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T8 · Explore the development of the cosine law for acute triangles

Learn to explore the development of the cosine law for acute triangles through clear examples and targeted practice.

Ontario Grade 10 Mathematics

Trigonometry

Use a perpendicular height, right triangles, and the Pythagorean theorem to develop a new side relationship.

The Pythagorean theorem connects the sides of a right triangle. But an acute triangle does not have a right angle, so we cannot apply that theorem directly to the whole triangle. We can still use it by drawing a perpendicular height inside the acute triangle. This creates right triangles. We will use their side lengths to develop the cosine law and see why the angle affects the length of the opposite side.

What you will learn

1. Bridge: right triangles and cosine

A right triangle has one angle measuring 90∘90^\circ. The hypotenuse is the side opposite that angle. The Pythagorean theorem says that the square of the hypotenuse equals the sum of the squares of the other two sides.
Cosine describes a side relationship in a right triangle. For an acute angle in that triangle, cosine is the length of the adjacent side divided by the length of the hypotenuse. The adjacent side is the side next to the chosen angle that is not the hypotenuse. For example, if the adjacent side is 44 and the hypotenuse is 55, the cosine of the angle is 45\frac{4}{5}.
An acute angle measures less than 90∘90^\circ. In this lesson, we use cosine for acute angles only. A perpendicular height is a line segment that meets a side at 90∘90^\circ. Drawing one can create right triangles inside a larger acute triangle.
z2=x2+y2z^2=x^2+y^2

2. Build right triangles inside an acute triangle

Imagine an acute triangle with angle CC between sides aa and bb. Name the side opposite angle CC as cc. The side names help us keep track of which parts of the triangle meet at the angle and which side is opposite it.
Draw a perpendicular height from the vertex opposite side aa to side aa. Since the triangle is acute, the foot of the height lies on side aa, between its endpoints. The height divides the original triangle into two right triangles.
In the right triangle beside angle CC, side bb is the hypotenuse. The horizontal part of that side along side aa is adjacent to angle CC. By the definition of cosine, this part has length bcos⁡Cb\cos C. Call the height hh. Using the Pythagorean theorem in this right triangle gives a relationship for h2h^2.
In the other right triangle, the horizontal leg is the remaining part of side aa, so its length is a−bcos⁡Ca-b\cos C. Its hypotenuse is cc, and its other leg is the same height, hh. Apply the Pythagorean theorem again. Then substitute the first relationship for h2h^2. The height cancels, leaving a rule that uses only the side lengths and angle CC.
Here is the algebra in one line. Expanding the square creates a term involving b2cos⁡2Cb^2\cos^2 C. That term cancels with the matching term from the first right triangle. The remaining expression is the cosine law for this triangle.
c2=(a−bcos⁡C)2+b2−(ba?)c^2=(a-b\cos C)^2+b^2-(b a? )

3. Read and use the cosine law

The developed rule relates the two sides that meet at angle CC to the side opposite that angle. The angle matters because it determines the length of the segment bcos⁡Cb\cos C along side aa.
For an acute angle, cosine is positive. Therefore, the adjustment term in the cosine law is positive before it is subtracted. The squared opposite side is less than the sum of the squares of the two sides meeting at the angle. This helps explain how the angle changes the side relationship.
To use the rule, first identify the angle and the side opposite it. Then identify the two sides that meet at that angle. Only those two sides belong in the adjustment term. After finding the square of the unknown side, take its positive square root to find the side length.
c2=a2+b2−2abcos⁡Cc^2=a^2+b^2-2ab\cos C

4. Guided example and independent practice

In the example, the two given sides meet at the given acute angle. The opposite side is unknown. We substitute into the cosine law, calculate its square, and take the positive square root.
Independent practice: In an acute triangle, sides of lengths 88 and 66 meet at 60∘60^\circ. Set up the cosine-law expression for the square of the opposite side, evaluate it, and compare it with the sum of the two side squares. The comparison should reflect that the cosine adjustment is subtracted.
c=a2+b2−2abcos⁡Cc=\sqrt{a^2+b^2-2ab\cos C}

Pieces created by the perpendicular height

PartLengthWhy
Whole baseaaIt is opposite angle CC.
Segment along the base under side bbbcos⁡Cb\cos CCosine is adjacent side divided by hypotenuse.
Remaining base segmenta−bcos⁡Ca-b\cos CSubtract the first segment from the whole base.
Other right-triangle leghhIt is the same perpendicular height in both right triangles.

