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6.2 · Apply Dalton’s law to ideal-gas mixtures

Learn to apply dalton’s law to ideal-gas mixtures through clear examples and targeted practice.

University of Alberta MEC E 340: Applied Thermodynamics

Gas Mixtures and Real Gases

Using mole fractions to find the pressure contributed by each gas

Consider a closed, rigid tank containing a mixture of ideal gases. Let state 1 describe the mixture in the tank, with every component at the same temperature and occupying the same tank volume. Assume the gases do not react and that mixture behaviour is ideal. Dalton’s law says the total pressure is the sum of the partial pressures: the pressure each component would exert if it alone occupied the mixture’s volume at the mixture temperature. The law is useful in applied thermodynamics whenever the composition and pressure of an ideal-gas mixture matter. This lesson focuses on applying that rule; it does not require an energy balance unless one is needed to determine a state.

What you will learn

  • State Dalton’s law and the assumptions behind applying it.
  • Relate a gas component’s partial pressure to its mole fraction and the mixture’s total pressure.
  • Use component amounts and the ideal-gas equation to solve mixture-pressure problems with SI units.
  • Check that calculated partial pressures add to the total pressure and are physically plausible.

1. Review the pressure and composition ideas

For an ideal gas, pressure, volume, temperature, and amount of gas are related by the ideal-gas equation. In a mixture, each component has its own amount, but all components share the mixture temperature and volume. The total amount is the sum of the component amounts.
The mole fraction of component ii is the fraction of the mixture’s total moles that belong to that component. Mole fractions are dimensionless, lie from zero to one, and add to one when all components are included.
Dalton’s law applies to an ideal-gas mixture. It connects each component’s mole fraction to its partial pressure. A component with a greater mole fraction has a greater share of the total pressure. The law does not say that the components occupy separate parts of the tank.
n=∑ini,yi=nin,∑iyi=1n=\sum_i n_i,\qquad y_i=\frac{n_i}{n},\qquad \sum_i y_i=1
  • Define the mixture and its state before calculating.
  • All components in the stated mixture share the same temperature and volume.
  • Use mole fractions, not mass fractions, in the partial-pressure relation.

2. Apply Dalton’s law

At state 1, imagine replacing the mixture with one component at a time while keeping the same temperature and tank volume. Each component’s hypothetical pressure is its partial pressure. Dalton’s law states that adding these partial pressures gives the mixture’s total pressure.
For ideal gases in the same volume and at the same temperature, the ideal-gas equation gives a useful form of the law: a component’s partial pressure equals its mole fraction multiplied by the total pressure. Alternatively, if the component amounts and the shared temperature and volume are known, calculate each partial pressure directly from the ideal-gas equation.
Keep units consistent. Pressure may be reported in kilopascals or pascals, but all terms in a pressure sum must use the same unit. If a gas constant is needed, use a value and units consistent with the chosen pressure, volume, temperature, and amount units.
Pi=yiP,P=∑iPiP_i=y_iP,\qquad P=\sum_i P_i
  • The partial pressures sum to the total pressure.
  • A zero mole fraction gives a zero partial pressure.
  • The sum of the mole fractions should be one, apart from small rounding differences.

3. A reliable problem-solving sequence

First identify the system: for example, a closed tank containing a nonreacting ideal-gas mixture at state 1. List the components and the known data, such as component amounts, total pressure, temperature, or volume. State that the mixture is treated as ideal when the problem provides that assumption.
Next find the total amount and each mole fraction if component amounts are given. Then use the most direct form of Dalton’s law: multiply mole fraction by total pressure when total pressure is known, or use the ideal-gas equation for each component when temperature, volume, and component amount are known.
Finally, check the result. The component partial pressures must add to the total pressure. Each partial pressure must be nonnegative and no greater than the total pressure. If the calculated mole fractions do not add to one, check whether a component was omitted or whether rounding caused the difference.
Dalton’s law is a pressure and composition relation. It is not, by itself, an energy balance. If temperature or another state property must be found from heating or cooling, the appropriate energy balance and property information are needed separately; do not infer missing state data from Dalton’s law.
Pi=niRTVP_i=\frac{n_iRT}{V}
  • Write down the state, system, components, and ideal-mixture assumption.
  • Choose between the mole-fraction form and component ideal-gas equations based on the known data.
  • Verify both the composition sum and the pressure sum.

