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RF8 · Use the product, quotient, and power laws of logarithms

Learn to use the product, quotient, and power laws of logarithms through clear examples and targeted practice.

Alberta Grade 12 Mathematics

Relations and Functions

Expand and condense logarithmic expressions accurately

Logarithm laws provide ways to rewrite expressions while preserving their values. Multiplication inside a logarithm can become addition outside it. Division can become subtraction. An exponent on a positive argument can become a coefficient. These laws are useful for both expanding an expression into several logarithms and condensing several logarithms into one. The arguments must satisfy the conditions for the original logarithms to be defined, and the logarithms being combined must have the same base.

What you will learn

  • Use the product law to expand a logarithm of a product.
  • Use the quotient law to expand a logarithm of a quotient.
  • Use the power law to move an exponent between an argument and a coefficient.
  • Condense sums and differences of logarithms with the same base.
  • State the variable restrictions needed for the original logarithms to be defined.

1. The three laws

First, recall that the argument is the quantity inside a logarithm. For example, in log⁡5(3x)\log_5(3x), the argument is 3x3x. For the logarithm to be defined in real-number work, its argument must be positive. This is the restriction we will check when variables appear.
The product law applies when the argument is a product of positive quantities. It changes one logarithm into the sum of two logarithms with the same base. For example, multiplying two positive quantities inside one logarithm corresponds to adding their logarithms.
The quotient law applies to a quotient whose numerator and denominator are positive. It changes one logarithm into the numerator's logarithm minus the denominator's logarithm. The order matters: the numerator comes first.
The power law applies when the argument being raised to a power is positive. It moves that exponent in front of the logarithm as a coefficient. In this lesson, an exponent may be an integer, including a negative integer, when the original power is defined. A negative exponent requires a nonzero base.
Each law works in reverse as well. This lets you expand a single logarithm or condense a sum or difference of logarithms. Always keep the base unchanged when applying these laws.
log⁡b(MN)=log⁡bM+log⁡bN,log⁡b(MN)=log⁡bM−log⁡bN,log⁡b(Mr)=rlog⁡bM\log_b(MN)=\log_b M+\log_b N,\quad \log_b\left(\frac{M}{N}\right)=\log_b M-\log_b N,\quad \log_b(M^r)=r\log_b M
  • Product inside becomes addition outside.
  • Quotient inside becomes subtraction outside.
  • An exponent on a positive argument becomes a coefficient.
  • The logarithms being combined must have the same base.

2. Choosing a law and checking restrictions

Look at the structure of the argument before choosing a law. A product has factors multiplied together, so use the product law. A quotient has a numerator divided by a denominator, so use the quotient law. A power has an exponent on an argument, so use the power law.
For example, log⁡3(2(x−1))\log_3(2(x-1)) has a product in its argument. If the original logarithm is defined, then 2(x−1)>02(x-1)>0, which requires x>1x>1. Splitting it gives log⁡32+log⁡3(x−1)\log_3 2+\log_3(x-1), and the second argument is positive under the same restriction.
A sum inside an argument is not a product. There is no product law that splits log⁡b(M+N)\log_b(M+N) into two logarithms. Likewise, a difference between two logarithms can be condensed by the quotient law, but a sum of logarithms is condensed using the product law.
Restrictions come from the original expression, not just from the final rewritten form. Check that every logarithm you write has a positive argument. If a variable occurs in a denominator, also check that the denominator is not zero. Rewriting does not make an originally undefined expression valid.
  • Identify multiplication, division, or an exponent before selecting a law.
  • Check the positivity of each logarithm argument.
  • Do not split a logarithm of a sum or difference.

3. A compact reference and a reliable process

The table gives both directions for each law. The left-to-right direction is useful when expanding. The right-to-left direction is useful when condensing.
For an expansion, first state the restriction, then separate products or quotients, and finally move powers to coefficients. For condensing, first move coefficients to exponents, then combine sums with the product law and differences with the quotient law.
After rewriting, compare the domain of the result with the domain of the original expression. The rewritten form should represent the original expression only where the original expression is defined.
  • Expand products and quotients before moving powers when that makes the structure clear.
  • When condensing, coefficients become exponents before logarithms are combined.
  • Keep domain restrictions with your final answer.

Expand and condense

StructureExpandCondense
Productlog⁡b(MN)=log⁡bM+log⁡bN\log_b(MN)=\log_b M+\log_b Nlog⁡bM+log⁡bN=log⁡b(MN)\log_b M+\log_b N=\log_b(MN)
Quotientlog⁡b(MN)=log⁡bM−log⁡bN\log_b\left(\frac{M}{N}\right)=\log_b M-\log_b Nlog⁡bM−log⁡bN=log⁡b(MN)\log_b M-\log_b N=\log_b\left(\frac{M}{N}\right)
Powerlog⁡b(Mr)=rlog⁡bM\log_b(M^r)=r\log_b Mrlog⁡bM=log⁡b(Mr)r\log_b M=\log_b(M^r)

Worked example

Expand a product and a power

Expand log⁡5(25x3)\log_5(25x^3) using logarithm laws. State the restriction on xx.
  1. Check the original argument
    The argument must be positive. Since 25 is positive, the condition 25x3>025x^3>0 requires x>0x>0.
    25x3>0⇒x>025x^3>0\Rightarrow x>0
  2. Separate the product
    The argument is the product of 25 and x3x^3. The product law changes this logarithm into a sum.
    log⁡5(25x3)=log⁡525+log⁡5(x3)\log_5(25x^3)=\log_5 25+\log_5(x^3)
  3. Apply the power law
    The power law moves the exponent 3 in front of the second logarithm. Since 25=5225=5^2, its logarithm is 2.
    2+3log⁡5x2+3\log_5 x
Answer: 2+3log⁡5x2+3\log_5 x, for x>0x>0.
Check: If x=1x=1, the original expression is log⁡525=2\log_5 25=2. The expanded expression is 2+3log⁡51=22+3\log_5 1=2, so the values agree.

