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SL 1.7 · Expand binomials using the binomial theorem

Learn to expand binomials using the binomial theorem through clear examples and targeted practice.

International Baccalaureate (IB) IB AA SL: Mathematics: Analysis and Approaches SL

Number and Algebra

Using coefficients, powers, and structure to expand expressions efficiently

A binomial is an expression with two terms, such as x+3x+3 or 2x−12x-1. Multiplying a binomial by itself works for small powers, but repeated multiplication becomes lengthy. The binomial theorem gives a pattern for the coefficients and powers in the expansion. This lesson reviews the needed algebra, develops that pattern, and applies it to exact expansions and checks.

What you will learn

1. Prior knowledge: powers and coefficients

An exponent tells how many equal factors are multiplied: (x+2)3=(x+2)(x+2)(x+2)(x+2)^3=(x+2)(x+2)(x+2). Expanding means multiplying out the brackets and collecting like terms. For example, (x+2)2=x2+4x+4(x+2)^2=x^2+4x+4.
The binomial theorem extends this process to any non-negative integer exponent nn. The number of terms in the expansion is n+1n+1. The powers of the first term decrease from nn to 00, while the powers of the second term increase from 00 to nn.
The symbol (nr){n \choose r}, read as “nn choose rr,” is a coefficient. It counts the ways to choose rr items from nn items, and can be calculated using factorials. Here, nn and rr are whole numbers with 0≤r≤n0\le r\le n; 0!=10!=1.
(nr)=n!r!(n−r)!{n \choose r}=\frac{n!}{r!(n-r)!}

2. The theorem and its pattern

For a binomial (a+b)n(a+b)^n, the general term uses the coefficient (nr){n\choose r}, the power an−ra^{n-r}, and the power brb^r. Add these terms as rr runs from 00 to nn. This is the binomial theorem for a non-negative integer exponent.
For instance, the coefficients for power 44 are 1,4,6,4,1. They are the values (40),(41),…,(44){4\choose 0},{4\choose 1},\ldots,{4\choose 4}. The corresponding powers move from a4a^4 to a0a^0 and from b0b^0 to b4b^4.
If the second term is negative, substitute that negative term for bb. Its successive powers alternate in sign: odd powers are negative and even powers are positive. Write terms in descending powers of the first term, and combine like terms if the binomial terms contain the same variable.
(a+b)n=∑r=0n(nr)an−rbr(a+b)^n=\sum_{r=0}^{n}{n\choose r}a^{n-r}b^r

3. Reading an expansion in different ways

Algebraically, the theorem produces an exact polynomial. Numerically, substituting a value for the variable gives a value for the original power and for its expanded form; the two results must agree. This provides a useful check, but one substitution cannot prove that two expressions are identical.
Graphically, the original expression and the expanded polynomial should have the same graph over the real-number domain. A graphing calculator can plot both expressions together or compare their values at several inputs. This is a check for errors, not a replacement for showing the expansion.
In a simple context, if a square has side length x+2x+2 units, its area is (x+2)2(x+2)^2 square units. Expanding gives an equivalent expression for that area. The context may restrict xx so side lengths are non-negative; the algebraic identity itself holds for every real xx.
(x+2)2=x2+4x+4(x+2)^2=x^2+4x+4

4. A reliable expansion routine

Identify the first term, second term, and exponent before writing any terms. Use the coefficient row for that exponent, or calculate each coefficient with (nr){n\choose r}. Then write each term with decreasing powers of the first term and increasing powers of the second.
Check that there are n+1n+1 terms, that each term’s exponents add to nn, and that signs are consistent. If the question asks for one coefficient only, identify which value of rr gives the required power; a complete expansion may not be necessary.
A calculator check is most useful after the symbolic work: enter the original power and the proposed polynomial, then compare their values at several real inputs. Keep the written method visible, since a calculator comparison alone does not explain why the expansion has those coefficients.
(nr)an−rbr{n\choose r}a^{n-r}b^r

Worked example

Expand a binomial with a positive second term

Expand (2x+3)4(2x+3)^4.
  1. Identify the terms
    Here the first term is 2x2x, the second term is 33, and the exponent is 44. Use the coefficient row 1,4,6,4,1.
  2. Apply the powers
    Decrease the power of 2x2x from 44 to 00 and increase the power of 33 from 00 to 44. The exponents in each product add to 44.
    (2x)4+4(2x)3(3)+6(2x)2(3)2+4(2x)(3)3+(3)4(2x)^4+4(2x)^3(3)+6(2x)^2(3)^2+4(2x)(3)^3+(3)^4
  3. Simplify each term
    Evaluate the numerical factors and write the result in descending powers of xx.
    16x4+96x3+216x2+216x+8116x^4+96x^3+216x^2+216x+81
Answer: (2x+3)4=16x4+96x3+216x2+216x+81(2x+3)^4=16x^4+96x^3+216x^2+216x+81.
Check: At x=1x=1, the original expression is 54=6255^4=625. The expanded expression gives 16+96+216+216+81=62516+96+216+216+81=625.

