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SL 3.6 · Apply fundamental and double-angle trigonometric identities

Learn to apply fundamental and double-angle trigonometric identities through clear examples and targeted practice.

International Baccalaureate (IB) IB AA SL: Mathematics: Analysis and Approaches SL

Geometry and Trigonometry

Using familiar trigonometric relationships to rewrite and evaluate expressions

An identity is an equality that is true for every value in its stated domain. Trigonometric identities let you rewrite an expression without changing its value. This lesson focuses on the fundamental relationships between sine, cosine, and tangent, and on formulas for the sine, cosine, and tangent of twice an angle. The aim is not simply to remember formulas: it is to recognize which form makes a calculation or simplification easier. Angles may be measured in degrees or radians; keep the chosen unit consistent, particularly when using a calculator.

What you will learn

1. Prior knowledge: sine, cosine, and tangent

For an angle θ\theta, sine, cosine, and tangent are written sin⁡θ\sin\theta, cos⁡θ\cos\theta, and tan⁡θ\tan\theta. On a right-angled triangle, sine is opposite over hypotenuse, cosine is adjacent over hypotenuse, and tangent is opposite over adjacent. The quotient relationship between tangent and the other two functions is useful even when working with angles beyond a right triangle.
A fundamental identity is sin⁡2θ+cos⁡2θ=1\sin^2\theta+\cos^2\theta=1. The notation sin⁡2θ\sin^2\theta means (sin⁡θ)2(\sin\theta)^2, not sin⁡(θ2)\sin(\theta^2). The identity applies for every real angle.
Tangent is defined by tan⁡θ=sin⁡θcos⁡θ\tan\theta=\frac{\sin\theta}{\cos\theta} wherever cos⁡θ≠0\cos\theta\ne 0. This restriction matters: tangent is undefined when the denominator is zero. Rearranging the fundamental identity and dividing by cos⁡2θ\cos^2\theta also gives 1+tan⁡2θ=1cos⁡2θ1+\tan^2\theta=\frac{1}{\cos^2\theta} where cos⁡θ≠0\cos\theta\ne0. This form can be useful when an expression contains tangent.
sin⁡2θ+cos⁡2θ=1,tan⁡θ=sin⁡θcos⁡θ\sin^2\theta+\cos^2\theta=1,\qquad \tan\theta=\frac{\sin\theta}{\cos\theta}

2. The double-angle identities

A double angle means twice a given angle, written 2θ2\theta. The angle-addition relationships for sine and cosine lead to formulas for sin⁡(2θ)\sin(2\theta) and cos⁡(2θ)\cos(2\theta). In these formulas, the same angle θ\theta appears in each factor.
The cosine double-angle identity has three equivalent forms. The first uses both sine and cosine. Replacing sin⁡2θ\sin^2\theta using sin⁡2θ=1−cos⁡2θ\sin^2\theta=1-\cos^2\theta gives a form involving cosine alone; replacing cos⁡2θ\cos^2\theta gives one involving sine alone. Choose the form that matches the information you have.
For tangent, divide the sine double-angle formula by the cosine double-angle formula and use tan⁡θ=sin⁡θ/cos⁡θ\tan\theta=\sin\theta/\cos\theta. This gives a compact expression, but its denominator must not be zero, and the original tangent must be defined. Check these restrictions when using the formula.
These are algebraic relationships, not estimates. For a specified angle, calculate the original expression and its identity-based form to see that the values agree. On graphs, the curves for the two sides of an identity lie on top of each other wherever both sides are defined.
sin⁡(2θ)=2sin⁡θcos⁡θ,cos⁡(2θ)=cos⁡2θ−sin⁡2θ=1−2sin⁡2θ=2cos⁡2θ−1,tan⁡(2θ)=2tan⁡θ1−tan⁡2θ\sin(2\theta)=2\sin\theta\cos\theta,\quad \cos(2\theta)=\cos^2\theta-\sin^2\theta=1-2\sin^2\theta=2\cos^2\theta-1,\quad \tan(2\theta)=\frac{2\tan\theta}{1-\tan^2\theta}

