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C3.2 · Factor polynomials up to degree four

Learn to factor polynomials up to degree four through clear examples and targeted practice.

Ontario Grade 12 Mathematics

Polynomial and Rational Functions

Recognize structure, choose a method, and check by expanding

Factoring rewrites a polynomial as a product of simpler expressions. For example, the expression x2+5x+6x^2+5x+6 can be written as (x+2)(x+3)(x+2)(x+3). Multiplying the factors returns the original expression. This lesson reviews useful Grade 11 skills, then applies them to polynomials whose degree is at most four. The degree is the greatest exponent of the variable with a nonzero coefficient.

What you will learn

1. Prerequisite bridge: factors and degree

A polynomial is an expression made from terms such as numbers and powers of a variable, combined by addition or subtraction. In this lesson, the variable is usually xx. A term is one part of an expression separated by addition or subtraction. In 3x2−5x+23x^2-5x+2, the terms are 3x23x^2, −5x-5x, and 22.
A factor is an expression that is multiplied by another expression. Since 3(x+2)=3x+63(x+2)=3x+6, the expression 3x+63x+6 has factors 33 and x+2x+2. Factoring reverses multiplication and expansion.
The degree of a nonzero polynomial in one variable is its highest exponent. For instance, 4x3−x+74x^3-x+7 has degree three. The expression 2x4+3x2−12x^4+3x^2-1 has degree four, even though it has no x3x^3 or xx term.
Before factoring, arrange terms in descending powers when that makes the structure easier to see. Look for a number or variable factor shared by every term. Taking out this common factor is often the best first move.

2. Useful factoring patterns

A common factor can include a number, a variable, or both. For example, each term in 6x3+9x26x^3+9x^2 contains 3x23x^2. Removing it leaves 3x2(2x+3)3x^2(2x+3). The terms inside the brackets must multiply by the common factor to reproduce the original terms.
A difference of squares is a subtraction of two perfect squares. A perfect square is an expression multiplied by itself, such as x2x^2 or 2525. The pattern a2−b2=(a−b)(a+b)a^2-b^2=(a-b)(a+b) applies when both parts are squares and are separated by subtraction.
For a quadratic trinomial of the form x2+bx+cx^2+bx+c, seek two numbers whose product is cc and whose sum is bb. Those numbers become the constants in two binomial factors. A binomial is a polynomial with two terms.
For expressions with four terms, grouping can help. Group pairs of terms, factor a common factor from each pair, and look for a matching bracket. If the brackets match, that bracket is a common factor.
A polynomial of degree four may also be viewed as a quadratic in x2x^2. If every variable power is even, let u=x2u=x^2 temporarily. Factor the resulting quadratic in uu, then replace each uu with x2x^2 and continue if a factor pattern applies.
a2−b2=(a−b)(a+b)a^2-b^2=(a-b)(a+b)

3. A method for choosing and checking

No single method works for every polynomial. Start by counting the terms and checking for a common factor. Then inspect the remaining expression for a familiar pattern.
For a trinomial of degree two, use the product-and-sum method when the coefficient of x2x^2 is one. For four terms, test grouping. For a difference of squares, use the matching pattern. For a degree-four expression with only even powers, consider treating it as a quadratic in x2x^2.
After factoring, multiply the factors to check the result. Expand one pair at a time, combine like terms, and compare with the original polynomial. Like terms have the same variable raised to the same power. For example, 2x22x^2 and 5x25x^2 are like terms, but 2x22x^2 and 5x5x are not.
A polynomial is fully factored over the integers when it has been written as a product and none of its factors can be factored further using integer coefficients. For this lesson, report the common factor as well as any further factorization that the expression allows.

4. Apply the patterns carefully

Factoring can involve more than one decision. A common factor may reveal a familiar pattern that was not obvious at first. Similarly, a quadratic-in-x2x^2 approach may produce a difference of squares that needs another step.
Keep the variable and exponents visible while working. Replacing x2x^2 by a temporary letter can make a degree-four expression easier to read, but it does not change the original variable. After factoring, substitute back and check whether the new factors can be broken down further.
Signs matter. In a quadratic trinomial, the product determines whether the two constants have matching or opposite signs, and their sum determines which signs are needed. Always verify both conditions rather than relying on a guess.