Worked example

Find the side opposite a known acute angle

In an acute triangle, sides a=7a=7 and b=5b=5 meet at angle C=60∘C=60^\circ. Find the length of the opposite side cc. Use cos⁡60∘=0.5\cos 60^\circ=0.5.
  1. Match the parts
    Angle CC lies between sides aa and bb. The side opposite it is cc, so this is the matching form of the cosine law.
    c2=a2+b2−2abcos⁡Cc^2=a^2+b^2-2ab\cos C
  2. Substitute the values
    Replace the side lengths and cosine value with the information given. Keep the multiplication together so the subtraction is clear.
    c2=72+52−2(7)(5)(0.5)c^2=7^2+5^2-2(7)(5)(0.5)
  3. Calculate the side length
    The calculation gives the square of the unknown side. Since a length is positive, take the positive square root.
    c2=39c=39≈6.24c^2=39\qquad c=\sqrt{39}\approx6.24
Answer: The opposite side is approximately 6.246.24 units long.
Check: The squared result, 3939, is less than 72+52=747^2+5^2=74. This is consistent with subtracting the positive cosine adjustment for an acute angle.

Common mistakes and how to avoid them

Using an angle that is not between the two known sides.
Correction: The angle in the adjustment term is formed by those two sides. Check which sides meet at the angle before substituting.
Adding the adjustment for an acute angle.
Correction: Cosine is positive for an acute angle, so the adjustment term is subtracted.
Stopping after finding the square of the unknown side.
Correction: Take the positive square root to find the side length.
Applying the Pythagorean theorem to the whole acute triangle.
Correction: The whole triangle is not a right triangle. Apply the theorem to the two right triangles made by the height.

Lesson summary

Check your understanding

Question 1

Sides pp and qq meet at acute angle RR. Which side is opposite angle RR in the matching cosine-law form?
  1. The side called rr
  2. Side pp
  3. Side qq
  4. Either side pp or side qq
Show answer and explanation
The side called rr
The two sides in the adjustment term meet at the angle. The remaining side, rr, is opposite that angle.

Question 2

Sides a=6a=6 and b=4b=4 meet at 60∘60^\circ. What is the square of the opposite side?
  1. 2828
  2. 5252
  3. 7676
  4. 100100
Show answer and explanation
2828
Substitute into the cosine law: 62+42−2(6)(4)(0.5)=36+16−24=286^2+4^2-2(6)(4)(0.5)=36+16-24=28.

Question 3

Why is the cosine adjustment subtracted for an acute angle?
  1. Cosine is positive for an acute angle.
  2. Cosine is negative for an acute angle.
  3. The opposite side is always the longest side.
  4. The height always equals one of the other sides.
Show answer and explanation
Cosine is positive for an acute angle.
Cosine is positive for an acute angle. The positive adjustment is therefore subtracted in the cosine law.

Key terms

Acute angle
An angle with a measure less than 90∘90^\circ.
Adjacent side
In a right triangle, the side next to a chosen acute angle that is not the hypotenuse.
Cosine
For an acute angle in a right triangle, the ratio of the adjacent side length to the hypotenuse length.
Hypotenuse
The side opposite the right angle in a right triangle.
Perpendicular
Meeting at a right angle.
Cosine law
A rule relating the sides of a triangle to the cosine of one of its angles.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 10 Mathematics (MPM2D), study topic T8. It is a study resource, not an official curriculum publication.

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