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A1 · Apply and rearrange practical measurement and finance formulas

Learn to apply and rearrange practical measurement and finance formulas through clear examples and targeted practice.

Alberta Grade 11 Mathematics

Algebra

Use measurement and finance formulas to find unknown values

Formulas describe how quantities are connected. A measurement formula can connect the dimensions of a container to its volume. A finance formula can connect money, an interest rate, and time. A variable is a letter that stands for a quantity. Substitution means replacing a variable with a known value. Rearranging means changing a formula so a different variable is by itself. In each problem, identify what is known and what you need to find. Then choose a suitable formula, substitute carefully, and check the result.

What you will learn

  • Identify known values and the unknown quantity in a practical problem.
  • Choose and use a formula that connects the quantities in a problem.
  • Rearrange a formula with inverse operations to isolate an unknown.
  • Check units and decide whether an answer is reasonable.

Choose a formula and track units

Start by naming the unknown. List the known values with their units. Then choose a formula that connects those values to the unknown. For example, the volume of a rectangular prism is found by multiplying its length, width, and height. A rectangular prism is a box-shaped solid with six rectangular faces.
Units tell what a measurement means. Length may be measured in centimetres, time in years, and money in Canadian dollars. Keep units beside values as you work. If measurements of the same kind use different units, convert one before substituting. Use a conversion factor supplied in the problem rather than memorizing a long list.
V=lwhV=lwh
  • Name the unknown before calculating.
  • Write known values with units.
  • Choose a formula that connects the known values to the unknown.

Substitute and check

To substitute, replace each variable with its known value. Brackets make it clear which values belong together. Follow the operations in the formula and keep units with measurements.
Units can help check your work. Multiplying three lengths gives cubic units, such as cubic centimetres. A reasonableness check asks whether the answer fits the situation. A volume must be positive. If one dimension doubles while the other dimensions stay the same, the volume doubles too.
(1 cm)(1 cm)(1 cm)=1 cm3(1\text{ cm})(1\text{ cm})(1\text{ cm})=1\text{ cm}^3
  • Put each known value in the matching place in the formula.
  • Use units in the calculation and in the final answer.
  • Check that the result makes sense in context.

Rearrange by undoing operations

A formula may not show the unknown by itself. To rearrange it, undo the operations connected to that unknown. Multiplication is undone by division. Addition is undone by subtraction. Apply the same operation to both sides of an equation so the equality remains true.
For example, the area of a rectangle is its length multiplied by its width. If the area and width are known, divide both sides by the width to isolate the length. Substitute the result into the original relationship as a check.
A=lw⇒l=AwA=lw\quad\Rightarrow\quad l=\frac{A}{w}
  • Use inverse operations to isolate the requested variable.
  • Apply the same operation to both sides.
  • Check the result in the original formula.

Apply a simple-interest formula

Simple interest is interest calculated on the original amount only. The principal is the starting amount of money. The rate is the interest rate written as a decimal for calculation. Time must use the same basis as the rate. For an annual rate, time is measured in years. The simple-interest formula finds the interest earned, not the final balance.
A financial rate needs a source. A rate described as hypothetical is a made-up practice value, not a claim about a current product. In a real problem, use the rate and terms supplied by the relevant source. Convert a percent to a decimal by dividing it by 100.
I=PrtI=Prt
  • Simple interest is based on the original principal.
  • Convert a percent rate to a decimal before substituting.
  • Match the time unit to the rate’s time basis.

Worked example

Find the volume of a storage bin

A rectangular storage bin is 60 cm long, 35 cm wide, and 40 cm high. Find its volume in cubic centimetres.
Rectangular storage bin
60 cm35 cm40 cmV = 84000 cm³

The labelled dimensions are the measurements used to calculate the bin’s volume.

  1. Choose the formula
    The bin is a rectangular prism. Its volume is the product of its length, width, and height.
    V=lwhV=lwh
  2. Substitute and calculate
    All three dimensions are in centimetres, so the volume is in cubic centimetres.
    V=(60 cm)(35 cm)(40 cm)=84 000 cm3V=(60\text{ cm})(35\text{ cm})(40\text{ cm})=84\,000\text{ cm}^3
  3. Check the result
    The answer is positive and represents the space inside the bin. Multiplying three lengths gives cubic units.
    60×35×40=84 00060\times35\times40=84\,000
Answer: The bin’s volume is 84 000 cm³.
Check: The unit is cubic centimetres because three lengths were multiplied.

