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SL 3.5 · Use the unit circle and exact trigonometric values

Learn to use the unit circle and exact trigonometric values through clear examples and targeted practice.

International Baccalaureate (IB) IB AA SL: Mathematics: Analysis and Approaches SL

Geometry and Trigonometry

A visual and analytical guide for IB Mathematics: Analysis and Approaches SL, topic SL 3.5

This lesson focuses on using the unit circle and exact trigonometric values. You should already know that angles can be measured in degrees or radians and that a right-angled triangle has side ratios called sine, cosine, and tangent. On the unit circle, these ideas extend to angles in every direction around a circle. The circle gives a reliable way to identify exact values and their signs. Unless an angle is explicitly in degrees, angles in formulas in this lesson are in radians.

What you will learn

1. Prior knowledge: angles and side ratios

An angle describes a turn from a starting direction. One full turn is 360∘360^\circ or 2π2\pi radians, so 180∘=π180^\circ=\pi radians. A positive angle is measured anticlockwise from the positive horizontal direction. For example, π2\frac{\pi}{2} radians is a quarter-turn.
In a right-angled triangle, sine is opposite side divided by hypotenuse, cosine is adjacent side divided by hypotenuse, and tangent is opposite side divided by adjacent side. The unit circle keeps the same sine and cosine relationships, but makes them usable for angles in all four quadrants.
180∘=π radians180^\circ=\pi\text{ radians}

2. The unit circle and exact values

The unit circle is the circle of radius 11 centred at the origin of a coordinate plane. A point reached by turning through an angle θ\theta from the positive horizontal direction has coordinates (cos⁡θ,sin⁡θ)(\cos\theta,\sin\theta). Therefore, the horizontal coordinate gives cosine and the vertical coordinate gives sine. Tangent is the ratio of these coordinates when cosine is not zero.
The signs follow from the point's location: in the upper half of the circle sine is positive, and in the lower half it is negative. Cosine is positive on the right half and negative on the left. Tangent is positive when sine and cosine have the same sign, and negative when their signs differ.
The familiar exact values come from special right triangles. For angles in the first quadrant, the values at π6\frac{\pi}{6}, π4\frac{\pi}{4}, and π3\frac{\pi}{3} follow from triangles with side ratios 1:3:21:\sqrt{3}:2 and 1:1:21:1:\sqrt{2}. At the axis angles, the coordinates are read directly from the circle. Knowing these values lets you give exact answers rather than rounded calculator decimals.
To use a standard value at an angle outside the first quadrant, find its reference angle: the acute angle between the terminal side and the horizontal axis. The reference angle supplies the size of the sine and cosine values; the quadrant supplies their signs. For instance, an angle in the second quadrant has the same reference-angle sine as its first-quadrant partner, but its cosine is negative.
(cos⁡θ,sin⁡θ)(\cos\theta,\sin\theta)

3. Read values in symbolic, numerical, and graphical forms

A standard-angle table is a compact numerical record of the unit-circle coordinates. It is useful to learn the first-quadrant entries and then apply the quadrant signs. At 00 the point is (1,0)(1,0); at π2\frac{\pi}{2} it is (0,1)(0,1); at π\pi it is (−1,0)(-1,0); and at 3π2\frac{3\pi}{2} it is (0,−1)(0,-1). These values also help you locate the axes before interpreting any other angle.
The graph of y=sin⁡θy=\sin\theta records the vertical coordinate as the angle changes, while y=cos⁡θy=\cos\theta records the horizontal coordinate. A graphing calculator can check an angle's approximate value or show whether a sign is plausible. Set the angle mode to radians when entering radian measures. The graph or decimal is a check: the unit-circle reasoning is what establishes an exact answer.
In a context, a point moving around a circle of radius 11 has horizontal and vertical coordinates given by cosine and sine. If the circle has radius rr, the corresponding coordinates are rcos⁡θr\cos\theta and rsin⁡θr\sin\theta when its centre is at the origin. The radius and angle determine the position; the trigonometric values themselves remain dimensionless.
(x,y)=(rcos⁡θ,rsin⁡θ)(x,y)=(r\cos\theta,r\sin\theta)

4. A reliable method and technology check

For an exact-value question, first identify the angle's quadrant and, when useful, its reference angle. Match the reference angle to a standard value, then apply the correct sign. For a sum or difference of exact values, evaluate each trigonometric value before doing the arithmetic. Keep roots and fractions exact until the question asks for an approximation.
To check with technology, enter the angle in the correct mode and compare the calculator's decimal with the exact value's approximate size. A graph can also show whether the angle lies where the relevant function is positive or negative. For example, a second-quadrant angle should have positive sine and negative cosine. If the calculator gives the opposite signs, check the angle mode and the quadrant reasoning.

