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D2.5 · Calculate current, voltage, or resistance in context

Learn to calculate current, voltage, or resistance in context through clear examples and targeted practice.

Ontario Grade 9 Science

Physics: Principles and Applications of Electricity

Ontario Grade 9 Science — study topic D2.5

A battery-powered lamp glows when it is connected in a complete circuit. A circuit is a complete path through which electric charge can move. This raises a useful science question: if we know two electrical values, how can we calculate the third? We will use simple models and hypothetical values. Do not open outlets, handle exposed wires, or connect household electricity to a circuit.

What you will learn

  • Describe current, voltage, and resistance in a simple circuit.
  • Calculate one of these quantities when the other two are given.
  • Use suitable units and check whether a result fits the context.

1. Begin with a simple circuit

A simple circuit can include a source, such as a battery, connected to one component, such as a lamp. The source supplies electrical energy. A resistor is a component that makes it harder for current to flow. In the examples, the circuit is treated as a simple model with one source and one component.
Current tells us how much electric charge flows past a point over time. Its symbol is II. Current is measured in amperes, abbreviated A. A smaller unit is the milliampere, abbreviated mA. One ampere equals 1,000 milliamperes.
Voltage describes the energy supplied to or transferred by electric charge. Its symbol is VV. Voltage is measured in volts, also abbreviated V. For the simple examples here, the source voltage is the voltage across the single component.
Resistance describes how much a component opposes current. Its symbol is RR. Resistance is measured in ohms, shown by the symbol Ω. In this model, if voltage stays the same, a component with more resistance has less current.
These descriptions are useful for calculations, but they simplify real circuits. A circuit drawing does not show the detailed motion of every charge or every change inside a component. A calculated value is not the same as a measurement.
  • Current is measured in amperes (A).
  • Voltage is measured in volts (V).
  • Resistance is measured in ohms (Ω).

2. Choose a form of the relationship

For the simple circuit situations in this lesson, current, voltage, and resistance are related. The relationship can be written in different forms depending on which quantity is unknown.
First, mark the two known values and the quantity the question asks you to find. Choose the form that puts the unknown by itself. Substitute the known numbers with their units, calculate, and write the answer with its unit.
Keep units consistent. When using volts and ohms in these calculations, convert current from milliamperes to amperes first. For example, 250 mA is 0.250 A. Keeping units beside the numbers helps prevent mistakes.
Check the result against the situation. If the voltage is unchanged, increasing resistance should reduce the calculated current in this model. Check that the final unit matches the quantity: amperes for current, volts for voltage, and ohms for resistance.
V=IR,I=VR,R=VIV=IR,\qquad I=\frac{V}{R},\qquad R=\frac{V}{I}
  • Identify the unknown before choosing a form.
  • Convert milliamperes to amperes when needed.
  • Include the correct unit and check whether the result makes sense.

3. Understand what a calculation can show

A calculation gives a value based on the numbers provided and the model being used. It can help us compare situations. For example, we can calculate how current would change if resistance changed while voltage stayed the same.
A hypothetical practice problem is not an experiment. Scientific evidence comes from observations or measurements gathered in a suitable investigation. A calculation alone cannot show whether a real connection is loose or whether a component changed during use.
A model is a simplified representation of a situation. It helps answer a focused question but leaves out details. A social or ethical judgment, such as whether a product is a good choice, cannot be settled by a current, voltage, or resistance calculation alone.
  • Calculated results depend on the given values and model.
  • Hypothetical values are practice, not measured evidence.
  • A calculation does not answer every practical or social question.

Worked example

Calculate current for a lamp

A simple circuit has a 6.0 V source and a lamp with a resistance of 12 Ω. What current does the model predict?
One source and one lamp
One source and one lampSchematic path from source through lamp and back to source. Not to scale; it does not show charge motion in detail.6.0 V source12 ΩSeries path

Schematic path from source through lamp and back to source. Not to scale; it does not show charge motion in detail.

  1. Identify the unknown
    The question asks for current. Voltage and resistance are given, so use the form with current by itself.
    I=VRI=\frac{V}{R}
  2. Substitute and calculate
    Divide the voltage by the resistance. In this relationship, volts divided by ohms gives amperes.
    I=6.0 V12 Ω=0.50 AI=\frac{6.0\text{ V}}{12\text{ Ω}}=0.50\text{ A}
  3. State the result
    The simple model predicts a current of 0.50 A. This is calculated from the stated values; it is not a measurement of a real lamp.
Answer: The predicted current is 0.50 A.
Check: The answer is in amperes. At the same voltage, a larger resistance would give a smaller current in this model.

