z-score of 2. It is two standard deviations above the mean.
Check: A time above the mean should have a positive z-score. The difference of 6 minutes is exactly two 3-minute standard deviations.
Worked example
Interpreting a negative z-score
Hypothetical package weights are approximately normally distributed, with a mean of 500 grams and a standard deviation of 20 grams. A package weighs 470 grams. Find and interpret its z-score, and use the 68–95–99.7 rule to describe how its position compares with the central data.
Hypothetical package weights
The highlighted value of 470 grams is 1.5 standard deviations below the mean of 500 grams.
Find the difference from the mean
The package is lighter than the mean, so subtracting the mean gives a negative difference.
470−500=−30 grams
Calculate the z-score
Divide the difference by the standard deviation. Both quantities are in grams, so the units cancel.
z=20470−500=−1.5
Connect the score to the normal model
The package is 1.5 standard deviations below the mean. It lies outside the interval within one standard deviation, but inside the interval within two standard deviations. About 68% of values are within one standard deviation and about 95% within two, so the package is in the broader outer portion between those intervals, not beyond two standard deviations.
500−2(20)=460,500−20=480
Answer: The z-score is −1.5. The package is 1.5 standard deviations below the mean. It is outside the central one-standard-deviation interval but within the two-standard-deviation interval.
Check: The weight is below 500 grams, so the score is negative. Its distance of 30 grams is greater than 20 grams but less than 40 grams.
Common mistakes and how to avoid them
Saying the standard deviation is the average value.
Correction: The mean is the average and centre. Standard deviation describes how spread out values are around the mean.
Giving a positive z-score for an observation below the mean.
Correction: Subtract the mean from the observation. A value below the mean gives a negative difference and a negative z-score.
Including units in a z-score.
Correction: The observation-minus-mean difference and standard deviation use the same units. Dividing cancels those units.
Treating the 68–95–99.7 rule as an exact count.
Correction: These percentages are approximate and apply when the distribution is well represented by a normal model.
Lesson summary
A normal distribution is approximately symmetric and bell-shaped, with the mean at its centre.
Standard deviation describes spread and uses the same unit as the data.
About 68%, 95%, and 99.7% of values lie within one, two, and three standard deviations of the mean, respectively.
A z-score gives an observation's distance from the mean in standard-deviation units: positive is above, negative is below.
Check your understanding
Question 1
A normal distribution has mean 40 and standard deviation 5. What does a value with z-score −2 mean?
It is 2 units below the mean.
It is 2 standard deviations below the mean.
It is 2 standard deviations above the mean.
It is equal to the mean.
Show answer and explanation
It is 2 standard deviations below the mean.
A z-score measures distance in standard deviations. The negative sign means below the mean.
Question 2
A distribution has mean 18 and standard deviation 4. Which interval contains about 68% of the values if the distribution is normal?
From 14 to 22
From 10 to 26
From 6 to 30
From 18 to 22
Show answer and explanation
From 14 to 22
About 68% lie within one standard deviation of the mean: 18 minus 4 to 18 plus 4, or 14 to 22.
Question 3
A measurement of 27 comes from a distribution with mean 30 and standard deviation 3. What is its z-score?
1
−1
3
−3
Show answer and explanation
−1
Subtract the mean and divide by the standard deviation: (27 − 30) ÷ 3 = −1. The measurement is one standard deviation below the mean.
Key terms
Distribution
A description of the values in data and how often they occur.
Normal distribution
A symmetric, bell-shaped model in which values near the mean are more common than values far from it.
Mean
The average of a set of values.
Standard deviation
A measure of how spread out values are around the mean.
z-score
A value that states how many standard deviations an observation is above or below the mean.
Tutor support for S1 · Interpret normal distributions, standard deviation, and z-scores
Working on S1 · Interpret normal distributions, standard deviation, and z-scores in Math 20-2? Bring the question and your own attempt. In a live session, you can identify the data and assumptions, choose a suitable representation, and interpret the result in context. Ask about the first step that does not make sense, then try a similar question yourself.
برای مبحث S1 · توزیع نرمال، انحراف معیار و نمرهٔ z را تفسیر کنید در درس Math 20-2، سؤال و تلاش خود را همراه بیاورید. در جلسه میتوانید دادهها و فرضها را مشخص کنید، نمایش مناسبی برگزینید و نتیجه را در متن مسئله تفسیر کنید. راهنمای معلم ریاضی را ببینید یا جلسهٔ معارفهٔ رایگان ۳۰ دقیقهای درخواست کنید. زمان جلسه پس از پذیرش معلم قطعی میشود.
About this lesson and its review
Published by DoAssignment. This reviewed lesson follows Alberta Grade 11 Mathematics (Math 20-2), expectation S1. It is a study resource, not an official curriculum publication.
Before publication, content is checked for structure, mathematical or chemical notation, calculations, course boundaries, and readability. Errors can still occur, so corrections are welcomed.