4. Scope and interpretation

Partial pressure is a convenient accounting quantity for an ideal-gas mixture. It represents the pressure contribution assigned to one component under the shared mixture conditions. The actual mixture is still one gas mixture in one volume.
The calculations in this lesson rely on the stated ideal-gas model. If a problem specifies real-gas behaviour, this simple Dalton-law calculation alone may not describe the mixture accurately. Do not silently substitute a different model or invent correction data.
For straightforward mixture questions, no cycle diagram or control-volume device diagram is needed. The essential representation is the list of components at the same mixture state, together with their amounts or mole fractions and the total pressure.
  • Dalton’s law here is for ideal-gas mixtures.
  • State clearly which components are included in the total.
  • Do not confuse the mixture’s total pressure with any one component’s partial pressure.

Worked example

Find partial pressures from composition

A rigid tank at state 1 contains 2.0 mol of nitrogen and 1.0 mol of oxygen. The ideal-gas mixture pressure is 300 kPa. Find both partial pressures. Treat the gases as nonreacting ideal gases.
  1. Identify the mixture
    The closed tank contains two ideal-gas components at the same state, temperature, and volume. The total amount is the sum of their amounts.
    n=2.0+1.0=3.0 moln=2.0+1.0=3.0\ \mathrm{mol}
  2. Find mole fractions
    Divide each component amount by the total amount. The fractions should add to one.
    yN2=2.03.0,yO2=1.03.0y_{\mathrm{N_2}}=\frac{2.0}{3.0},\qquad y_{\mathrm{O_2}}=\frac{1.0}{3.0}
  3. Calculate component pressures
    Multiply each mole fraction by the given total pressure. These are the partial pressures under the mixture conditions.
    PN2=200 kPa,PO2=100 kPaP_{\mathrm{N_2}}=200\ \mathrm{kPa},\qquad P_{\mathrm{O_2}}=100\ \mathrm{kPa}
Answer: The nitrogen partial pressure is 200 kPa, and the oxygen partial pressure is 100 kPa.
Check: The partial pressures sum to 300 kPa, the stated total pressure. Each is nonnegative and below the total.

Worked example

Find total pressure from component amounts

A sealed 0.020 m³ vessel at state 1 contains 0.40 mol of helium and 0.60 mol of neon. The uniform mixture temperature is 300 K. Treat both gases as ideal. Using the supplied ideal-gas constant R=8.314 J/(mol⋅K)R=8.314\ \mathrm{J/(mol\cdot K)}, find the total pressure and each partial pressure.
  1. Set the shared conditions
    Both components occupy the same vessel volume and are at the same temperature. Use the ideal-gas equation for each component with the supplied gas constant.
    Pi=niRTVP_i=\frac{n_iRT}{V}
  2. Calculate partial pressures
    Using pascals for pressure because the supplied gas constant is in joules, calculate each component’s pressure contribution.
    PHe=49.9 kPa,PNe=74.8 kPaP_{\mathrm{He}}=49.9\ \mathrm{kPa},\qquad P_{\mathrm{Ne}}=74.8\ \mathrm{kPa}
  3. Add the contributions
    Dalton’s law gives the total pressure as the sum of the component partial pressures.
    P=49.9+74.8=124.7 kPaP=49.9+74.8=124.7\ \mathrm{kPa}
Answer: The total pressure is approximately 124.7 kPa. The helium and neon partial pressures are approximately 49.9 kPa and 74.8 kPa, respectively.
Check: The amount ratio is 0.40:0.60, so the partial-pressure ratio is also 0.40:0.60 at common temperature and volume. The calculated values have that ratio and sum to the total.