Worked example

Calculate resistance from voltage and current

A component has 9.0 V across it, and the current is 0.30 A. Calculate its resistance.
One source and one component
One source and one componentSchematic path from source through the component and back. Not to scale; values are hypothetical, not measurements.9.0 V source30 Ω componentSeries path

Schematic path from source through the component and back. Not to scale; values are hypothetical, not measurements.

  1. Choose the resistance form
    Resistance is unknown, while voltage and current are given. Divide voltage by current.
    R=VIR=\frac{V}{I}
  2. Substitute the values
    Divide 9.0 volts by 0.30 amperes. This gives resistance in ohms.
    R=9.0 V0.30 A=30 ΩR=\frac{9.0\text{ V}}{0.30\text{ A}}=30\text{ Ω}
  3. Check the result
    The answer is in ohms. Multiplying 30 Ω by 0.30 A gives the stated 9.0 V, so the values agree with the relationship.
Answer: The component's resistance is 30 Ω.
Check: The units are ohms, as required for resistance.

Worked example

Calculate voltage from current and resistance

A simple circuit model gives a current of 0.25 A through a component with a resistance of 16 Ω. What voltage is across the component?
One source and one component
One source and one componentSchematic path from source through the component and back. Not to scale; values are hypothetical, not measurements.4.0 V source16 Ω componentSeries path

Schematic path from source through the component and back. Not to scale; values are hypothetical, not measurements.

  1. Choose the voltage form
    Voltage is unknown, and current and resistance are known. Multiply current by resistance.
    V=IRV=IR
  2. Calculate
    Multiply 0.25 amperes by 16 ohms. The result is in volts.
    V=(0.25 A)(16 Ω)=4.0 VV=(0.25\text{ A})(16\text{ Ω})=4.0\text{ V}
  3. Interpret the value
    The simple model gives 4.0 V across the component. The result depends on the supplied values and model.
Answer: The voltage is 4.0 V.
Check: The answer is in volts. Substituting 4.0 V and 16 Ω into the current form gives 0.25 A.

Common mistakes and how to avoid them

Multiplying for every unknown.
Correction: Choose the form that matches the unknown. The current and resistance forms use division.
Using milliamperes as though they were amperes.
Correction: Convert first. For example, 300 mA is 0.300 A.
Leaving off the unit.
Correction: Write A for current, V for voltage, or Ω for resistance.
Calling a calculated answer a measurement.
Correction: Say whether values are given, hypothetical, or measured. Calculation uses values; it does not collect them.

Lesson summary

  • Current, voltage, and resistance describe different electrical quantities.
  • Use their relationship to calculate an unknown when the other two are known.
  • Check the arithmetic, unit, and meaning of the result.

Check your understanding

Question 1

A component has 8.0 V across it and a resistance of 20 Ω. What current does the model predict?
  1. 0.40 A
  2. 2.5 A
  3. 160 A
  4. 28 A
Show answer and explanation
0.40 A
Divide voltage by resistance: 8.0 V ÷ 20 Ω = 0.40 A.

Question 2

A component has 12 V across it and a current of 0.50 A. What is its resistance?
  1. 6.0 Ω
  2. 24 Ω
  3. 12.5 Ω
  4. 0.042 Ω
Show answer and explanation
24 Ω
Divide voltage by current: 12 V ÷ 0.50 A = 24 Ω.

Question 3

A component has a resistance of 10 Ω and a current of 0.20 A. What voltage is across it?
  1. 0.020 V
  2. 2.0 V
  3. 10.2 V
  4. 50 V
Show answer and explanation
2.0 V
Multiply current by resistance: 0.20 A × 10 Ω = 2.0 V.

Key terms

Circuit
A complete path through which electric charge can move.
Current
A measure of electric charge flowing past a point; measured in amperes.
Voltage
A measure of energy supplied to or transferred by electric charge; measured in volts.
Resistance
A measure of how much a component opposes current; measured in ohms.
Resistor
A circuit component that makes it harder for current to flow.

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Published by DoAssignment. This reviewed lesson follows Ontario Grade 9 Science (SNC1W), expectation D2.5. It is a study resource, not an official curriculum publication.

Before publication, content is checked for structure, mathematical or chemical notation, calculations, course boundaries, and readability. Errors can still occur, so corrections are welcomed.

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