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A3 · Solve proportional problems using unit analysis

Learn to solve proportional problems using unit analysis through clear examples and targeted practice.

Alberta Grade 11 Mathematics

Algebra

Use units to choose operations, convert measurements, and check whether an answer makes sense.

A proportional problem links two quantities that change at a steady rate. For example, if a machine fills the same number of bottles each minute, more minutes mean more bottles. Unit analysis is a way to organize the numbers and units in a calculation. The units help show which operation to use and whether the answer has the kind of measurement the question asks for.

What you will learn

  • Identify the units in a proportional problem and decide which units the answer needs.
  • Use a rate and multiplication or division to solve for an unknown amount.
  • Convert measurements by multiplying by a conversion factor that equals one.
  • Check that units cancel correctly and that the answer is reasonable.

Start with the units

A unit tells what a number measures. Examples include kilometres, hours, litres, and boxes. A rate compares two measurements, such as kilometres per hour. The word “per” means “for each” or “divided by.” Thus, a rate of 60 kilometres per hour can be written as 60 km/h.
Before calculating, name the quantity you need to find. Then write its unit. If a question asks for the time needed to travel 150 km at 50 km/h, the answer must be in hours. Dividing distance by speed gives hours because the kilometre units cancel.
A proportional relationship has a constant rate: each equal-sized change in one quantity matches the same-sized change in the other. If a worker packs 28 boxes each hour, the number of boxes is the hourly rate multiplied by the time worked. This method assumes the worker keeps the same pace.
rate=quantitytime\text{rate}=\frac{\text{quantity}}{\text{time}}
  • Write down the known quantities with their units.
  • Write the unit required for the answer before choosing an operation.
  • Use the meaning of the rate to decide whether to multiply or divide.

Use unit analysis to set up a calculation

Unit analysis means tracking units through a calculation. When multiplying, units multiply too. When dividing, units divide. Matching units can cancel: kilometres divided by kilometres leave no distance unit, while kilometres divided by kilometres per hour leave hours.
A conversion factor is a fraction made from two equal measurements in different units. For example, 1 km and 1000 m describe the same distance. The fractions 1000 m / 1 km and 1 km / 1000 m therefore both equal one. Choose the version that cancels the unit you do not want.
For example, to change 3.2 km into metres, multiply by 1000 m / 1 km. The km units cancel, leaving metres. A conversion factor does not change the size of the measurement; it changes how that measurement is written.
Sometimes a problem has more than one step. Keep the units in each step. If the final unit is not the unit asked for, check the setup before trusting the number. Round only when needed, and keep enough digits during the calculation to avoid changing the result too much.
3.2 km×1000 m1 km=3200 m3.2\,\text{km}\times\frac{1000\,\text{m}}{1\,\text{km}}=3200\,\text{m}
  • Choose a conversion factor that cancels the unwanted unit.
  • Units that appear once above and once below a fraction can cancel.
  • A correct number with the wrong unit is not a complete answer.

Check the answer

After calculating, read the answer with its unit and compare it with the situation. A distance travelled in a few minutes should not come out as thousands of kilometres. A useful check is to estimate: round the numbers to values that are easy to use, then see whether the exact answer is close.
Pay attention to the direction of a conversion. Since a kilometre contains 1000 metres, a distance written in metres should have a larger number than the same distance written in kilometres. For a rate problem, check whether the answer should increase or decrease. More time at a steady positive rate should produce more output.
In the examples, the figures are hypothetical practice situations, not claims about current prices, wages, or other real-world rates. Each rate is given in the question so it can be checked and used.
  • State the answer with the requested unit.
  • Use an estimate and the situation to check the size of the answer.
  • Check whether the answer changes in the expected direction.

Worked example

Find a travel time

A delivery van travels 150 km at a steady speed of 50 km/h. How long does the trip take? Treat the given speed as the rate for the whole trip.
  1. Choose the answer unit
    The question asks how long the trip takes, so the answer should be in hours. The given rate is 50 kilometres for each hour.
    50 km/h50\,\text{km/h}
  2. Divide distance by rate
    Dividing the distance by the speed gives the time. In the units, km divided by km/h leaves h, which confirms that the setup gives time.
    150 km÷50 km/h=3 h150\,\text{km}\div 50\,\text{km/h}=3\,\text{h}
  3. Check the result
    At 50 km each hour, three hours covers 150 km. The answer has the requested unit and matches the situation.
    50 km/h×3 h=150 km50\,\text{km/h}\times 3\,\text{h}=150\,\text{km}
Answer: The trip takes 3 hours.
Check: The units reduce to hours, and the distance check returns 150 km.

Worked example

Convert a map measurement

On a hypothetical scale plan, a path measures 3.2 cm. The scale is 1:2500, meaning 1 cm on the plan represents 2500 cm in real life. Find the real distance in metres.
Path on a scale plan
3.2 cm on plan8000 cm in realityScale 1 : 2500Drawn lengths are schematic, not a shared scale.

A 3.2 cm plan length represents 80 m at a scale of 1:2500.