Worked example

Find a missing dimension by rearranging

A rectangular container has a volume of 2.4 m³. Its length is 2 m and its width is 0.8 m. Find its height.
Rectangular container
2 m0.8 m1.5 mV = 2.4 m³

The length and width are known; the calculated height completes the dimensions.

  1. Write the relationship
    The volume of a rectangular prism is length multiplied by width multiplied by height. The height is the unknown.
    V=lwhV=lwh
  2. Isolate the height
    The height is multiplied by the length and width. Divide both sides by their product to undo those multiplications.
    h=Vlwh=\frac{V}{lw}
  3. Substitute and calculate
    Use the given measurements. Dividing cubic metres by square metres leaves metres, the correct unit for height.
    h=2.4 m3(2 m)(0.8 m)=1.5 mh=\frac{2.4\text{ m}^3}{(2\text{ m})(0.8\text{ m})}=1.5\text{ m}
  4. Check in the original formula
    Multiply the three dimensions. The result matches the given volume.
    (2 m)(0.8 m)(1.5 m)=2.4 m3(2\text{ m})(0.8\text{ m})(1.5\text{ m})=2.4\text{ m}^3
Answer: The container is 1.5 m high.
Check: The dimensions reproduce the stated volume, and the answer has units of length.

Worked example

Calculate hypothetical simple interest

For practice, suppose CAD 800 is invested at a hypothetical simple annual interest rate of 3% for 2 years. Find the interest earned. This is a made-up practice rate, not a current offer.
  1. Choose the formula
    The principal is CAD 800, the annual rate is 3%, and the time is 2 years. The question asks for interest, not the final balance.
    I=PrtI=Prt
  2. Convert the rate
    A percent means an amount out of 100. Divide 3 by 100 to write the rate as a decimal.
    3%=0.033\%=0.03
  3. Substitute and calculate
    The rate is annual and time is in years, so the time units match.
    I=(800)(0.03)(2)=48I=(800)(0.03)(2)=48
  4. Check the size
    At this practice rate, one year’s interest is CAD 24. Two years of simple interest is CAD 48.
    24+24=4824+24=48
Answer: The hypothetical investment earns CAD 48 in simple interest.
Check: The answer is interest earned, not the total balance. The stated rate and time give CAD 24 per year.

Common mistakes and how to avoid them

Using an area unit for a volume answer.
Correction: Volume uses cubic units because three lengths are multiplied.
Dividing by the wrong quantity when rearranging.
Correction: Identify the operations involving the unknown, then undo them on both sides.
Using 3 instead of 0.03 for a 3% rate.
Correction: Convert a percent to a decimal by dividing by 100.
Treating simple interest as the final amount.
Correction: The formula gives interest only. Add the interest to the principal only if the question asks for the total balance.

Lesson summary

  • Choose a formula that links the known values to the unknown.
  • Substitute carefully and keep units with measurements.
  • Rearrange with inverse operations, applying the same operation to both sides.
  • Check units, context, and reasonableness before reporting an answer.

Check your understanding

Question 1

A rectangle has an area of 18 m² and a width of 3 m. What is its length?
  1. 6 m
  2. 54 m
  3. 15 m
  4. 6 m²
Show answer and explanation
6 m
Divide area by width: 18 m² divided by 3 m equals 6 m.

Question 2

What decimal represents a hypothetical annual rate of 5% in a simple-interest calculation?
  1. 0.5
  2. 5
  3. 0.05
  4. 50
Show answer and explanation
0.05
Divide 5 by 100 to convert the percent to 0.05.

Question 3

A box is 2 m long, 1 m wide, and 0.5 m high. What is its volume?
  1. 3.5 m³
  2. 1 m³
  3. 3 m²
  4. 2 m³
Show answer and explanation
1 m³
Multiply the dimensions: 2 times 1 times 0.5 equals 1. Three dimensions give cubic metres.

Key terms

Variable
A letter used to stand for a quantity.
Substitution
Replacing a variable in a formula with a known value.
Rearranging
Changing a formula’s form to isolate a different variable while keeping the relationship true.
Principal
The starting amount of money used in an interest calculation.
Simple interest
Interest calculated on the original principal only.

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Published by DoAssignment. This reviewed lesson follows Alberta Grade 11 Mathematics (Math 20-3), expectation A1. It is a study resource, not an official curriculum publication.

Before publication, content is checked for structure, mathematical or chemical notation, calculations, course boundaries, and readability. Errors can still occur, so corrections are welcomed.

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