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T10 · Solve real problems involving acute triangles

Learn to solve real problems involving acute triangles through clear examples and targeted practice.

Ontario Grade 10 Mathematics

Trigonometry

Choose a triangle rule, match sides and angles, and interpret the result

You already know that a triangle’s angles add to 180∘180^\circ. You may also have used right-triangle ratios, but those ratios need a right angle. In this lesson, you will solve problems involving acute triangles. An acute triangle has three angles smaller than 90∘90^\circ. The sine law and cosine law let you find missing measurements when the triangle does not have a right angle. You will learn how to identify the information you have, choose a rule, and check your answer in context.

What you will learn

1. Review triangle parts and angle facts

A triangle has three sides and three angles. The side opposite an angle is the side directly across from it. For example, the side across from angle AA is called side aa. Side bb is across from angle BB, and side cc is across from angle CC. These matching pairs are important when you choose a rule.
An acute triangle has three angles, each smaller than 90∘90^\circ. The angle-sum rule still applies: the three angles add to 180∘180^\circ. If two angles are known, subtract their sum from 180∘180^\circ to find the third. This can help complete a sketch or check a result.
In a real problem, measurements may describe roads, paths, supports, or distances between locations. First draw a simple triangle to represent the situation. The sketch does not need to be to scale. Label the known measurements and mark the measurement you need to find.
A+B+C=180∘A+B+C=180^\circ

2. Choose a rule that fits the known information

The sine law connects a triangle’s sides with the sines of their opposite angles. The sine of an angle is a value found using a calculator. Use the sine law when you know at least one opposite side-and-angle pair and need another side or angle. A matching pair means that the side and angle are directly across from each other.
The cosine law connects two sides and the angle between them to the third side. The angle between two sides is called the included angle. Use the cosine law when you know two sides and their included angle. It can also be rearranged to find an angle when all three sides are known.
A quick way to choose is to circle the known measurements on your sketch. Look for an opposite side-and-angle pair. If you have one, the sine law may fit. If you have two sides and the angle between them, the cosine law fits. Write the labels before substituting numbers so you do not mix up an angle and a side.
Set your calculator to degree mode. The angle measurements in these problems are given in degrees. Keep calculator values through the calculation and round only when you reach the requested final answer.
asin⁡A=bsin⁡B=csin⁡C\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}

3. Read the cosine law from a sketch

Imagine two straight paths that begin at the same point. One path is 4242 m long and the other is 5757 m long. The angle where they meet is 68∘68^\circ. The straight-line distance between the far ends completes a triangle. On a sketch, the unknown distance lies across from the known angle.
For this arrangement, call the unknown side cc, the two known sides aa and bb, and the angle between the known sides CC. The cosine law subtracts a term involving the two side lengths and the cosine of the included angle. This subtraction is part of the rule; do not replace it with addition.
The sketch gives a useful reasonableness check. The angle is acute, so the distance across the ends should be less than it would be if the paths opened to a right angle. It should also be longer than the difference between the two path lengths. A calculated value outside a reasonable range may signal a setup or calculator error.
c2=a2+b2−2abcos⁡Cc^2=a^2+b^2-2ab\cos C

4. Plan, solve, and practise

A reliable plan has four parts. Draw and label the triangle. Choose a rule that uses the known information. Substitute values with their units and calculate. Then state the result with units and check whether it makes sense in the situation.
For a sine-law problem, check that every side is paired with its opposite angle. For a cosine-law problem with two sides, check that the angle is between those sides. These checks matter more than the order in which you write the labels.
Independent practice: A surveyor marks two straight distances from one point, one measuring 3535 m and the other 4848 m. The angle between them is 72∘72^\circ. Sketch the triangle, identify the rule that fits, and write an expression for the distance between the two marked endpoints. Do not round an intermediate value.
Next, consider a triangular sign support. One side is 66 m, another is 99 m, and the angle between them is 55∘55^\circ. Decide which side is opposite the 55∘55^\circ angle and describe what you would calculate first. In both situations, your sketch should show why the chosen rule matches the measurements.

