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C1.2 · Assess impacts of energy- and momentum-based technologies

Learn to assess impacts of energy- and momentum-based technologies through clear examples and targeted practice.

Ontario Grade 12 Physics

Energy and Momentum

Using physics to weigh benefits, costs, and trade-offs

Technologies can help people meet needs, but they can also create costs or risks. A device may reduce injury, supply electricity, or make transport more efficient. It may also use materials, affect nearby communities, or create waste. To assess a technology, connect its purpose to physics, then consider evidence about its effects. In this lesson, an impact means a change or consequence linked to using or making a technology. A benefit is a helpful impact; a cost is a harmful impact. An impact can affect people, the environment, or the economy. A fair assessment considers more than one impact and states what evidence would support each claim.

What you will learn

1. Start with the physics and the system

SPH3U provides useful starting ideas. Energy is a scalar: it has an amount but no direction. Kinetic energy is energy of motion. Momentum is a vector: it has both an amount and a direction. A force can change an object's momentum. These ideas help explain technologies such as vehicle safety devices, braking systems, and energy-conversion devices.
Before using a relationship, define the system, reference frame, and positive direction. The system is the object or group of objects being considered. The reference frame is the viewpoint used to describe motion. For a vehicle example, choose the vehicle and occupant as the system, the road as the reference frame, and the vehicle's initial travel direction as positive. State what is inside the system because energy or momentum can be transferred between the system and its surroundings.
A technology's physical effect is only one part of its impact. Ask what need it addresses, who benefits, who may bear costs, and how long the impacts last. Separate a physics claim, such as 'the device reduces the force on an occupant in this model,' from a broader claim, such as 'the device makes travel safe.' The broader claim needs additional evidence.
Ek=12mv2,p⃗=mv⃗E_k=\frac{1}{2}mv^2,\quad \vec p=m\vec v

2. Use relationships to explain a technology

Kinetic energy depends on mass and on speed squared. This means that, for the same mass, doubling speed makes kinetic energy four times as large. A braking or protective technology may need to manage energy transferred during a stop. The equation estimates the object's initial kinetic energy; it does not by itself tell us how well a specific device works.
Momentum depends on mass and velocity. Impulse is the change in momentum during an interaction. If the change in momentum is spread over a longer time, the average force can be smaller. This is one physics reason that a suitably designed airbag or padding can reduce the force on a person in a collision. The result depends on the actual device and conditions; the relationship alone is not proof of a particular safety outcome.
Energy technologies can be assessed by tracking useful energy output and energy input. Efficiency is the fraction of input energy converted into the intended useful output. A larger efficiency can mean less input is needed for the same useful output, but it does not show the full impact. Construction, operation, location, maintenance, and end-of-life handling can also matter. Assess these using relevant evidence rather than assuming that one efficiency number settles the question.
J⃗=Δp⃗=F⃗avgΔt,η=EusefulEinput\vec J=\Delta\vec p=\vec F_{\text{avg}}\Delta t,\quad \eta=\frac{E_{\text{useful}}}{E_{\text{input}}}

3. Assess impacts with evidence and trade-offs

A balanced assessment has four parts. First, identify the technology's purpose and the physics principle that makes it work. Second, name the expected benefits and possible costs. Third, identify evidence for each claim. Fourth, explain who is affected and whether the impact changes over time. Relevant evidence may include measured performance, safety records, energy use, material requirements, or reports about effects on people and the environment. Check where the evidence came from and whether it applies to the situation being discussed.
A trade-off is a choice in which improving one outcome may worsen another, or in which different groups experience different outcomes. For example, a technology may provide a useful service while requiring materials and infrastructure. Do not assume those effects are equal in size or certainty. State what is known, what remains uncertain, and what further evidence would help.
Keep calculated, measured, and proposed information distinct. A calculation based on stated values is a model result. It is not a measurement. A proposed investigation describes what someone could measure; it is not completed evidence. If a comparison uses example values, label them as hypothetical. This makes the assessment honest and easier to evaluate.

