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C3.4 · Relate mass, gravitational field strength, and force of gravity

Learn to relate mass, gravitational field strength, and force of gravity through clear examples and targeted practice.

Ontario Grade 11 Physics

Forces

Understanding how an object's mass and the local gravitational field determine its weight

A book and a full backpack are both pulled toward Earth. The backpack usually experiences a larger force of gravity because it has more mass. To describe this clearly, we need three ideas: mass, gravitational field strength, and force of gravity. This lesson connects them with one simple relationship.

What you will learn

1. Prerequisite bridge: mass, force, and direction

A scalar is a quantity described by a size alone. Mass is a scalar. Its SI unit is the kilogram, written kg\mathrm{kg}. Mass describes how much matter an object contains. It does not point in a direction.
A vector has both a size and a direction. Force is a vector, and its SI unit is the newton, written N\mathrm{N}. The force of gravity is the force that a planet or other object exerts on a mass. Near Earth's surface, its direction is toward Earth's centre, which we usually describe as downward.
A gravitational field is the region where an object with mass experiences a force of gravity. Gravitational field strength describes the force of gravity on each kilogram of mass at a location. Its SI unit is newtons per kilogram, written N/kg\mathrm{N/kg}. Near Earth's surface, its value is about 9.8 N/kg9.8\ \mathrm{N/kg}, directed downward.
For calculations, define the system as the object whose force we are finding. Choose downward as the positive direction. Then downward forces have a positive sign. The gravitational field strength and force of gravity point in the positive direction. This sign choice is a description of direction, not a change in the physical force.

2. The relationship

The force of gravity on an object depends on its mass and the gravitational field strength where it is located. Multiply the mass by the field strength to find the force's magnitude. The force points in the same direction as the gravitational field.
In symbols, FgF_g means the magnitude of the force of gravity, mm means mass, and gg means the magnitude of gravitational field strength. The relationship is Fg=mgF_g=mg. If direction must be shown, state it in words or use a vector arrow: the force of gravity is downward near Earth's surface.
The units also support the relationship: multiplying kilograms by newtons per kilogram gives newtons. A greater mass in the same field has a greater force of gravity. For the same mass, a stronger gravitational field gives a greater force.
Mass and force of gravity are not the same thing. A person's mass can be the same in two places while the force of gravity differs if the gravitational field strength differs. In this lesson, use the provided field strength for the location rather than assuming every location has Earth's near-surface value.
Fg=mgF_g=mg

3. Choosing a direction and solving

Before calculating, identify the object, its mass, the field strength, and what is unknown. Write the units beside each known value. State the positive direction so the force's direction is clear.
A simple force diagram for an object near Earth's surface can be described in words: draw the object as a dot, then draw one arrow straight down from the dot and label it FgF_g. The arrow points in the same direction as the gravitational field. The arrow's length can represent the force's size, but no scale is implied unless one is stated.
Substitute values with their units. Keep the units during multiplication, then round the result to a sensible number of significant figures based on the given values. Report both the magnitude and direction. Finally, check the units and ask whether the result makes sense: a mass of several kilograms in Earth's field should have a force of gravity of several tens of newtons.

4. Rearranging the relationship

The same relationship can answer different questions. If force and field strength are known, divide the force magnitude by the field strength to find mass. If force and mass are known, divide the force magnitude by mass to find field strength.
These rearrangements use ordinary algebra. They do not change the meaning of the quantities. For example, finding a mass from a force still gives mass in kilograms, while finding field strength gives newtons per kilogram.
When a question gives a force direction, use it to describe the direction of the gravitational field as well: the gravitational force and field point the same way. Do not attach a direction to mass, because mass is a scalar.
m=Fg/g,g=Fg/mm=F_g/g,\quad g=F_g/m

Worked example

Finding the force of gravity near Earth's surface

A 6.2 kg6.2\ \mathrm{kg} toolbox is near Earth's surface, where the gravitational field strength is 9.8 N/kg9.8\ \mathrm{N/kg} downward. Find the force of gravity on it.
  1. Set up
    The system is the toolbox. Choose downward as positive. The known values are its mass and the local field strength; the unknown is the force of gravity.
    m=6.2 kg,g=9.8 N/kgm=6.2\ \mathrm{kg},\quad g=9.8\ \mathrm{N/kg}
  2. Apply the relationship
    The magnitude of gravitational force is mass multiplied by field strength. The force points downward because the field points downward.
    Fg=mg=(6.2 kg)(9.8 N/kg)F_g=mg=(6.2\ \mathrm{kg})(9.8\ \mathrm{N/kg})
  3. Calculate and check
    The product is 60.76 N60.76\ \mathrm{N}. Round to two significant figures, matching the given mass. The units reduce to newtons, and a force of about 61 N61\ \mathrm{N} is reasonable for a few kilograms in Earth's field.
    Fg≈61 NF_g\approx61\ \mathrm{N}
Answer: The toolbox experiences a force of gravity of 61 N61\ \mathrm{N} downward.
Check: The result is in newtons, points downward, and is close to the expected several tens of newtons for a 6.2 kg6.2\ \mathrm{kg} object near Earth.