Worked example

Use partial pressure to recover component amount

A rigid vessel at state 1 contains an ideal-gas mixture at 320 K and 150 kPa. Its volume is 0.050 m³. The partial pressure of carbon dioxide is 30 kPa. Find the carbon-dioxide mole fraction and amount. Use R=8.314 J/(mol⋅K)R=8.314\ \mathrm{J/(mol\cdot K)}.
  1. Find the mole fraction
    Dalton’s law relates the component partial pressure to the total pressure through its mole fraction.
    yCO2=30150=0.20y_{\mathrm{CO_2}}=\frac{30}{150}=0.20
  2. Find the component amount
    Convert the partial pressure to pascals and use the ideal-gas equation for the carbon dioxide at the shared vessel temperature and volume.
    nCO2=(30,000 Pa)(0.050 m3)(8.314 J/(mol⋅K))(320 K)=0.564 moln_{\mathrm{CO_2}}=\frac{(30{,}000\ \mathrm{Pa})(0.050\ \mathrm{m^3})}{(8.314\ \mathrm{J/(mol\cdot K)})(320\ \mathrm{K})}=0.564\ \mathrm{mol}
  3. Check against the total amount
    The total amount follows from the same ideal-gas equation using total pressure. The component amount should equal its mole fraction times this total.
    n=2.82 mol,0.20n=0.564 moln=2.82\ \mathrm{mol},\qquad 0.20n=0.564\ \mathrm{mol}
Answer: The carbon-dioxide mole fraction is 0.20, and the vessel contains approximately 0.564 mol of carbon dioxide.
Check: The component amount is one-fifth of the total amount, matching its one-fifth share of the total pressure. The pressure and amount calculations are consistent.

Common mistakes and how to avoid them

Using a component’s mass fraction directly in the partial-pressure equation.
Correction: Convert the composition to mole fractions first; Dalton’s law uses mole fraction.
Treating partial pressures as pressures in separate parts of the vessel.
Correction: Each partial pressure is the ideal-gas pressure that component would exert alone in the full mixture volume at the mixture temperature.
Reporting one component’s partial pressure as the total pressure.
Correction: Add the partial pressures of all included components to obtain the total.
Mixing pressure units in the ideal-gas equation or pressure sum.
Correction: Convert all pressures to a consistent unit and match the gas-constant units.

Lesson summary

  • For an ideal-gas mixture, components share the mixture temperature and volume.
  • Mole fractions are component moles divided by total moles and sum to one.
  • A component’s partial pressure is its mole fraction times total pressure.
  • The sum of all component partial pressures equals total pressure.
  • Use the ideal-gas equation when component amount, temperature, and volume are known, and check units and pressure sums.

Check your understanding

Question 1

An ideal-gas mixture has total pressure 240 kPa and a component mole fraction of 0.25. What is that component’s partial pressure?
  1. 60 kPa
  2. 180 kPa
  3. 240 kPa
  4. 960 kPa
Show answer and explanation
60 kPa
The partial pressure is the mole fraction multiplied by total pressure: 0.25 times 240 kPa equals 60 kPa.

Question 2

In a two-component ideal-gas mixture, the mole fractions are 0.35 and 0.65. If the first component’s partial pressure is 70 kPa, what is the total pressure?
  1. 24.5 kPa
  2. 107.7 kPa
  3. 200 kPa
  4. 270 kPa
Show answer and explanation
200 kPa
The first component has 0.35 of the total pressure, so total pressure is 70 kPa divided by 0.35, or 200 kPa.

Key terms

Ideal-gas mixture
A mixture treated as ideal in which each gas component follows the ideal-gas model under the shared mixture conditions.
Mole fraction
The amount of one component divided by the total amount of the mixture.
Partial pressure
The pressure assigned to one component as if it alone occupied the mixture volume at the mixture temperature.
Dalton’s law
For an ideal-gas mixture, total pressure equals the sum of the component partial pressures.

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