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E2.2 · Calculate solution concentration in multiple units

Learn to calculate solution concentration in multiple units through clear examples and targeted practice.

Ontario Grade 11 Chemistry

Solutions and Solubility

SCH3U E2.2 study topic: mol/L, g/L, and mass-based ppm

Two drinks with the same volume may have different colour intensity. The darker drink may contain more dissolved colouring in that volume. At the particle level, it has more colouring particles compared with the amount of solution. Concentration describes this comparison. Different concentration units are useful because a question may give the solute amount in moles or grams, and the solution amount as a volume or mass.

What you will learn

1. Connect the quantities to the mixture

A solution is a uniform mixture. The solute is the substance dissolved in the mixture. The solvent is the substance that dissolves the solute. In salt water, salt is the solute and water is the solvent.
Concentration compares an amount of solute with a stated amount of the whole solution. The denominator is not just the solvent. For example, if two samples have the same solution volume, the sample with more dissolved solute has the greater concentration.
Before calculating, identify three things: the solute, the amount of solute, and the amount of solution. The solute amount may be in moles or grams. The solution amount may be a volume in litres or a mass in grams or kilograms, depending on the requested unit.
At the particle level, concentration describes how much solute is present relative to a chosen amount of solution. The particles are not counted one by one in these calculations. Instead, measurable amounts such as mass and volume are used to describe the mixture.
In words, concentration is the amount of solute divided by the amount of solution. The particular quantities and units depend on the concentration form. A concentration value is incomplete without its unit.

2. Molar concentration and mass concentration

Molar concentration compares the amount of solute, in moles, with the volume of solution, in litres. A mole is a counting unit for particles. The symbol nn represents amount in moles, VV represents solution volume, and cc represents molar concentration. The usual unit is mol/L\mathrm{mol/L}.
Mass concentration compares the solute mass, in grams, with the solution volume, in litres. Its unit is g/L\mathrm{g/L}. This form uses mass rather than amount in moles, so it reports a different comparison.
For both forms, use the final solution volume. If a volume is given in millilitres, convert it to litres before calculating. There are 1000 mL1000\ \mathrm{mL} in 1 L1\ \mathrm{L}, so divide the millilitre value by 10001000.
If a question gives solute mass but asks for molar concentration, first convert the mass to moles. Molar mass is the mass of one mole of a substance, expressed in g/mol\mathrm{g/mol}. Divide the mass by the molar mass. The gram units cancel, leaving moles.
Choose the relationship that matches the requested unit. Moles per litre gives molar concentration. Grams per litre gives mass concentration. Do not substitute grams for moles in a molar concentration calculation.
c=nVc=\frac{n}{V}

3. Mass-based concentration in parts per million

Parts per million, written ppm, is a scale for a small amount of solute compared with a much larger amount of solution. In the mass-based form taught here, compare the solute mass with the solution mass. Both masses must use the same unit before division.
Multiply the mass ratio by one million to express the result as parts per million. For example, 3 mg3\ \mathrm{mg} of solute per 1 kg1\ \mathrm{kg} of solution is 3 ppm3\ \mathrm{ppm}, because 1 kg=1 000 000 mg1\ \mathrm{kg}=1\,000\,000\ \mathrm{mg}.
Do not use solution volume in place of solution mass for this mass-based ppm calculation. If only a solution volume is known, the mass ratio cannot be calculated unless the solution mass is also given.
A ppm result is not the same numerical value as a result in mol/L or g/L. Each unit compares different quantities. A conversion between forms is possible only when the information needed for both forms is available.
ppm=msolutemsolution×106\mathrm{ppm}=\frac{m_{\mathrm{solute}}}{m_{\mathrm{solution}}}\times10^6

4. Set up calculations, track units, and round

A clear calculation begins by identifying the known quantities and the requested unit. Convert units first when needed. Then substitute values with their units into the matching relationship.
Units help check the setup. Dividing moles by litres leaves mol/L\mathrm{mol/L}. Dividing grams by litres leaves g/L\mathrm{g/L}. In mass-based ppm, matching mass units cancel in the ratio, and the factor of one million sets the ppm scale.
Significant digits show the precision of measured values. For multiplication and division, report the final result with the same number of significant digits as the least precise measured value. Exact unit conversions do not limit the digits.
Keep extra digits during intermediate calculations. Round only the final result, and include the unit. Also check that the denominator is the stated amount of the whole solution and that the result answers the requested form of concentration.