Worked example

Finding mass from gravitational force

An object experiences a gravitational force of 147 N147\ \mathrm{N} downward in a field of 9.8 N/kg9.8\ \mathrm{N/kg} downward. Find its mass.
  1. Set up
    The system is the object. Choose downward as positive. The force magnitude and field strength are known, and mass is the unknown scalar.
    Fg=147 N,g=9.8 N/kgF_g=147\ \mathrm{N},\quad g=9.8\ \mathrm{N/kg}
  2. Rearrange
    Starting with the force relationship, divide both sides by field strength. The units become kilograms because newtons divided by newtons per kilogram gives kilograms.
    m=Fgg=147 N9.8 N/kgm=\frac{F_g}{g}=\frac{147\ \mathrm{N}}{9.8\ \mathrm{N/kg}}
  3. Calculate and check
    The quotient is 15 kg15\ \mathrm{kg}. The given values each have two significant figures, so the answer is reported to two significant figures. A mass of 15 kg15\ \mathrm{kg} would experience about 150 N150\ \mathrm{N} of force in this field, which is reasonable.
    m=15 kgm=15\ \mathrm{kg}
Answer: The object's mass is 15 kg15\ \mathrm{kg}.
Check: Mass is a scalar and has units of kilograms. Multiplying the answer by 9.8 N/kg9.8\ \mathrm{N/kg} returns 147 N147\ \mathrm{N} downward.

Worked example

Finding field strength from force and mass

A 4.0 kg4.0\ \mathrm{kg} object experiences a force of gravity of 12 N12\ \mathrm{N} downward at a location. Find the gravitational field strength there.
  1. Set up
    The system is the object, and downward is positive. The force magnitude and mass are known. The field strength is the unknown, and its direction is downward because the force points downward.
    Fg=12 N,m=4.0 kgF_g=12\ \mathrm{N},\quad m=4.0\ \mathrm{kg}
  2. Rearrange
    Divide the force magnitude by mass to find the force of gravity per kilogram. This gives the field strength's magnitude.
    g=Fgm=12 N4.0 kgg=\frac{F_g}{m}=\frac{12\ \mathrm{N}}{4.0\ \mathrm{kg}}
  3. Calculate and check
    The quotient is 3.0 N/kg3.0\ \mathrm{N/kg}. It has two significant figures. The value is less than Earth's near-surface value, so it describes a weaker field than the one used in the first example. Its direction remains downward.
    g=3.0 N/kgg=3.0\ \mathrm{N/kg}
Answer: The gravitational field strength is 3.0 N/kg3.0\ \mathrm{N/kg} downward.
Check: The units are newtons per kilogram. Multiplying by 4.0 kg4.0\ \mathrm{kg} gives 12 N12\ \mathrm{N} downward, as stated.

Common mistakes and how to avoid them

Treating mass and force of gravity as interchangeable.
Correction: Mass is a scalar in kilograms. Force of gravity is a vector in newtons.
Reporting a gravitational force without its direction.
Correction: State the direction as well as the magnitude. Near Earth's surface, gravitational force points downward.
Using the wrong units for field strength.
Correction: Use newtons per kilogram for gravitational field strength, not kilograms or newtons.
Assuming the field strength is always the same wherever an object is.
Correction: Use the field strength given for the object's location. The force depends on both mass and local field strength.
Rounding too early or omitting a final check.
Correction: Keep the calculator value until the final step. Then round sensibly and check units, direction, and reasonableness.

Lesson summary

Check your understanding

Question 1

A 2.0 kg2.0\ \mathrm{kg} object is in a field of 9.8 N/kg9.8\ \mathrm{N/kg} downward. What is its force of gravity?
  1. 4.9 N4.9\ \mathrm{N} downward
  2. 20 N20\ \mathrm{N} downward
  3. 20 N/kg20\ \mathrm{N/kg} downward
  4. 2.0 N2.0\ \mathrm{N} upward
Show answer and explanation
20 N20\ \mathrm{N} downward
Use Fg=mgF_g=mg. The product is 19.6 N19.6\ \mathrm{N}, which rounds to 20 N20\ \mathrm{N} to two significant figures. Its direction is downward.

Question 2

An object has a force of gravity of 30 N30\ \mathrm{N} downward in a field of 10 N/kg10\ \mathrm{N/kg} downward. What is its mass?
  1. 3.0 kg3.0\ \mathrm{kg}
  2. 300 kg300\ \mathrm{kg}
  3. 0.33 kg0.33\ \mathrm{kg}
  4. 3.0 N/kg3.0\ \mathrm{N/kg}
Show answer and explanation
3.0 kg3.0\ \mathrm{kg}
Divide force magnitude by field strength: 30 N/(10 N/kg)=3.0 kg30\ \mathrm{N}/(10\ \mathrm{N/kg})=3.0\ \mathrm{kg}. Mass has no direction.

Question 3

Which statement correctly describes gravitational field strength?
  1. It is the mass of an object, measured in kilograms.
  2. It is the force of gravity per kilogram, measured in newtons per kilogram.
  3. It is the force of gravity, measured only in kilograms.
  4. It is always directed upward near Earth's surface.
Show answer and explanation
It is the force of gravity per kilogram, measured in newtons per kilogram.
Gravitational field strength describes force of gravity per unit mass. Near Earth's surface, its direction is downward.

Key terms

Scalar
A quantity with size but no direction.
Vector
A quantity with both size and direction.
Mass
A scalar describing how much matter an object contains, measured in kilograms.
Gravitational field
A region where an object with mass experiences a force of gravity.
Gravitational field strength
The force of gravity per kilogram at a location, measured in newtons per kilogram.
Force of gravity
The force exerted on an object with mass by a gravitational field, measured in newtons.

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Published by DoAssignment. This AI-assisted lesson follows Ontario Grade 11 Physics (SPH3U), expectation C3.4. It is a study resource, not an official curriculum publication.

Before publication, the draft is checked for structure, mathematical or chemical notation, calculations, course boundaries, and readability, and then requires administrator approval. Errors can still occur, so corrections are welcomed.

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