3. Choosing a representation and checking results

Symbolically, use identities to change the form of an expression while preserving its value. Numerically, substitute an angle and evaluate both forms, keeping sufficient calculator precision until the final answer. A small difference in displayed decimal values may result from rounding, not a failure of the identity.
Graphing technology can provide a useful check. Enter the two sides of an identity as separate functions of the same angle, and use the same angle mode and viewing window. If one side is undefined at some angles, a graph may show a gap or fail to draw there; that does not disprove the identity on its valid domain.
In a context, an angle might describe a direction or a repeated rotation. If the original angle is θ\theta, a double-angle expression concerns 2θ2\theta, in the same unit. Identities help evaluate or rewrite the expression, but they do not change the meaning or units of the angle.
A reliable exam approach is to identify the information given, select a matching identity, substitute carefully, and simplify using ordinary algebra. Finish by checking restrictions and, when appropriate, checking the result numerically. A calculator supports the reasoning; it does not replace showing the identity and algebra used.

Worked example

1. Evaluate a double-angle expression exactly

Given sin⁡θ=35\sin\theta=\frac{3}{5} and that θ\theta is acute, find cos⁡(2θ)\cos(2\theta) exactly.
  1. Find the missing trigonometric value
    Because θ\theta is acute, its cosine is positive. Use the fundamental identity to determine cosine from the given sine.
    cos⁡2θ=1−(35)2=1625,cos⁡θ=45\cos^2\theta=1-\left(\frac{3}{5}\right)^2=\frac{16}{25},\qquad \cos\theta=\frac{4}{5}
  2. Select a suitable cosine form
    Both sine and cosine are now known, so use the form involving their squares. This avoids first calculating the doubled angle.
    cos⁡(2θ)=cos⁡2θ−sin⁡2θ\cos(2\theta)=\cos^2\theta-\sin^2\theta
  3. Substitute and simplify
    Substitute the exact values and subtract the fractions with the same denominator.
    cos⁡(2θ)=(45)2−(35)2=725\cos(2\theta)=\left(\frac{4}{5}\right)^2-\left(\frac{3}{5}\right)^2=\frac{7}{25}
Answer: cos⁡(2θ)=725\cos(2\theta)=\frac{7}{25}.
Check: The result is between −1-1 and 11, as a cosine value must be. The acute-angle condition selected the positive value of cos⁡θ\cos\theta.

Worked example

2. Rewrite an expression using double-angle identities

Rewrite 2sin⁡xcos⁡x+cos⁡2x−sin⁡2x2\sin x\cos x+\cos^2x-\sin^2x as a sum of trigonometric functions of the doubled angle.
  1. Recognize the sine double angle
    The product term matches the formula for the sine of twice the angle.
    2sin⁡xcos⁡x=sin⁡(2x)2\sin x\cos x=\sin(2x)
  2. Recognize the cosine double angle
    The difference of the squared cosine and squared sine matches the cosine double-angle formula.
    cos⁡2x−sin⁡2x=cos⁡(2x)\cos^2x-\sin^2x=\cos(2x)
  3. Combine the rewritten terms
    Apply both identities to the original expression. The result is a sum of sine and cosine functions of the same doubled angle.
    2sin⁡xcos⁡x+cos⁡2x−sin⁡2x=sin⁡(2x)+cos⁡(2x)2\sin x\cos x+\cos^2x-\sin^2x=\sin(2x)+\cos(2x)
Answer: The expression rewrites as sin⁡(2x)+cos⁡(2x)\sin(2x)+\cos(2x).
Check: At x=0x=0, the original expression equals 11 and the rewritten expression is sin⁡0+cos⁡0=1\sin 0+\cos 0=1.