Worked example

Condense a difference with a coefficient

Write 2log⁡4(x+1)−log⁡432\log_4(x+1)-\log_4 3 as one logarithm. State its restriction.
  1. Find the restriction
    The argument x+1x+1 must be positive, so x>−1x>-1. The other argument, 3, is already positive.
    x+1>0⇒x>−1x+1>0\Rightarrow x>-1
  2. Move the coefficient into the argument
    Use the power law in reverse. The coefficient 2 becomes an exponent on the positive argument x+1x+1.
    2log⁡4(x+1)=log⁡4((x+1)2)2\log_4(x+1)=\log_4((x+1)^2)
  3. Combine the difference
    The quotient law combines a difference of logarithms with the same base into the logarithm of a quotient.
    log⁡4((x+1)23)\log_4\left(\frac{(x+1)^2}{3}\right)
Answer: log⁡4((x+1)23)\log_4\left(\frac{(x+1)^2}{3}\right), for x>−1x>-1.
Check: For x>−1x>-1, the original argument x+1x+1 is positive. The condensed argument is also positive because its numerator is a positive square and its denominator is positive.

Worked example

Expand a quotient and powers

Expand log⁡2(a2b3)\log_2\left(\frac{a^2}{b^3}\right), given a>0a>0 and b>0b>0.
  1. Check the given restrictions
    Because a>0a>0 and b>0b>0, both powers are positive and the original quotient is positive. The logarithm is defined.
    a2>0,b3>0a^2>0,\quad b^3>0
  2. Apply the quotient law
    The quotient law changes the logarithm of the fraction into the logarithm of the numerator minus the logarithm of the denominator.
    log⁡2(a2)−log⁡2(b3)\log_2(a^2)-\log_2(b^3)
  3. Apply the power law
    Both arguments are positive, so move each exponent in front of its logarithm as a coefficient.
    2log⁡2a−3log⁡2b2\log_2 a-3\log_2 b
Answer: 2log⁡2a−3log⁡2b2\log_2 a-3\log_2 b, given a>0a>0 and b>0b>0.
Check: For example, if a=2a=2 and b=2b=2, the original expression is log⁡2(4/8)=−1\log_2(4/8)=-1. The expanded expression is 2(1)−3(1)=−12(1)-3(1)=-1.

Common mistakes and how to avoid them

Writing log⁡b(M+N)=log⁡bM+log⁡bN\log_b(M+N)=\log_b M+\log_b N.
Correction: The product law applies to multiplication, not addition. Do not split a logarithm of a sum.
Combining logarithms that have different bases.
Correction: Use the product, quotient, and power laws only with logarithms of the same base.
Forgetting a positivity restriction when a variable is in an argument.
Correction: Check the original argument before rewriting, and state the restrictions that make it positive.
Changing the order when condensing a difference.
Correction: The first logarithm becomes the numerator and the second becomes the denominator.

Lesson summary

  • Use the product law to change multiplication inside a logarithm into addition outside.
  • Use the quotient law to change division inside a logarithm into subtraction outside.
  • Use the power law to move an exponent on a positive argument to a coefficient.
  • Use the same base when combining logarithms, and check the original argument restrictions.

Check your understanding

Question 1

Which expression is equivalent to log⁡3(9x)\log_3(9x), for x>0x>0?
  1. 2+log⁡3x2+\log_3 x
  2. log⁡39+log⁡3(x2)\log_3 9+\log_3(x^2)
  3. 9+log⁡3x9+\log_3 x
  4. 2log⁡3x2\log_3 x
Show answer and explanation
2+log⁡3x2+\log_3 x
The product law gives log⁡39+log⁡3x\log_3 9+\log_3 x. Since 9=329=3^2, log⁡39=2\log_3 9=2.

Question 2

Which expression is equivalent to log⁡5(mn2)\log_5\left(\frac{m}{n^2}\right) when m>0m>0 and n>0n>0?
  1. log⁡5m−2log⁡5n\log_5 m-2\log_5 n
  2. log⁡5m+2log⁡5n\log_5 m+2\log_5 n
  3. 2log⁡5(m−n)2\log_5(m-n)
  4. log⁡5m2log⁡5n\frac{\log_5 m}{2\log_5 n}
Show answer and explanation
log⁡5m−2log⁡5n\log_5 m-2\log_5 n
The quotient law gives log⁡5m−log⁡5(n2)\log_5 m-\log_5(n^2), and the power law gives log⁡5m−2log⁡5n\log_5 m-2\log_5 n.

Question 3

Which expression is equivalent to 3log⁡2p+log⁡2q3\log_2 p+\log_2 q, given p>0p>0 and q>0q>0?
  1. log⁡2(p3q)\log_2(p^3q)
  2. log⁡2(3p+q)\log_2(3p+q)
  3. log⁡2(p3q)\log_2\left(\frac{p^3}{q}\right)
  4. log⁡2(pq3)\log_2(pq^3)
Show answer and explanation
log⁡2(p3q)\log_2(p^3q)
The power law gives 3log⁡2p=log⁡2(p3)3\log_2 p=\log_2(p^3). The product law then combines the sum as log⁡2(p3q)\log_2(p^3q).

Key terms

Argument
The quantity inside a logarithm. It must be positive for the logarithm to be defined in real-number work.
Expand
Rewrite one logarithm as a sum or difference of logarithms by using the logarithm laws.
Condense
Rewrite a sum or difference of logarithms as one logarithm by using the logarithm laws.
Restriction
A condition on a variable that ensures the original expression is defined.

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