4. Build a clear conclusion

A useful conclusion answers a focused question, such as whether a technology is suitable for a particular purpose. Support the answer with a physics explanation and evidence about impacts. Acknowledge a meaningful limitation or uncertainty. Avoid calling a technology simply 'good' or 'bad' when the evidence shows several kinds of effects.
For example, a conclusion about a protective device might say that its design can reduce average force in a stated collision model because it increases stopping time. It should then note that actual protection depends on device performance and use, and that broader safety claims require relevant evidence. A conclusion about an energy technology should similarly link its energy conversion to evidence about its wider impacts.

Worked example

Estimating a change in average force

A hypothetical safety-device model considers a 70.0 kg70.0\,\mathrm{kg} occupant moving at 12.0 m/s12.0\,\mathrm{m/s} who comes to rest. Compare the average force magnitude if the stop takes 0.0600 s0.0600\,\mathrm{s} rather than 0.120 s0.120\,\mathrm{s}. These are example values, not measured data.
  1. Define the motion
    Take the occupant as the system, the road as the reference frame, and the initial travel direction as positive. The initial velocity is positive and the final velocity is zero. The unknown is the average force exerted during each stop.
  2. Find the momentum change
    Momentum is mass times velocity. The final momentum is zero, so the change in momentum points opposite to the initial motion. Use the impulse relationship to find the average force.
    Δp=(70.0 kg)(0−12.0 m/s)=−840 kg m/s\Delta p=(70.0\,\mathrm{kg})(0-12.0\,\mathrm{m/s})=-840\,\mathrm{kg\,m/s}
  3. Compare stopping times
    Average force equals momentum change divided by time. The negative sign gives the direction: opposite the initial motion. The magnitudes are reported for the comparison.
    ∣Favg∣=840 kg m/s0.0600 s=1.40×104 N;∣Favg∣=840 kg m/s0.120 s=7.00×103 N|F_{\text{avg}}|=\frac{840\,\mathrm{kg\,m/s}}{0.0600\,\mathrm{s}}=1.40\times10^4\,\mathrm{N};\quad |F_{\text{avg}}|=\frac{840\,\mathrm{kg\,m/s}}{0.120\,\mathrm{s}}=7.00\times10^3\,\mathrm{N}
Answer: In this simplified model, doubling stopping time halves the average force magnitude, from 1.40×104 N1.40\times10^4\,\mathrm{N} to 7.00×103 N7.00\times10^3\,\mathrm{N}. The force points opposite the initial motion.
Check: The units reduce to newtons because kg m/s\mathrm{kg\,m/s} divided by seconds is kg m/s2\mathrm{kg\,m/s^2}. The result is reasonable: the same momentum change over twice the time gives half the average force. This model does not establish the performance of a real device.

Worked example

Comparing kinetic energy at two speeds

A hypothetical 1.20×103 kg1.20\times10^3\,\mathrm{kg} vehicle moves at 10.0 m/s10.0\,\mathrm{m/s} or 20.0 m/s20.0\,\mathrm{m/s}. Compare its kinetic energy in the road reference frame.
  1. Define the system and unknown
    Take the vehicle as the system and the road as the reference frame. Kinetic energy is a scalar, so it has no direction. The unknown is the kinetic energy at each speed.
  2. Apply the kinetic-energy relationship
    Use the same mass at both speeds. Substitute each speed in metres per second and keep the energy unit, joule, in the result.
    Ek,1=12(1.20×103 kg)(10.0 m/s)2=6.00×104 J;Ek,2=12(1.20×103 kg)(20.0 m/s)2=2.40×105 JE_{k,1}=\frac{1}{2}(1.20\times10^3\,\mathrm{kg})(10.0\,\mathrm{m/s})^2=6.00\times10^4\,\mathrm{J};\quad E_{k,2}=\frac{1}{2}(1.20\times10^3\,\mathrm{kg})(20.0\,\mathrm{m/s})^2=2.40\times10^5\,\mathrm{J}
  3. Interpret the comparison
    The second speed is twice the first, while the calculated energy is four times as large. A technology assessment may use this relationship to explain why speed matters, but it should use suitable evidence before making claims about actual stopping distance or safety.
    Ek,2Ek,1=4.00\frac{E_{k,2}}{E_{k,1}}=4.00
Answer: The kinetic energies are 6.00×104 J6.00\times10^4\,\mathrm{J} at 10.0 m/s10.0\,\mathrm{m/s} and 2.40×105 J2.40\times10^5\,\mathrm{J} at 20.0 m/s20.0\,\mathrm{m/s}. The faster case has four times the kinetic energy.
Check: The unit kg m2/s2\mathrm{kg\,m^2/s^2} is a joule. A fourfold increase is reasonable because speed is squared in the relationship.