Worked example

Calculate concentration in three units

A solution has a final volume of 250.0 mL250.0\ \mathrm{mL} and a mass of 250.0 g250.0\ \mathrm{g}. It contains 5.85 g5.85\ \mathrm{g} of sodium chloride, NaCl\mathrm{NaCl}. Calculate its mass concentration in g/L\mathrm{g/L}, molar concentration in mol/L\mathrm{mol/L}, and mass-based concentration in ppm. Use a molar mass of 58.44 g/mol58.44\ \mathrm{g/mol} for NaCl\mathrm{NaCl}.
  1. Convert solution volume
    Convert millilitres to litres because the two volume-based concentration units use litres. The millilitre units cancel in the conversion.
    250.0 mL×1 L1000 mL=0.2500 L250.0\ \mathrm{mL}\times\frac{1\ \mathrm{L}}{1000\ \mathrm{mL}}=0.2500\ \mathrm{L}
  2. Find mass concentration
    Divide the solute mass by the final solution volume in litres. The remaining unit is grams per litre.
    5.85 g0.2500 L=23.4 g/L\frac{5.85\ \mathrm{g}}{0.2500\ \mathrm{L}}=23.4\ \mathrm{g/L}
  3. Convert solute mass to moles
    Divide the solute mass by its molar mass. The gram units cancel, leaving the amount of sodium chloride in moles.
    n=5.85 g58.44 g/mol=0.100 moln=\frac{5.85\ \mathrm{g}}{58.44\ \mathrm{g/mol}}=0.100\ \mathrm{mol}
  4. Find molar concentration
    Divide the amount in moles by the final solution volume in litres. The result has three significant digits, based on the solute mass.
    c=0.100 mol0.2500 L=0.400 mol/Lc=\frac{0.100\ \mathrm{mol}}{0.2500\ \mathrm{L}}=0.400\ \mathrm{mol/L}
  5. Find mass-based ppm
    Use the solution mass, not its volume, for mass-based ppm. The mass units cancel in the ratio. The solution mass includes the solute.
    5.85 g250.0 g×106=2.34×104 ppm\frac{5.85\ \mathrm{g}}{250.0\ \mathrm{g}}\times10^6=2.34\times10^4\ \mathrm{ppm}
Answer: The solution has a mass concentration of 23.4 g/L23.4\ \mathrm{g/L}, a molar concentration of 0.400 mol/L0.400\ \mathrm{mol/L}, and a mass-based concentration of 2.34×104 ppm2.34\times10^4\ \mathrm{ppm}.
Check: The volume-based results both use 0.2500 L0.2500\ \mathrm{L} of solution. For ppm, the solute mass is 0.02340.0234 of the solution mass. Multiplying that ratio by one million gives 2.34×104 ppm2.34\times10^4\ \mathrm{ppm}.

Common mistakes and how to avoid them

Using the solvent volume instead of the final solution volume.
Correction: Use the volume of the whole solution for molar concentration and mass concentration.
Using grams directly in a molar concentration calculation.
Correction: Convert the solute mass to moles using molar mass before dividing by solution volume.
Leaving millilitres in a calculation that requires litres.
Correction: Convert the solution volume to litres before calculating mol/L or g/L.
Using solution volume in a mass-based ppm calculation.
Correction: Compare solute mass with solution mass, using the same mass units.
Reporting concentration without a unit or rounding too early.
Correction: Include the requested unit and round only the final answer.

Lesson summary

Check your understanding

Question 1

A solution contains 4.0 g4.0\ \mathrm{g} of solute in a final volume of 0.200 L0.200\ \mathrm{L}. What is its mass concentration?
  1. 20. g/L20.\ \mathrm{g/L}
  2. 0.80 g/L0.80\ \mathrm{g/L}
  3. 0.020 g/L0.020\ \mathrm{g/L}
  4. 20. mol/L20.\ \mathrm{mol/L}
Show answer and explanation
20. g/L20.\ \mathrm{g/L}
Divide solute mass by solution volume: 4.0 g/0.200 L=20. g/L4.0\ \mathrm{g}/0.200\ \mathrm{L}=20.\ \mathrm{g/L}. The given values support two significant digits.

Question 2

A solution contains 2.0 mg2.0\ \mathrm{mg} of solute in 1.0 kg1.0\ \mathrm{kg} of solution. What is its mass-based concentration?
  1. 2.0 ppm2.0\ \mathrm{ppm}
  2. 0.0020 ppm0.0020\ \mathrm{ppm}
  3. 2.0×103 ppm2.0\times10^3\ \mathrm{ppm}
  4. 2.0 mol/L2.0\ \mathrm{mol/L}
Show answer and explanation
2.0 ppm2.0\ \mathrm{ppm}
Convert 1.0 kg1.0\ \mathrm{kg} to 1.0×106 mg1.0\times10^6\ \mathrm{mg}. The mass ratio is 2.0 mg/(1.0×106 mg)2.0\ \mathrm{mg}/(1.0\times10^6\ \mathrm{mg}). Multiplying by one million gives 2.0 ppm2.0\ \mathrm{ppm}.

Key terms

Solution
A uniform mixture of a solute and a solvent.
Solute
The substance dissolved in a solution.
Solvent
The substance that dissolves the solute.
Concentration
A comparison between an amount of solute and a stated amount of solution.
Molar concentration
The amount of solute in moles divided by the volume of solution in litres.
Mass concentration
The mass of solute in grams divided by the volume of solution in litres.
Molar mass
The mass of one mole of a substance, usually expressed in grams per mole.
Parts per million
A concentration scale that expresses solute amount relative to one million matching parts of solution.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 11 Chemistry (SCH3U), expectation E2.2. It is a study resource, not an official curriculum publication.

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