Standard first-quadrant values and axis values

Angle θ\thetacos⁡θ\cos\thetasin⁡θ\sin\thetatan⁡θ\tan\theta
00110000
π6\frac{\pi}{6}32\frac{\sqrt{3}}{2}12\frac{1}{2}33\frac{\sqrt{3}}{3}
π4\frac{\pi}{4}22\frac{\sqrt{2}}{2}22\frac{\sqrt{2}}{2}11
π3\frac{\pi}{3}12\frac{1}{2}32\frac{\sqrt{3}}{2}3\sqrt{3}
π2\frac{\pi}{2}0011Undefined

Worked example

Find values in the second quadrant

Find the exact values of sin⁡(5π6)\sin\left(\frac{5\pi}{6}\right) and cos⁡(5π6)\cos\left(\frac{5\pi}{6}\right).
  1. Locate the angle
    The angle 5π6\frac{5\pi}{6} is between π2\frac{\pi}{2} and π\pi, so its terminal side is in the second quadrant. Its reference angle is the difference between π\pi and the given angle.
    π−5π6=π6\pi-\frac{5\pi}{6}=\frac{\pi}{6}
  2. Use the standard values and signs
    At the reference angle π6\frac{\pi}{6}, sine is 12\frac{1}{2} and cosine is 32\frac{\sqrt{3}}{2}. In the second quadrant sine is positive and cosine is negative.
    sin⁡(5π6)=12,cos⁡(5π6)=−32\sin\left(\frac{5\pi}{6}\right)=\frac{1}{2},\quad \cos\left(\frac{5\pi}{6}\right)=-\frac{\sqrt{3}}{2}
Answer: sin⁡(5π6)=12\sin\left(\frac{5\pi}{6}\right)=\frac{1}{2} and cos⁡(5π6)=−32\cos\left(\frac{5\pi}{6}\right)=-\frac{\sqrt{3}}{2}.
Check: The point is in the upper-left part of the circle, so its vertical coordinate is positive and its horizontal coordinate is negative.

Worked example

Use a reference angle in the fourth quadrant

Find the exact value of tan⁡(7π4)\tan\left(\frac{7\pi}{4}\right).
  1. Identify the reference angle
    The angle 7π4\frac{7\pi}{4} lies in the fourth quadrant. Its reference angle is the difference between one full turn and the angle.
    2π−7π4=π42\pi-\frac{7\pi}{4}=\frac{\pi}{4}
  2. Apply the tangent value and sign
    At π4\frac{\pi}{4}, sine and cosine are both 22\frac{\sqrt{2}}{2}, so tangent has magnitude 11. In the fourth quadrant sine is negative and cosine is positive, making tangent negative.
    tan⁡(7π4)=−1\tan\left(\frac{7\pi}{4}\right)=-1
Answer: −1-1
Check: The coordinates have opposite signs, so their ratio, tangent, must be negative.

Worked example

Combine exact values

Evaluate sin⁡(π3)+cos⁡(π6)\sin\left(\frac{\pi}{3}\right)+\cos\left(\frac{\pi}{6}\right) exactly.
  1. Substitute standard values
    Both angles are standard first-quadrant angles. The sine of π3\frac{\pi}{3} and the cosine of π6\frac{\pi}{6} are each 32\frac{\sqrt{3}}{2}.
    32+32\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}
  2. Add like terms
    The denominators are equal, so add the numerators and retain the common denominator. The result is exact, so no rounding is needed.
    232=3\frac{2\sqrt{3}}{2}=\sqrt{3}
Answer: 3\sqrt{3}
Check: Since each term is about 0.8660.866, their sum is about 1.7321.732, consistent with 3\sqrt{3}.

Common mistakes and how to avoid them

Giving cosine a positive sign in the second quadrant because its reference angle has positive cosine.
Correction: The reference angle gives the magnitude. The actual quadrant determines the sign; cosine is negative in the second quadrant.
Using a calculator decimal when an exact value is requested.
Correction: Write the exact fraction or surd first. Use a decimal only when the question asks for an approximation or as a check.
Entering radians while the calculator is set to degrees, or the reverse.
Correction: Check the angle mode before calculating. A mismatch can produce a plausible-looking but incorrect decimal.
Treating tangent as defined at π2\frac{\pi}{2}.
Correction: Tangent is sine divided by cosine, and cosine is zero at π2\frac{\pi}{2}. Division by zero is undefined.

Lesson summary

Check your understanding

Question 1

What is the exact value of cos⁡(2π3)\cos\left(\frac{2\pi}{3}\right)?
  1. 12\frac{1}{2}
  2. −12-\frac{1}{2}
  3. 32\frac{\sqrt{3}}{2}
  4. −32-\frac{\sqrt{3}}{2}
Show answer and explanation
−12-\frac{1}{2}
The reference angle is π3\frac{\pi}{3}, whose cosine is 12\frac{1}{2}. The angle is in the second quadrant, where cosine is negative.

Question 2

What is the exact value of sin⁡(3π2)\sin\left(\frac{3\pi}{2}\right)?
  1. 11
  2. 00
  3. −1-1
  4. Undefined
Show answer and explanation
−1-1
At the bottom of the unit circle the point is (0,−1)(0,-1), so its vertical coordinate, sine, is −1-1.

Question 3

A calculator is set to radians. Which sign should its value for cos⁡(5π4)\cos\left(\frac{5\pi}{4}\right) have?
  1. Positive, because the angle is greater than π\pi
  2. Negative, because the angle is in the third quadrant
  3. Zero, because the angle is halfway around the circle
  4. Positive, because cosine is always positive
Show answer and explanation
Negative, because the angle is in the third quadrant
The angle is in the third quadrant, where the horizontal coordinate and hence cosine are negative.

Key terms

Unit circle
A circle of radius 11 centred at the origin of a coordinate plane.
Reference angle
The acute angle between an angle's terminal side and the horizontal axis.
Exact value
A value written without rounding, often as an integer, fraction, or root.
Terminal side
The direction reached after turning through an angle from the positive horizontal direction.

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Published by DoAssignment. This AI-assisted lesson follows International Baccalaureate (IB) IB AA SL: Mathematics: Analysis and Approaches SL, study topic SL 3.5. It is a study resource, not an official curriculum publication.

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