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B2.6 · Represent composite numbers with prime factor trees

Learn to represent composite numbers with prime factor trees through clear examples and targeted practice.

Ontario Grade 6 Mathematics

Number

Split composite numbers into factors until every branch ends in a prime

A factor tree shows how a number can be split into smaller factors. At each split, the two new numbers multiply to make the number above them. Keep splitting any composite numbers. Stop when every branch ends in a prime. Multiplication facts help you build and check the tree.

What you will learn

  • Recognize prime and composite numbers used in a factor tree.
  • Build a factor tree by splitting composite numbers into factors.
  • Tell when a factor tree is complete.
  • List and check every prime at the ends of a tree.

1. Review the numbers in a factor tree

A factor is a whole number that can be multiplied by another whole number to make a product. For example, 33 and 44 are factors of 1212 because 3×4=123 \times 4 = 12. The product is the answer to a multiplication question.
A prime number is a whole number greater than 11 with exactly two factors: 11 and itself. For example, 55 is prime because its only factors are 11 and 55. A composite number is a whole number greater than 11 with more than two factors. For example, 1212 is composite because 33 and 44 multiply to make it.
The number 11 is neither prime nor composite. A factor tree starts with a composite number. Each split replaces one number with two factors. The numbers at the ends of the branches are called the ends of the tree. A prime factor is a prime number at one of those ends.
  • The two factors at a split must multiply to make the number being split.
  • A prime number can end a branch.
  • A composite number needs to be split further.

2. Build and check a factor tree

Start with the composite number you want to represent. Choose two factors that multiply to make it, and write them as the next branches. Check the split by multiplying the factors.
If a branch ends in a composite number, split it into two factors. If it ends in a prime number, leave it alone. Repeat until every branch ends in a prime.
For example, split 1212 into 33 and 44. This works because 3×4=123 \times 4 = 12. The 33 is prime, but the 44 is composite. Split 44 into 22 and 22. The ends are now 33, 22, and 22, all prime.
A number can have more than one correct tree. Another way to start with 1212 is to split it into 22 and 66, then split 66 into 22 and 33. The trees have different shapes, but the ends are still 22, 22, and 33. Each split must be correct, and every end must be prime.
To check a tree, confirm that the two factors at each split multiply to make the number above them. Then check that every end is prime. If an end is composite, the tree is not complete.
  • Every split must keep the same product.
  • Split composite branches, but leave prime branches alone.
  • Different tree shapes can have the same prime ends.

3. Read the ends and practise

When a tree is complete, list every prime number at its ends. Include a number each time it appears. If two branches end in 22, write both 22s.
Multiply the listed primes to check the starting number. Their product should match it. Also check that each listed number is prime; a matching product alone does not show that the tree is complete.
Try making a tree for 1818 and then one for 2828. For 1818, you could begin with 22 and 99. For 2828, you could begin with 44 and 77. In each tree, keep splitting composite branches and leave prime branches alone.
Your tree does not need to match someone else’s tree. It is correct when every split uses factors of the number above it and all the ends are prime.
  • Include repeated prime ends in your list.
  • Multiply the final primes to check the starting number.
  • A complete tree has only prime numbers at its ends.

Worked example

Build a tree for 18

Represent 1818 with a prime factor tree.
Prime ends for 18
Prime ends for 18Each bar shows one prime at the end of the tree. The values are stated factors in this example, not measured data.2 prime-number units23 prime-number units33 prime-number units3

Each bar shows one prime at the end of the tree. The values are stated factors in this example, not measured data.

  1. Choose a factor pair
    Split 1818 into 22 and 99. This is valid because their product is 1818. The 22 is prime, but the 99 is composite, so split only the 99.
    18=2×918 = 2 \times 9
  2. Finish the composite branch
    Split 99 into 33 and 33. Both are prime, so all the ends of the tree are now prime.
    9=3×39 = 3 \times 3
  3. Check the ends
    The ends are 22, 33, and 33. Their product is the starting number, so the tree is correct.
    2×3×3=182 \times 3 \times 3 = 18
Answer: One correct tree splits 1818 into 22 and 99, then splits 99 into 33 and 33. Its prime ends are 22, 33, and 33.
Check: The ends are all prime, and their product is 1818.

Worked example

Split two composite branches

Represent 4040 with a prime factor tree.
Prime ends for 40
Prime ends for 40Each bar shows one prime at the end of the tree. Repeated ends are shown separately. The values are stated factors, not measured data.2 prime-number units22 prime-number units22 prime-number units25 prime-number units5

Each bar shows one prime at the end of the tree. Repeated ends are shown separately. The values are stated factors, not measured data.