Worked example

3. Apply the tangent double-angle identity

Given tan⁡θ=13\tan\theta=\frac{1}{3}, find tan⁡(2θ)\tan(2\theta), assuming the angles are in radians.
  1. Check the formula's denominator
    The tangent double-angle formula requires 1−tan⁡2θ≠01-\tan^2\theta\ne0. With the given value, the denominator is nonzero.
    1−(13)2=89≠01-\left(\frac{1}{3}\right)^2=\frac{8}{9}\ne0
  2. Substitute into the identity
    Use the given tangent in the numerator and denominator of the double-angle formula.
    tan⁡(2θ)=2(13)1−(13)2\tan(2\theta)=\frac{2\left(\frac{1}{3}\right)}{1-\left(\frac{1}{3}\right)^2}
  3. Simplify the fraction
    Divide by multiplying by the reciprocal of the denominator.
    tan⁡(2θ)=23⋅98=34\tan(2\theta)=\frac{2}{3}\cdot\frac{9}{8}=\frac{3}{4}
Answer: tan⁡(2θ)=34\tan(2\theta)=\frac{3}{4}.
Check: As a numerical check, an angle with tangent 1/31/3 is approximately 0.3220.322 radians. Doubling gives approximately 0.6440.644 radians, whose tangent is approximately 0.7500.750.

Common mistakes and how to avoid them

Writing sin⁡(2θ)=2sin⁡θ\sin(2\theta)=2\sin\theta.
Correction: The sine double-angle formula includes both sine and cosine: sin⁡(2θ)=2sin⁡θcos⁡θ\sin(2\theta)=2\sin\theta\cos\theta.
Treating sin⁡2θ\sin^2\theta as sin⁡(θ2)\sin(\theta^2).
Correction: The square is applied after evaluating sine: sin⁡2θ=(sin⁡θ)2\sin^2\theta=(\sin\theta)^2.
Using tan⁡(2θ)=2tan⁡θ1−tan⁡2θ\tan(2\theta)=\frac{2\tan\theta}{1-\tan^2\theta} without checking whether the denominator is zero.
Correction: Check 1−tan⁡2θ≠01-\tan^2\theta\ne0, and make sure the tangent values involved are defined.
Assuming a rounded calculator check proves an identity.
Correction: Show the identity and algebraic reasoning. Use numerical or graphical checks only as supporting evidence.

Lesson summary

Check your understanding

Question 1

If sin⁡θ=513\sin\theta=\frac{5}{13} and θ\theta is acute, what is cos⁡(2θ)\cos(2\theta)?
  1. 119169\frac{119}{169}
  2. 144169\frac{144}{169}
  3. −119169-\frac{119}{169}
  4. 1013\frac{10}{13}
Show answer and explanation
119169\frac{119}{169}
The fundamental identity gives cos⁡θ=12/13\cos\theta=12/13. Therefore cos⁡(2θ)=cos⁡2θ−sin⁡2θ=(144−25)/169=119/169\cos(2\theta)=\cos^2\theta-\sin^2\theta=(144-25)/169=119/169.

Question 2

Which expression equals sin⁡(2x)\sin(2x)?
  1. 2sin⁡xcos⁡x2\sin x\cos x
  2. sin⁡2x+cos⁡2x\sin^2x+\cos^2x
  3. 2sin⁡x2\sin x
  4. cos⁡2x−sin⁡2x\cos^2x-\sin^2x
Show answer and explanation
2sin⁡xcos⁡x2\sin x\cos x
The sine double-angle identity is sin⁡(2x)=2sin⁡xcos⁡x\sin(2x)=2\sin x\cos x. The last option is cos⁡(2x)\cos(2x).

Question 3

Given tan⁡θ=12\tan\theta=\frac{1}{2}, what is tan⁡(2θ)\tan(2\theta)?
  1. 43\frac{4}{3}
  2. 13\frac{1}{3}
  3. 23\frac{2}{3}
  4. 34\frac{3}{4}
Show answer and explanation
43\frac{4}{3}
Substitute into the tangent double-angle identity: tan⁡(2θ)=11−1/4=4/3\tan(2\theta)=\frac{1}{1-1/4}=4/3. The denominator is nonzero.

Key terms

Identity
An equality that is true for every value in its stated domain.
Double angle
An angle twice another angle, written 2θ2\theta.
Domain restriction
A condition describing values for which an expression is defined, such as requiring a denominator to be nonzero.

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Published by DoAssignment. This AI-assisted lesson follows International Baccalaureate (IB) IB AA SL: Mathematics: Analysis and Approaches SL, study topic SL 3.6. It is a study resource, not an official curriculum publication.

Before publication, the draft is checked for structure, mathematical or chemical notation, calculations, course boundaries, and readability, and then requires administrator approval. Errors can still occur, so corrections are welcomed.

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