Choose a factoring approach

What you noticeApproach to tryExample pattern
Every term shares a factorTake out the common factor6x2+9x=3x(2x+3)6x^2+9x=3x(2x+3)
Two squares are separated by subtractionUse difference of squaresx2−16=(x−4)(x+4)x^2-16=(x-4)(x+4)
A monic quadratic trinomialFind a product and sum pairx2+7x+12=(x+3)(x+4)x^2+7x+12=(x+3)(x+4)
Four terms can form matching bracketsGroup pairs of termsax+ay+bx+by=(a+b)(x+y)ax+ay+bx+by=(a+b)(x+y)
Only even powers appear in a degree-four expressionTreat it as a quadratic in x2x^2x4+bx2+cx^4+bx^2+c

Worked example

Factor a degree-four polynomial

Factor x4−5x2+4x^4-5x^2+4 fully over the integers.
  1. Notice the structure
    The expression has degree four, but its variable powers are 44, 22, and 00. Treat it as a quadratic in x2x^2 by using uu in place of x2x^2.
    u=x2u=x^2
  2. Factor the quadratic
    We need two numbers with product 44 and sum −5-5. The numbers −1-1 and −4-4 meet both conditions, so the quadratic factors as shown.
    u2−5u+4=(u−1)(u−4)u^2-5u+4=(u-1)(u-4)
  3. Substitute back
    Replace each uu with x2x^2. Both new factors are differences of squares, so each can be factored again.
    (x2−1)(x2−4)(x^2-1)(x^2-4)
  4. Factor each difference of squares
    Apply the difference-of-squares pattern to both brackets. The four resulting linear factors cannot be factored further over the integers.
    (x−1)(x+1)(x−2)(x+2)(x-1)(x+1)(x-2)(x+2)
Answer: x4−5x2+4=(x−1)(x+1)(x−2)(x+2)x^4-5x^2+4=(x-1)(x+1)(x-2)(x+2)
Check: Pair the factors as (x2−1)(x2−4)(x^2-1)(x^2-4). Their product is x4−5x2+4x^4-5x^2+4, which matches the original.

Common mistakes and how to avoid them

Stopping after taking out a common factor.
Correction: Check the remaining bracket for another factorization. A complete answer may require several stages.
Using the difference-of-squares pattern on a sum, such as x2+9x^2+9.
Correction: The pattern requires subtraction between the squares. Do not change a plus sign to a minus sign.
Choosing two numbers whose product is correct but whose sum is not.
Correction: For x2+bx+cx^2+bx+c, check both conditions: the product must be cc and the sum must be bb.
Forgetting to replace a temporary variable such as uu with the original expression.
Correction: Substitute back before writing the final factors in terms of xx.
Changing a sign while expanding to check the result.
Correction: Multiply each pair carefully, then combine like terms and compare every coefficient with the original.

Lesson summary

Check your understanding

Question 1

Which is the fully factored form of x2−9x^2-9 over the integers?
  1. (x−3)(x+3)(x-3)(x+3)
  2. (x−9)(x+1)(x-9)(x+1)
  3. (x−3)2(x-3)^2
  4. x(x−9)x(x-9)
Show answer and explanation
(x−3)(x+3)(x-3)(x+3)
x2−9x^2-9 is a difference of squares: x2−32=(x−3)(x+3)x^2-3^2=(x-3)(x+3). Multiplying the factors gives x2−9x^2-9.

Question 2

Which pair of numbers factors x2+x−12x^2+x-12 as a product of two binomials?
  1. 44 and −3-3
  2. −4-4 and 33
  3. 66 and −2-2
  4. −6-6 and 22
Show answer and explanation
44 and −3-3
4(−3)=−124(-3)=-12 and 4+(−3)=14+(-3)=1, so x2+x−12=(x+4)(x−3)x^2+x-12=(x+4)(x-3).

Question 3

What should be done first when factoring 8x3−12x28x^3-12x^2?
  1. Take out the common factor 4x24x^2.
  2. Use the difference-of-squares pattern.
  3. Treat the expression as a quadratic in x2x^2.
  4. Group the two terms into pairs.
Show answer and explanation
Take out the common factor 4x24x^2.
Both terms share 4x24x^2, so the first step is 8x3−12x2=4x2(2x−3)8x^3-12x^2=4x^2(2x-3). The remaining binomial does not factor further over the integers.

Key terms

Polynomial
An expression made from terms with numerical coefficients and nonnegative integer powers of a variable, joined by addition or subtraction.
Term
One part of an expression separated from other parts by addition or subtraction.
Degree
The greatest exponent of the variable in a nonzero polynomial.
Factor
A quantity or expression multiplied by another to make a product.
Binomial
A polynomial with two terms.
Monic quadratic
A quadratic polynomial whose coefficient of x2x^2 is 11.
Difference of squares
A subtraction of two perfect-square expressions that can be factored as the difference and sum of their square roots.
Like terms
Terms with the same variable raised to the same power.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 12 Mathematics (MHF4U), expectation C3.2. It is a study resource, not an official curriculum publication.

Before publication, the draft is checked for structure, mathematical or chemical notation, calculations, course boundaries, and readability, and then requires administrator approval. Errors can still occur, so corrections are welcomed.

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