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SL 4.5 · Use sample spaces, events, complements, and expected frequencies

Learn to use sample spaces, events, complements, and expected frequencies through clear examples and targeted practice.

International Baccalaureate (IB) IB AA SL: Mathematics: Analysis and Approaches SL

Statistics and Probability

IB Mathematics: Analysis and Approaches SL — Study topic SL 4.5

A random experiment has an outcome that cannot be known with certainty in advance, even when the possible outcomes are known. Examples include rolling a die or selecting a coloured counter from a bag. To reason clearly about such situations, list the possible outcomes, describe the event of interest, and connect its probability to how often it might occur in repeated trials. This lesson uses only these ideas. The notation and counting methods rely on basic arithmetic and fractions.

What you will learn

1. From outcomes to a sample space

A sample space is the set of all possible outcomes of a random experiment. It is usually written as SS. Each individual outcome must be described precisely enough that the outcomes do not overlap and none are missing. For example, when a fair six-sided die is rolled once, the sample space is S={1,2,3,4,5,6}S=\{1,2,3,4,5,6\}.
An event is a collection of outcomes from the sample space. Events are often named with capital letters. If AA is the event that the die shows an even number, then A={2,4,6}A=\{2,4,6\}. An outcome belongs to the event if it satisfies the stated condition.
When all outcomes are equally likely, the probability of an event can be found by counting. The number of outcomes in a set AA is written as n(A)n(A). The probability is the number of favourable outcomes divided by the total number of possible outcomes. This counting rule depends on equal likelihood; it cannot be used just because the outcomes have been listed.
P(A)=n(A)n(S)P(A)=\frac{n(A)}{n(S)}

2. Complements and representations

The complement of event AA, written A' in this lesson, means that AA does not occur. Its outcomes are all the outcomes in the sample space that are not in AA. An event and its complement cover the whole sample space without overlapping, so their probabilities add to 11.
This gives a useful way to find the probability of an event that is awkward to count directly: count or calculate the outcomes in which it does not happen, then subtract that probability from 11. For example, “at least one” often has the complementary description “none”.
The same situation can be represented in different ways. A list or table makes outcomes visible; a fraction shows the probability numerically; a set description identifies the event symbolically; and a context explains what the event means. A probability lies between 00 and 11: 00 means impossible and 11 means certain. A probability is not a guarantee about one trial.
P(A)+P(A′)=1P(A)+P(A')=1

3. Repeated trials and expected frequency

Suppose an event has probability pp on each trial and the experiment is carried out NN times under the same conditions. The expected frequency is the number of times the event would occur on average over many sets of NN trials. Calculate it by multiplying the number of trials by the probability.
Expected frequency is an estimate of a long-run average, not a prediction that the observed count must equal the answer. For example, an expected frequency of 1818 means that counts around 1818 are reasonable over repeated groups of trials; one particular group may have fewer or more. The expected frequency can be a decimal even though an actual count must be a whole number.
A graphing calculator or spreadsheet can simulate repeated trials by generating random outcomes and counting how often the event occurs. Compare the simulated proportion with the calculated probability, or the simulated count with the expected frequency. A simulation is a numerical check, not a replacement for identifying the sample space and calculating the probability. Different runs can produce different counts.
E=NpE=Np

4. A reliable problem-solving routine

First state what one trial consists of and identify its possible outcomes. Next, define the event in words and as a set or condition. Check whether the outcomes are equally likely before using a counting fraction. If counting the event directly is difficult, consider its complement. Finally, when repeated trials are involved, multiply the probability by the number of trials and interpret the result as an average.
For a technology check, use a random-number function that matches the sample space. For a fair six-sided die, for example, generate integers from 11 to 66, repeat the experiment, and count outcomes in the event. Do not use a function that makes some outcomes more likely unless the real experiment does so. Explain the theoretical probability before comparing it with the simulation.
In an exam-style response, make the assumption of equal likelihood clear when it matters, show the probability calculation, and include units or context for an expected frequency. If the question asks for a probability, give a value between 00 and 11; if it asks how many times, report a frequency and state that it is expected rather than certain.