Choose a triangle rule

Known informationUseful ruleWhat to check
An opposite side-and-angle pair, plus another side or angleSine lawMatch each side with its opposite angle
Two sides and the angle between themCosine lawUse the angle formed by the two known sides
All three sides and a missing angleCosine lawKeep track of which side is opposite the angle you need

Worked example

Find the distance across a triangular park

Two paths from a meeting point to the ends of a park are 4242 m and 5757 m long. The angle between the paths is 68∘68^\circ. Find the straight-line distance between the two ends of the park, to the nearest tenth of a metre.
  1. Sketch and choose
    Draw the two known paths meeting at an angle of 68∘68^\circ. The distance between their far ends is opposite that angle. Since the problem gives two sides and their included angle, the cosine law fits.
  2. Substitute
    Let cc be the distance to find. Use the two path lengths for aa and bb, and use the angle between them for CC.
    c2=422+572−2(42)(57)cos⁡68∘c^2=42^2+57^2-2(42)(57)\cos 68^\circ
  3. Calculate and round
    The squared distance is about 3219.383219.38. Take the positive square root because a distance is positive, then round to the nearest tenth.
    c≈3219.38≈56.7c\approx\sqrt{3219.38}\approx56.7
Answer: The straight-line distance between the ends of the park is about 56.756.7 m.
Check: The two paths are 4242 m and 5757 m long. The answer is less than the longer path, as expected for this acute included angle, and it is greater than the difference between the path lengths, which is 1515 m. The units are metres, matching the measurements in the problem.

Common mistakes and how to avoid them

Using the sine law without matching each side to its opposite angle.
Correction: Label the triangle first. Side aa matches angle AA, side bb matches angle BB, and side cc matches angle CC.
Using an angle that is not between the two known sides in the cosine law.
Correction: On your sketch, identify the angle formed by the two sides you know. That is the included angle for this use of the cosine law.
Changing the subtraction in the cosine law to addition.
Correction: Copy the cosine-law pattern carefully. The term involving the two known sides and the cosine is subtracted.
Rounding intermediate values heavily.
Correction: Keep the calculator value until the final step, then round as the question requests.
Giving a distance without units.
Correction: Include the unit used in the problem, such as metres or centimetres.

Lesson summary

Check your understanding

Question 1

A triangle has angles 48∘48^\circ and 67∘67^\circ. What is its third angle?
  1. 55∘55^\circ
  2. 65∘65^\circ
  3. 75∘75^\circ
  4. 115∘115^\circ
Show answer and explanation
65∘65^\circ
The angles total 180∘180^\circ. Subtract the two known angles: 180∘−48∘−67∘=65∘180^\circ-48^\circ-67^\circ=65^\circ.

Question 2

You know two sides of an acute triangle and the angle between them. Which rule should you use to find the third side?
  1. The sine law
  2. The cosine law
  3. The angle-sum rule alone
  4. A right-triangle ratio
Show answer and explanation
The cosine law
The cosine law uses two sides and their included angle to find the side opposite that angle.

Question 3

In triangle ABCABC, side aa is opposite which angle?
  1. Angle AA
  2. Angle BB
  3. Angle CC
  4. The largest angle
Show answer and explanation
Angle AA
The standard labels in this lesson pair side aa with the angle directly across from it, angle AA.

Question 4

Two sides are 88 cm and 1111 cm, and their included angle is 60∘60^\circ. Which expression gives the square of the side opposite the 60∘60^\circ angle?
  1. 82+112−2(8)(11)cos⁡60∘8^2+11^2-2(8)(11)\cos 60^\circ
  2. 82+112+2(8)(11)cos⁡60∘8^2+11^2+2(8)(11)\cos 60^\circ
  3. 8sin⁡60∘=11sin⁡60∘\frac{8}{\sin 60^\circ}=\frac{11}{\sin 60^\circ}
  4. (8+11)cos⁡60∘(8+11)\cos 60^\circ
Show answer and explanation
82+112−2(8)(11)cos⁡60∘8^2+11^2-2(8)(11)\cos 60^\circ
The cosine law subtracts twice the product of the known sides and the cosine of the included angle.

Key terms

Acute triangle
A triangle with three angles smaller than 90∘90^\circ.
Opposite side
The side directly across from a particular angle in a triangle.
Included angle
The angle formed by two specified sides.
Sine law
A rule that relates each side of a triangle to the sine of its opposite angle.
Cosine law
A rule that relates two sides and their included angle to the third side, and can be rearranged to find an angle.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 10 Mathematics (MPM2D), study topic T10. It is a study resource, not an official curriculum publication.

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