  1. Use the scale
    Each centimetre on the plan represents 2500 centimetres in reality. Multiply the plan length by this real-distance amount per plan centimetre. The plan centimetres cancel.
    3.2 cm×2500 cm1 cm=8000 cm3.2\,\text{cm}\times\frac{2500\,\text{cm}}{1\,\text{cm}}=8000\,\text{cm}
  2. Convert to metres
    The conversion factor is provided: 100 cm equals 1 m. Use the fraction with centimetres below so those units cancel and metres remain.
    8000 cm×1 m100 cm=80 m8000\,\text{cm}\times\frac{1\,\text{m}}{100\,\text{cm}}=80\,\text{m}
  3. Check the size
    A plan length of a little over 3 cm represents 8000 cm, or 80 m, at this scale. The result is larger than the plan measurement because the plan is a reduced drawing.
    8000 cm=80 m8000\,\text{cm}=80\,\text{m}
Answer: The real distance is 80 m.
Check: The centimetres cancel at each conversion, leaving metres. The scale calculation is 3.2 times 2500 cm, or 8000 cm.

Worked example

Find production over part of a shift

In a hypothetical packing task, a worker packs 84 boxes in 3 hours at a steady rate. How many boxes can the worker pack in 6.5 hours at that rate?
  1. Find the hourly rate
    Divide the number of boxes by the hours. This gives boxes per hour, the rate needed for the next step.
    84 boxes÷3 h=28 boxes/h84\,\text{boxes}\div 3\,\text{h}=28\,\text{boxes/h}
  2. Scale the rate to the time
    Multiply the hourly rate by 6.5 hours. The hour units cancel, leaving boxes.
    28 boxes/h×6.5 h=182 boxes28\,\text{boxes/h}\times 6.5\,\text{h}=182\,\text{boxes}
  3. Check against the rate
    Six and a half hours is a little more than six hours. At 28 boxes per hour, the result should be a little more than 168 boxes. The calculated 182 boxes fits that estimate.
    28 boxes/h×6 h=168 boxes28\,\text{boxes/h}\times 6\,\text{h}=168\,\text{boxes}
Answer: The worker can pack 182 boxes in 6.5 hours at the stated steady rate.
Check: The answer is a whole number of boxes, and its unit is boxes. It is greater than the six-hour estimate because the time is longer than six hours.

Common mistakes and how to avoid them

Multiplying the distance by the speed when the question asks for travel time.
Correction: Divide distance by speed. Check that km divided by km/h leaves hours.
Using a conversion factor in the direction that makes the unwanted unit remain.
Correction: Write the units in the conversion fraction and choose the order that cancels the unit you are changing from.
Giving only a number and leaving off the unit.
Correction: Include the unit in the final answer. Use unit cancellation to check that it matches the question.

Lesson summary

  • A rate compares quantities, often as an amount per unit of time.
  • Set up the calculation so units cancel and the requested unit remains.
  • Use conversion factors made from equal measurements.
  • Estimate and check whether the answer is reasonable for the situation.

Check your understanding

Question 1

A printer makes 36 labels in 4 minutes at a steady rate. How many labels does it make per minute?
  1. 9 labels/min
  2. 32 labels/min
  3. 144 labels/min
  4. correctIndex: 0,
Show answer and explanation
9 labels/min
Divide 36 labels by 4 minutes. The units become labels per minute, and 36 divided by 4 is 9.

Question 2

Convert 2.4 km to metres using 1000 m = 1 km. Which calculation has the correct unit setup?
  1. 2.4 km×1000 m1 km2.4\,\text{km}\times\frac{1000\,\text{m}}{1\,\text{km}}
  2. 2.4 km×1 km1000 m2.4\,\text{km}\times\frac{1\,\text{km}}{1000\,\text{m}}
  3. 2.4 km÷1000 m2.4\,\text{km}\div 1000\,\text{m}
  4. correctIndex: 0,
Show answer and explanation
2.4 km×1000 m1 km2.4\,\text{km}\times\frac{1000\,\text{m}}{1\,\text{km}}
The first fraction cancels km and leaves metres. It gives 2400 m.

Question 3

A cyclist travels at 18 km/h for 2.5 hours. How far does the cyclist travel at that steady speed?
  1. 7.2 km
  2. 20.5 km
  3. 45 km
  4. correctIndex: 2,
Show answer and explanation
45 km
Multiply speed by time. Hours cancel, leaving kilometres: 18 times 2.5 equals 45.

Key terms

Unit
A label that tells what a number measures, such as hours or metres.
Rate
A comparison of quantities measured in different units, such as boxes per hour.
Unit analysis
Tracking units through a calculation to help choose operations and check the answer.
Conversion factor
A fraction made from two equal measurements in different units, used to rewrite a measurement.
Proportional relationship
A relationship in which one quantity changes at a steady rate compared with another.

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Published by DoAssignment. This reviewed lesson follows Alberta Grade 11 Mathematics (Math 20-3), expectation A3. It is a study resource, not an official curriculum publication.

Before publication, content is checked for structure, mathematical or chemical notation, calculations, course boundaries, and readability. Errors can still occur, so corrections are welcomed.

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