  1. Split the starting number
    Use 44 and 1010 as factors of 4040. Both are composite, so both branches need to be split again.
    40=4×1040 = 4 \times 10
  2. Split both branches
    Split 44 into 22 and 22. Split 1010 into 22 and 55. Each pair multiplies to make the number it splits.
    4=2×2,10=2×54 = 2 \times 2, \quad 10 = 2 \times 5
  3. Read and check the ends
    The ends are 22, 22, 22, and 55. They are all prime, and their product is 4040.
    2×2×2×5=402 \times 2 \times 2 \times 5 = 40
Answer: The prime ends are 22, 22, 22, and 55.
Check: Each split has the correct product, every end is prime, and the ends multiply to 4040.

Worked example

Choose a different first split

Represent 4545 with a prime factor tree. Begin with a pair other than 55 and 99.
Prime ends for 45
Prime ends for 45Each bar shows one prime at the end of the tree. Repeated ends are shown separately. The values are stated factors, not measured data.3 prime-number units33 prime-number units35 prime-number units5

Each bar shows one prime at the end of the tree. Repeated ends are shown separately. The values are stated factors, not measured data.

  1. Choose another factor pair
    Use 33 and 1515. This is a valid split because their product is 4545. The 33 is prime, but the 1515 is composite.
    45=3×1545 = 3 \times 15
  2. Split the composite branch
    Split 1515 into 33 and 55. Both are prime, so every end of the tree is now prime.
    15=3×515 = 3 \times 5
  3. Check the representation
    The ends are 33, 33, and 55. Multiplying them gives the starting number.
    3×3×5=453 \times 3 \times 5 = 45
Answer: One correct tree starts with 33 and 1515, then splits 1515 into 33 and 55. Its prime ends are 33, 33, and 55.
Check: Both splits are valid, all ends are prime, and their product is 4545.

Common mistakes and how to avoid them

Stopping when a branch ends in a composite number.
Correction: Split that branch again. A completed tree ends only in primes.
Choosing factors that do not multiply to the number above them.
Correction: Check every split by multiplying its two factors.
Leaving out a repeated prime when listing the ends.
Correction: Include each end, even when the same prime appears more than once.
Splitting a prime number further.
Correction: Leave the prime as an end of the tree.

Lesson summary

  • Split a composite number into factors that multiply to make it.
  • Keep splitting composite branches until all ends are prime.
  • List every prime end, including repeated primes.
  • Multiply the ends to check the starting number.

Check your understanding

Question 1

A tree for 2424 has ends 22, 22, 22, and 33. Which check confirms these are its prime factors?
  1. 2×2×2×3=242 \times 2 \times 2 \times 3 = 24, and all four numbers are prime.
  2. 2+2+2+3=242 + 2 + 2 + 3 = 24, and all four numbers are prime.
  3. The ends must all be different, so the tree is not complete.
  4. One end must be 2424 for the tree to be complete.
Show answer and explanation
2×2×2×3=242 \times 2 \times 2 \times 3 = 24, and all four numbers are prime.
The ends are prime, and their product is 2424. A prime may appear more than once.

Question 2

A factor tree for 3030 has ends 22, 33, and 55. Which branch, if any, should be split further?
  1. None. All the ends are prime.
  2. Only 22, because it is even.
  3. Only 33, because it has another factor pair.
  4. All three, because every factor must be split.
Show answer and explanation
None. All the ends are prime.
The ends are all prime, and their product is 3030. The tree is complete.

Question 3

A student splits 2828 into 44 and 77. What should the student do next?
  1. Split 44 into 22 and 22, and leave 77 as it is.
  2. Split 77 into 11 and 77, and leave 44 as it is.
  3. Stop because 44 and 77 are both prime.
  4. Change the first split because 44 and 77 do not multiply to 2828.
Show answer and explanation
Split 44 into 22 and 22, and leave 77 as it is.
The split is valid because 4×7=284 \times 7 = 28. The 44 is composite and splits into 22 and 22; 77 is already prime.

Key terms

Factor
A whole number multiplied by another whole number to make a product.
Prime number
A whole number greater than 11 with exactly two factors: 11 and itself.
Composite number
A whole number greater than 11 with more than two factors.
Factor tree
A branching way to split composite numbers into factors.
Prime factor
A prime number at the end of a completed factor tree.

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Published by DoAssignment. This reviewed lesson follows Ontario Grade 6 Mathematics, expectation B2.6. It is a study resource, not an official curriculum publication.

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