Outcomes for a coin toss and a four-sided spinner

Coin resultSpinner resultOutcome pair
Heads1(H,1)(H,1)
Heads2(H,2)(H,2)
Heads3(H,3)(H,3)
Heads4(H,4)(H,4)
Tails1(T,1)(T,1)
Tails2(T,2)(T,2)
Tails3(T,3)(T,3)
Tails4(T,4)(T,4)

Worked example

1. A die event and its complement

A fair six-sided die is rolled once. Let AA be the event that the result is greater than 44. Find P(A)P(A) and the probability of the complement.
  1. List the outcomes
    The die can show any one of the six numbers, and fairness means these outcomes are equally likely.
    S={1,2,3,4,5,6}S=\{1,2,3,4,5,6\}
  2. Identify the event
    The numbers greater than 44 are 55 and 66, so there are two favourable outcomes out of six.
    A={5,6},P(A)=26=13A=\{5,6\},\quad P(A)=\frac{2}{6}=\frac{1}{3}
  3. Use the complement
    The complement consists of all results that are not greater than 44. Its probability is also found by subtracting the event probability from 11.
    P(A′)=1−13=23P(A')=1-\frac{1}{3}=\frac{2}{3}
Answer: The probability of rolling a number greater than 44 is 13\frac{1}{3}, and the probability of its complement is 23\frac{2}{3}.
Check: The probabilities add to 11, as the event and its complement together include every possible result.

Worked example

2. A two-part outcome and an event

A fair coin is tossed and a fair four-sided spinner labelled 1,2,3,4 is spun once. Each coin outcome is equally likely, each spinner outcome is equally likely, and the two results do not affect one another. Find the probability of getting tails and an odd number.
  1. Represent the sample space
    Each outcome records both the coin result and the spinner result. There are two coin outcomes paired with four spinner outcomes, giving eight equally likely pairs.
    S={(H,1),(H,2),(H,3),(H,4),(T,1),(T,2),(T,3),(T,4)}S=\{(H,1),(H,2),(H,3),(H,4),(T,1),(T,2),(T,3),(T,4)\}
  2. Select favourable outcomes
    The event requires tails and an odd spinner number. The matching pairs are (T,1)(T,1) and (T,3)(T,3), so two of the eight outcomes satisfy the condition.
    A={(T,1),(T,3)},P(A)=28=14A=\{(T,1),(T,3)\},\quad P(A)=\frac{2}{8}=\frac{1}{4}
Answer: The probability of getting tails and an odd number is 14\frac{1}{4}.
Check: The table of eight pairs shows that exactly two satisfy both conditions; the counting fraction is based on equally likely pairs.

Worked example

3. Expected frequency in repeated trials

A game has probability 310\frac{3}{10} of awarding a prize on each play. What is the expected number of prizes in 8080 plays?
  1. Identify the probability and trial count
    The event is winning a prize. Its probability is 310\frac{3}{10} on each play, and the total number of plays is 8080.
    p=310,N=80p=\frac{3}{10},\quad N=80
  2. Calculate the expected frequency
    Multiply the probability of a prize by the number of plays. The result is a frequency, so it is interpreted as an average number of prizes.
    E=Np=80(310)=24E=Np=80\left(\frac{3}{10}\right)=24
Answer: The expected frequency is 2424 prizes.
Check: This does not guarantee exactly 2424 prizes in one set of 8080 plays; it is the average indicated by the probability over repeated sets.

Common mistakes and how to avoid them

Using the favourable-outcomes fraction without checking whether the outcomes are equally likely.
Correction: Confirm equal likelihood first. If outcomes have different chances, simply counting them does not give the probability.
Leaving outcomes out of the sample space or listing the same outcome more than once.
Correction: Describe each outcome clearly and check that every possible result appears exactly once.
Treating the expected frequency as the count that must occur.
Correction: Interpret it as a long-run average; actual counts in a particular set of trials can differ.
Finding the complement by counting only outcomes that seem unlikely.
Correction: The complement is precisely all outcomes in the sample space that are not in the event.

Lesson summary

Check your understanding

Question 1

A fair die is rolled once. What is the probability that the result is not a 66?
  1. 16\frac{1}{6}
  2. 56\frac{5}{6}
  3. 12\frac{1}{2}
  4. 11
Show answer and explanation
56\frac{5}{6}
Five of the six equally likely results are not 66, so the probability is 56\frac{5}{6}. Equivalently, subtract 16\frac{1}{6} from 11.

Question 2

An event has probability 0.40.4 on each trial. What is its expected frequency in 5050 trials?
  1. 0.80.8
  2. 2020
  3. 4040
  4. 5050
Show answer and explanation
2020
Multiply the number of trials by the event probability: 50(0.4)=2050(0.4)=20. This is an average, not a guaranteed count.

Key terms

Random experiment
A process with an outcome that is not known with certainty before it happens.
Sample space
The set of all possible outcomes of a random experiment.
Event
A specified outcome or collection of outcomes from a sample space.
Complement
The event consisting of all outcomes in the sample space that are not in a given event.
Expected frequency
The average number of times an event is expected to occur in a stated number of trials.

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