Worked example

Expand carefully when a term is negative

Expand (x−2)5(x-2)^5.
  1. Set the second term
    Use the second term as −2-2, not 22. The coefficients for power 55 are 1,5,10,10,5,1.
  2. Write the terms
    The negative second term is raised to successive powers, so its signs alternate. Keep the powers of xx in descending order.
    x5+5x4(−2)+10x3(−2)2+10x2(−2)3+5x(−2)4+(−2)5x^5+5x^4(-2)+10x^3(-2)^2+10x^2(-2)^3+5x(-2)^4+(-2)^5
  3. Simplify
    Evaluate each power of −2-2 and collect the resulting terms.
    x5−10x4+40x3−80x2+80x−32x^5-10x^4+40x^3-80x^2+80x-32
Answer: (x−2)5=x5−10x4+40x3−80x2+80x−32(x-2)^5=x^5-10x^4+40x^3-80x^2+80x-32.
Check: At x=2x=2, both the original expression and the expansion equal 00, as expected.

Worked example

Find a particular coefficient

Find the coefficient of x3x^3 in (2x−1)6(2x-1)^6 without expanding every term.
  1. Match the power
    A general term is (6r)(2x)6−r(−1)r{6\choose r}(2x)^{6-r}(-1)^r. Its power of xx is 6−r6-r. Set that power equal to 33.
    6−r=36-r=3
  2. Determine the term
    The matching value is r=3r=3. Substitute it into the general term to obtain the entire term containing x3x^3.
    (63)(2x)3(−1)3{6\choose 3}(2x)^3(-1)^3
  3. Read off the coefficient
    Since (63)=20{6\choose 3}=20, the term is −160x3-160x^3. The coefficient is the number multiplying x3x^3.
    20⋅8⋅(−1)=−16020\cdot 8\cdot(-1)=-160
Answer: The coefficient of x3x^3 is −160-160.
Check: The negative sign is correct because the matched term uses the odd power (−1)3(-1)^3.

Common mistakes and how to avoid them

Writing the powers of both terms in descending order.
Correction: The first term’s powers decrease, while the second term’s powers increase. Their exponents add to the original exponent in every term.
Treating (x−2)5(x-2)^5 as though the second term were positive.
Correction: Use −2-2 as the second term. Its powers produce alternating signs.
Stopping after writing the coefficient row.
Correction: A coefficient row gives only the numerical coefficients. Include the powers of both binomial terms as well.
Assuming a matching calculator value proves the expansion.
Correction: Show the theorem-based expansion. Substitution and graphing are checks that can help find errors, not substitutes for the algebra.

Lesson summary

Check your understanding

Question 1

What is the coefficient of x2x^2 in (x+3)4(x+3)^4?
  1. 18
  2. 54
  3. 36
  4. 81
Show answer and explanation
54
The x2x^2 term uses r=2r=2: (42)x232=6⋅9x2=54x2{4\choose 2}x^2 3^2=6\cdot9x^2=54x^2.

Question 2

How many terms are in the expansion of (2x−1)7(2x-1)^7 before collecting like terms?
  1. 7
  2. 8
  3. 14
  4. 49
Show answer and explanation
8
An exponent of 77 gives 7+1=87+1=8 terms.

Question 3

What is the constant term in (x−2)4(x-2)^4?
  1. −16-16
  2. 1616
  3. −8-8
  4. 11
Show answer and explanation
1616
The constant term occurs when the power of xx is zero, giving (−2)4=16(-2)^4=16.

Key terms

Binomial
An algebraic expression with two terms, such as x+3x+3.
Coefficient
A numerical factor multiplying a term, such as 55 in 5x25x^2.
Factorial
For a positive whole number nn, n! is the product n(n−1)(n−2)⋯1n(n-1)(n-2)\cdots1, and 0!=10!=1.
Binomial coefficient
The number (nr){n\choose r}, calculated by n!r!(n−r)!\frac{n!}{r!(n-r)!}, used as a coefficient in the expansion.

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Published by DoAssignment. This AI-assisted lesson follows International Baccalaureate (IB) IB AA SL: Mathematics: Analysis and Approaches SL, study topic SL 1.7. It is a study resource, not an official curriculum publication.

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