Worked example

Using efficiency without overstating impact

A hypothetical energy device receives 800 J800\,\mathrm{J} of energy and delivers 520 J520\,\mathrm{J} as useful output. Calculate its efficiency and state what the result can and cannot establish.
  1. Define the energy comparison
    Treat the device as the system during the stated energy transfer. Energy is scalar. The input and useful output are the known values; efficiency is the unknown.
  2. Calculate efficiency
    Divide useful output energy by input energy. The joule units cancel, so efficiency is a ratio with no unit. Convert the ratio to a percentage.
    η=520 J800 J=0.65=65%\eta=\frac{520\,\mathrm{J}}{800\,\mathrm{J}}=0.65=65\%
  3. Limit the conclusion
    The result describes the stated energy conversion only. It does not tell us how the device was manufactured, how long it lasts, or what effects occur when it is disposed of. Those claims need other evidence.
Answer: The device's efficiency in this hypothetical example is 65%.
Check: Efficiency is dimensionless and is below 100%, consistent with useful output being less than input. The calculation alone is not a complete impact assessment.

Common mistakes and how to avoid them

Treating momentum as a scalar or leaving out its direction.
Correction: Momentum is a vector. Choose a positive direction and use the sign of velocity to show direction.
Claiming that a longer stopping time proves a real safety device prevents injury.
Correction: The impulse model explains a possible force reduction. A claim about actual injury outcomes needs relevant evidence.
Using one efficiency value as a complete assessment of an energy technology.
Correction: Efficiency describes energy conversion. Assess other impacts with additional evidence.
Presenting hypothetical values or a calculation as measured evidence.
Correction: Label model inputs clearly. State separately what has actually been measured and what is proposed.

Lesson summary

Check your understanding

Question 1

For the same momentum change, what happens to average force magnitude if stopping time doubles?
  1. It doubles.
  2. It is halved.
  3. It stays the same.
  4. It becomes zero.
Show answer and explanation
It is halved.
Average force magnitude is momentum-change magnitude divided by time. Doubling time halves the force for the same momentum change.

Question 2

A device has a calculated efficiency of 65%. What does that result establish by itself?
  1. It establishes every environmental impact of the device.
  2. It establishes the device will last a particular number of years.
  3. It describes the useful-output fraction for the stated energy comparison.
  4. It proves that the device is the best choice for every community.
Show answer and explanation
It describes the useful-output fraction for the stated energy comparison.
Efficiency describes the stated energy conversion. Other claims need additional evidence.

Question 3

Which statement correctly distinguishes a model result from measured evidence?
  1. A calculation using stated example values is automatically a measurement.
  2. A proposed procedure is evidence that its predicted result occurred.
  3. A model result follows from stated assumptions; a measurement comes from observations or instrument readings.
  4. A model result and a measurement always have identical certainty.
Show answer and explanation
A model result follows from stated assumptions; a measurement comes from observations or instrument readings.
A calculation is derived from inputs and assumptions. A measurement is obtained from observations or instruments; the two should not be confused.

Key terms

System
The object or group of objects selected for analysis.
Reference frame
The viewpoint used to describe position and motion.
Momentum
A vector quantity equal to an object's mass multiplied by its velocity.
Impulse
The change in momentum during an interaction; for a constant average force, it equals average force multiplied by interaction time.
Efficiency
The ratio of useful energy output to energy input.
Trade-off
A situation in which choices or effects involve competing outcomes.

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About this lesson and its review

Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 12 Physics (SPH4U), expectation C1.2. It is a study resource, not an official curriculum publication.

Before publication, the draft is checked for structure, mathematical or chemical notation, calculations, course boundaries, and readability, and then requires administrator approval. Errors can still occur, so corrections are welcomed.

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